00:05Numerical number 9 of unit 19 electromagnetic induction is a conductor of length 0.4 meter
00:14moves at a velocity of 5 meter per second perpendicular to a magnetic field of 0.3 tesla.
00:24Calculate the emotional EMF induced in the conductor. So, we will make all the data.
00:35Length of conductors. Suppose,
00:48this is galvanometer.
00:52And this is magnetic field means cross field.
01:06So, when conductor moves perpendicularly with velocity V through a uniform magnetic field
01:19B then EMF is induced at its ends and that induced EMF is known as Motional EMF.
01:31As length of conductor L is given which is 0.4 meter and velocity V is given as 5 meter
01:44per second.
01:45And conductor moves perpendicularly. So, angle is 90.
01:50So, as length of the conductor is given as 0.4 meter and velocity with which it moves is given
02:01as
02:025 meter per second and angle is 90 degree because it moves perpendicular to magnetic field.
02:12And magnetic field B is given which is 0.3 tesla.
02:23What we have to find? We have to find Motional EMF.
02:32So, for solution or calculation, we will use the formula is to calculate Motional EMF.
02:42If Xi is equal to VBL sin theta.
02:50So, Xi will be equal to the value of V is 5 multiplied with B magnetic field is given which
02:59is 0.3 tesla
03:01multiplied with length which is 0.4 meter multiplied with sin theta as the value of theta is 90 degree.
03:12As we know that sin 90 degree is equal to 1.
03:19So, Motional EMF will be obtained as 5 into 0.3 into 0.4 the value of sin 90 degree
03:31is 1.
03:32So, enter 1.
03:34So, Motional EMF means Xi will be equal to when we will multiply these values then we will get final
03:43the final answer is 0.6 volt. So, this is our final answer.
03:52Means EMF induced across the conductor is 0.6 volt.
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