00:06Numerical number 3 of unit 19 electromagnetic induction is two coils are placed close to
00:15each other.
00:17If a change in current of 3 ampere per second in the first coil induces an emf of 4 volt
00:24in the second coil, calculate the mutual inductance.
00:31This question is said that two coils are placed close to each other, so change in current
00:41in the first coil is obtained which is 3 ampere per second and second coil which is emf induced
00:48which is 4 volt.
00:53We have to calculate mutual inductance.
01:00So first of all we will make a data.
01:06is the change in current per unit time in primary coil is given which is 3 ampere per second
01:20and secondary coil which is emf induced which is 4 volt.
01:35So for solution or calculation we will use the formula is induced emf in secondary coil is
01:45equal to mutual inductance into rate of change of current in primary coil.
01:55is induced emf in secondary coil is given which is 4 volt so 4 is equal to mutual inductance
02:11so mutual inductance will be equal to 4 upon 3 when we will divide then we will get 1.33
02:25henry.
02:26So the final answer is 1.33 henry.
02:35So this is our required answer.
02:38So the final answer is 1.33 henry.
02:40So let's get back to the next one.
02:41You
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