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An AC generator produces an alternating current with a maximum voltage of 240 V.If the frequency of the generated AC is 50 Hz,calculate the peak value of the voltage.
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Numerical number seven of unit 19 electromagnetic induction
Electromagnetic Induction Numericals
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00:05Numerical number 7 of unit 19 electromagnetic induction is an AC generator produces an alternating
00:17current with a maximum voltage of 240 volt.
00:21If the frequency of the generated AC is 50 Hz, calculate the peak value of the voltage.
00:37As the value of root mean square voltage means Vrms is given which is 240 volt.
00:56We have to find peak voltage means V peak is equal to watt and frequency is also given
01:15which is 50 Hz.
01:20For solution or calculation, we will use the formula is, as we know that the root mean square
01:33voltage is equal to 0.707 times of peak voltage is the value of root mean square voltage is
01:50given which is 240 volt is equal to 0.707 into V peak.
02:04We have to find peak voltage.
02:07So, we have to find 0.707 multiplied by 0.707, then we will divide this side.
02:15So, peak voltage will be equal to 240 divided by 0.707.
02:24So, when we simplify it, then we will get the value of peak voltage is 339 volt.
02:37So, this is our final answer.
02:41So, że to which fällt, then you yourself will?
02:44That way, this is our final answer.
02:44So, we will continue our discussion with the most�s and political parties, and we will
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