A particle has displacement of 12m towards east and 5m towards north then 6m vertically upward. The sum of these displacements is

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Transcript

00:00Question is, a particle has displacement of 12 meter towards east and 5 meter towards

00:17north then 6 meter vertically upward.

00:22The sum of these displacements is a, 12 meter, b, 10.04 meter, c, 14.31 meter, d, none of these.

00:40To find the sum of these displacements, we will use the formula.

00:46The magnitude of displacement will be equal to under root x square plus y square plus

00:54z square.

00:58So the value of x is 12.

01:04So the square on 12 plus the value of y is 5.

01:12So the square on 5 plus the value of z is 6.

01:19So the square on 6.

01:22So the sum of displacements will be, as the square of 12 is 144, the square of 5 is 25,

01:30the square of 6 is 36.

01:34So 144 plus 25 plus 36, it will be under root 205.

01:50So the under root of 205 will be 14.31 meter.

02:00So the correct option will be c, 14.31 meter.

02:07So 14.31 meter.

02:08So 15.31 meter.

02:09So 15.31 meter.

02:10So 15.31 meter.

02:11So 15.31 meter.

02:12So 15.31 meter.

02:13So 15.31 meter.

02:14So 15.31 meter.

02:15So 15.31 meter.

02:16So 15.31 meter.

02:17So 15.31 meter.

02:18So 15.31 meter.

02:19So 15.31 meter.

02:20So 15.31 meter.

02:21So 15.31 meter.

02:22So 15.31 meter.

02:23So 15.31 meter.

02:24So 15.31 meter.

02:25So 15.31 meter.

02:26So 15.31 meter.

02:27So 15.31 meter.

02:28So 15.31 meter.

02:29So 15.31 meter.

02:30So 15.31 meter.

02:31So 15.31 meter.

02:32So 15.31 meter.

02:33So 15.31 meter.