00:05Numerical number 8 of unit 18 magnetic fields is what is phallux density at a distance of
00:150.1 meters in air from a long straight conductor carrying a current of 6.5 ampere. Calculate
00:26the force per unit length on a similar parallel conductor at a distance of 0.1 meter from
00:48the first and carrying a current of 3 ampere. Numerical number 8 of unit is that we calculate
01:00the flux density at a distance of 0.1 meter distance in air. Along straight conductor
01:10current carry 6.5 ampere and in the second condition we calculate the force per unit length
01:20at a distance of 0.1 meter from the first and second current I2 which is 3 ampere. So
01:31the force per unit we calculate the force per unit. First condition we calculate the force
01:45field intensity and magnetic field. We calculate the distance of 0.1 meter and the current
01:57I1 is given as 6.5 ampere and in the second condition we calculate the force per unit length.
02:15force per unit length means F upon L calculate the force per unit length means F upon L calculate
02:39the force per unit length. And for solution or calculation. First we find B. As B is calculated
02:54by Zing formula. B is equal to mu 0 I upon 2 pi R. As the value of mu 0
03:05means permeability
03:06of free space is constant. The free space is constant which is 4 pi multiplied with 10 raised
03:14power minus 7 tesla into meter per ampere. Now by putting the values. B will be equal to
03:26the value of mu 0 is 4 pi multiplied with 10 raised power minus 7 multiplied with I1
03:36i1 ka value
03:38put kar na hai
03:39so i1 ka jo value hai
03:436.5
03:44ampere so 6.5
03:47divided by
03:482 pi
03:51multiplied with r
03:52the value of r is 0.1
03:54meter
03:56so
03:57pi will be get cancelled with pi
03:59the table of 2 on 2 is 1 times
04:02and on 4 is 2 times
04:05jab ham in ko simplify
04:07karenge so then we will get
04:10final answer is
04:1213
04:13into 10
04:16raise power minus 6
04:17tesla
04:21so
04:22this is our
04:26first answer
04:32now
04:33secondly
04:34we will find
04:36force per unit length
04:38اب ہم force per unit length
04:40find کریں گے
04:40جب angle 90 ہو
04:43تو force کا فارمولا
04:45جو ہم use کریں گے
04:46which is
04:47f is equal to
04:48b
04:50i
04:51l
04:53means maximum force
04:56so ہمیں کیا find کرنا ہے
04:59ہمیں find کرنا ہے
05:00force per unit length
05:01so length
05:02so length
05:02so length
05:02we will multiply
05:02کریں گے
05:03so
05:04we will divide
05:06so force
05:07per unit length
05:09will be equal to
05:10b into i
05:12here we will use
05:14i to use
05:16so force
05:18per unit length
05:20will be equal to
05:21the value of
05:23b
05:23the value of b is obtained
05:26which is
05:2713
05:29multiplied with
05:3010
05:30raised power
05:31minus 6
05:35into i2
05:36the value of
05:37i2
05:37is
05:383
05:40so
05:40force per unit length
05:42will be obtained
05:43is
05:44جب ہم
05:4513
05:46کو 3
05:46کے ساتھ
05:47multiply کروائیں گے
05:48then we will get
05:4939
05:51into
05:5210
05:52raised power
05:53power minus 6
05:55newton
05:55per meter
05:57کیونکہ
05:57force کا unit
05:58newton ہے
05:59اور length
05:59کا meter
06:00so
06:01the value
06:02of
06:03force
06:04per unit
06:04length
06:05is
06:06obtained
06:07as
06:0739
06:08into
06:0910
06:09raised power
06:09minus 6
06:10newton
06:11per meter
06:12this is
06:13our second
06:13answer
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