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The torque of force F=(2i-3j+4k)N acting at the point r=(3i+2j+3k)m about the origin be
Physics with Akhtiar Ali Bullo
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2 months ago
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00:00
Question says, the torque of the force F is equal to 2i minus 3j plus 4k newton acting
00:15
at the point R is equal to 3i plus 2j plus 3k meters about the origin will be A 6i minus
00:29
6j plus 12k, B 17i minus 6j minus 13k, C minus 6i plus 6j minus 12k, D minus 17i plus 6j
00:46
plus 13k. As we have to find torque is, torque is the cross product of position vector and
01:03
force is torque is equal to R cross F. So, by using determinate form, first we will write
01:22
i, j and k, then we will put the values of R is the values of R are 3i plus 2j plus 3k.
01:39
So, the value of R with i is 3, with j is 2 and with k is 3. Now, we will put the values
01:53
of force, the value of force along i is 2, along j is minus 3 and along k is plus 4. So, first
02:11
of all, we will take i, when we will take i, then we will neglect the column of i. So, we
02:23
will multiply 2 with 4 and minus 3 with plus 3. So, 2 for the 8, this minus is our formula.
02:34
minus 3 into 3, it will be minus 9. So, break it over. Now, we will take j, so we will give
02:48
minus here. So, minus j into, when we will take j, then we will neglect the column of j, then
03:01
we will multiply 3 with 4 and 2 with 3. So, 3 for the 12 minus 2, 3 the 6. Now, we will take
03:16
k. When we will take k, then we will neglect this column, then we will multiply 3 with minus
03:24
3 and 2 with plus 2. So, 3 3 the minus 9. This minus is our formula. So, 2 to the 4. So, torque
03:41
will be obtained is i into 8, minus into minus, it will be plus 9, minus j, plus 12 minus 6,
03:57
it will be plus 6, plus k, minus 9, minus 4, it will be minus 13. So, torque will be obtained
04:15
is 8 plus 9, it will be plus 9, it will be plus 8 plus 9, it will be plus 9, it will be plus
04:31
k into 13, it will be 13 k. So, torque is obtained is 17 i minus 6 j minus 13 k. So, the correct
04:43
option will be b, 17 i minus 6 j minus 13 k.
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