A gas expands from 0.03 m³ to 0.06m³ against a constant pressure of 100kPa.Calculate the work done in both a reversible and an irreversible process and compare the results

Physics with Akhtiar Ali  Bullo

A gas expands from 0.03 m³ to 0.06m³ against a constant pressure of 100kPa.Calculate the work done in both a reversible and an irreversible process and compare the results Physics class 12 numericals  Inter class physics numerical solution  First law of thermodynamics numericals  Second year physics numerical solution  12 class physics numericals  New Sindh Text Physics numericals

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00:00Numerical number 6 of unit 16 first law of thermodynamics is a gas expands from 0.03

00:15meter cube to 0.06 meter cube against a constant pressure of 100 kilopascal. Calculate the work

00:24done in both a reversible and an irreversible process and compare the results. So,

00:32first of all, we will create data, initial volume V1 is obtained as 0.03 meter cube and final volume V2

00:55is obtained as 0.06 meter cube and pressure is obtained as here is 100 kilopascal.

01:10So, 10 kilopascal is equal to 1000 pascal. So, 10 cube is equal to 1000 pascal. So,

01:2810 into 10 raised power 3 pascal because 1 kilopascal is equal to 1000 pascal. So,

01:3810 cube is equal to 1000. So, when we multiply 10 with 1000, then pressure will be 10,000 pascal.

01:51So, we have to find work done in both conditions means for irreversible process and work done for

02:10reversible process. So, for solution or calculation,

02:17first, first we will find work done for irreversible process which is the work done for irreversible

02:27process is calculated by using formula W is equal to P delta V. So, we can also write this as

02:37delta V as delta V is equal to V2 minus V1 means final volume minus initial volume. So, work done

02:52for irreversible process will be as pressure is 10,000 pascal into V2. V2 is 0.06 cubic meter

03:08and V1 is minus V1 is 0.03 meter cube. So, work done for irreversible process will be

03:1910,000 into 0.06 minus 0.03 so it will be 0.03. So, work done for irreversible process will be

03:3110,000 into 0.03 it will be 300 Joules. So, this is answer for irreversible process.

03:47Now, we will calculate work done for reversible process.

03:59Work done in irreversible process will be equal to the twice of the work done

04:06by irreversible process. So, net work done by irreversible process will be equal to the

04:11work done by irreversible process. So, net work done by irreversible process

04:29So, net work done by irreversible process will be equal to 2 into 300. So, it will be 600 Joules.

04:46So, this is our second answer.

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