The freezing point of mercury is -39 degree centigrade. Convert it into degree fahrenheit and comfort level of temperature 20 degree Celsius into kelvin

Physics with Akhtiar Ali  Bullo

Molecular theory of gases numerical  12 class physics numerical  12 class physics problems

Transcript

00:00As-salamu alaykum dear students, today we will solve the numericals of chapter number 15.

00:15Numerical number 1 is the freezing point of mercury is minus 39 degree Celsius or

00:25centigrade, convert it into degree Fahrenheit and the comfort level temperature of 20 degree

00:35Celsius or centigrade into Kelvin. So, first of all we will make a data.

00:55The temperature in Celsius is given as minus 39 degree centigrade or Celsius and in first

01:15condition we will convert this temperature in Fahrenheit and in second condition temperature

01:27in centigrade is given as 20 degree centigrade and we will convert it into Kelvin.

01:42So, for calculation or solution, we will use the formula which is name of a scale minus

02:10freezing point of water divided by total number of deviants is equal to name of a scale

02:37minus freezing point of water divided by total number of deviants.

02:56So, first we will convert minus 39 degree centigrade into Fahrenheit.

03:03So, first we will convert minus 39 degree centigrade into Fahrenheit.

03:07And then if we convert added of the PAUL, if we put up the trze Bemlah server then we here

03:14first form spaghetti or cog nosaltres then we will convert it into moment.

03:15So, when we compared up the masa in Fahrenheit OR, we would be converted into位置

03:18So, if we convert it in Fahrenheit then we would convert it into our name of a scale value of

03:21Fahrenheit, then we will cast at name of a scale.

03:22Now we we will check a source on Fahrenheit裡…

03:23This notice can be Paige zde, we will put in time as minus freezing point of water on Fahrenheit is

03:25temperature rate by一點 Mines.

03:26The minus freezing point of water on Fahrenheit is 32 degree Fahrenheit

03:29and total number of deviance on Fahrenheit is 180 is equal to

03:36and which temperature we have obtained is Celsius

03:40so temperature in Celsius minus freezing point of water on Celsius is 0 degree Celsius

03:49total number of deviance is 100

03:52so temperature in Fahrenheit minus 32 is equal to

03:59temperature in Celsius divided by 100

04:03here we have 180 divided by 180 so we will multiply the other side into 180

04:09so the table of 20 on 100 is 5 times and on 180 is 9 times

04:15so temperature in Fahrenheit will be equal to

04:19temperature in Celsius divided by 5 into 9

04:25here we have 32 minus so we will multiply the other side by the other side

04:29plus so temperature in Fahrenheit will be equal to

04:36here we have temperature in Celsius obtained

04:39which is minus 39 degrees centigrade

04:42so minus 39 divided by 5 into 9 plus 32

04:50so jab हम इनको simplify करेंगे

04:54तो हमें answer obtained होगा

04:57minus 70.2 plus 32 will remain same

05:04so minus 70.2 plus 32 it will be

05:10minus 38.2 degree Fahrenheit

05:16so हमें first answer obtained हो गया

05:21अब हम दूसरी कंडिशन में Kelvin में convert करेंगे

05:27so जिस temperature में convert करेंगे वो हम पहले लिखेंगे

05:32so temperature in Kelvin minus freezing point of water on Kelvin is 273

05:37divided by total number of deviance which are 100 is equal to

05:42हमें कौन सा temperature obtained है Celsius

05:47और centigrade

05:48so यहां पर लिखेंगे temperature in Celsius minus freezing point of Celsius is 0

05:54divided by total number of deviance which are 100

05:58यहां पर 100 divide कर रहा है तो दूसरी side multiply करेगा

06:03so 100 will be get cancelled with 100

06:06so temperature in Kelvin minus 273 will be equal to

06:11temperature in Celsius minus 0

06:14so it will be temperature in Celsius

06:16so हमें temperature in Kelvin मालूम करना है

06:20so temperature in Kelvin will be equal to

06:23temperature in Celsius plus 273

06:27क्योंकि यहां पर 273 minus कर रहा है तो बराबर की दूसरी side plus करेगा

06:32अब हम Celsius का value put करेंगे

06:36जो हमें 20 degree Celsius obtained है

06:39so 20 plus 273

06:44so temperature in Kelvin will be obtained is

06:4720 plus 273

06:49so it will be 293 Kelvin

06:53so this is our second answer

06:57so

06:59so

07:02so

07:04so

07:06so

07:08so

07:09so

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