A wire 1.80m long carries a current of 13.0A and makes an angle of 35.0⁰ with a uniform magnetic field of magnitude B=1.50T.Calculate the magnetic force on the wire 12 class physics numericals Physics class 12 numericals Inter class physics numericals New sindh text physics numericals New sindh board physics numericals
00:00Numerical number 3 of unit 18 magnetic fields is a wire 1.8 meter long carries a current
00:15of 13.0 amperes and makes an angle of 35.0 degree with a uniform magnetic field of magnitude
00:26B is equal to 1.50 tesla. Calculate the magnetic force on the wire. So, sab se pehlein hum data
00:37banayenge. As length of conductor is given which is 1.80 meter and current is also given
00:56which is 13.0 amperes and angle theta is also given which is 35 degree and the value of magnetic
01:16field intensity B is also given which is 1.50 tesla. So, we have to find magnetic force means
01:30Fm. For solution or calculation, we will use the formula to calculate magnetic force is,
01:51magnetic force is equal to BIL sin theta. So, magnetic force will be obtained as the value
02:07of B is 1.50 multiplied with electric current. The value of electric current is 13.0 amperes,
02:17multiplied with the length. The value of length is 1.80 meter multiplied with sin theta. The value
02:30of theta is 35 degree. So, magnetic force will be obtained as when we will multiply these values,
02:41then we will get final answer is 20.1 Newton. So, the value of sine 35 degree is 0.573. So, magnetic force will be obtained as when we will multiply these values then we will get final answer is 20.1 Newton. So,
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