During an isochoric process,the internal energy of a gas increases by 300J.If no work is done,determine the heat added to the system

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During an isochoric process,the internal energy of a gas increases by 300J.If no work is done,determine the heat added to the system. Physics class 12 numericals  First law of thermodynamics numericals  12 class physics numerical solution  12 class physics problems  New Sindh Text Physics numericals

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00:00Numerical number 4 of unit number 16, first law of thermodynamics is, during an isophoric

00:13process, the internal energy of a gas increases by 300 joules.

00:18If no work is done, determine the heat added to the system.

00:24So first of all, we make data, we have obtained change in internal energy, which is, delta u

00:39is equal to 300 joules and we have to find heat added.

00:51So for calculation, the process is isochoric.

01:02So according to first law of thermodynamics, delta q is equal to delta u plus delta w is,

01:13in isochoric process, work done is 0.

01:25So, this equation will become is, delta q will be equal to delta u plus 0.

01:36So, delta q will be equal to delta u.

01:40means, in isochoric process, the heat supplied is used to increase the internal energy.

01:51delta q means, in isochoric process, total heat energy supplied is used to increase internal

01:58energy.

02:12in isochoric process, total ela, comasic process, total hour of thermodynamics, one of the

02:26internal energy of the finan pulmonary energy força, total amount of energy to powiedz

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