00:00Numerical number 2 of unit 16, first law of thermodynamics is, a piston compresses a gaze
00:15adiabatically if the initial volume is 0.02 meter cube and the final volume is 0.01 meter
00:25cube and the initial pressure is 200 kilo Pascal. Determine the final pressure. Assume the gaze
00:35behaves ideally. So, first of all, we will make a data. Shab se peli hum data banayenge.
00:46So, here the word adiabatically is actually wrong because here the word is basically
01:01basically hoona chahiye. Means isothermal process hoona chahiye. So, V1 is obtained is 0.02
01:13meter cube. V2 is obtained is 0.01 meter cube and pressure P1 is obtained is 200 kilo Pascal which
01:33is also equal to 200 into 10s power 3 Pascal because 1 kilo Pascal is equal to 1000 Pascal.
01:46So, P1 will be equal to 200 into 10s power 3. So, P1 will be equal to 200 into 10s power 3
01:54ko am iisay bhi likh sakte hain. Pascal means 2 leg Pascal. We have to find final pressure
02:07P2. So, P2. So, P2 will be equal to P1 V1 upon 0.02 meter cube. So, P2 will be equal to P1 V1 upon
02:37V2. Means after rearranging this equation we will get this. Now, by putting the values,
02:46the value of P1 is 2 lake Pascal into V1. The value of V1 is 0.02 meter cube divided by V2
03:07the value of V2 is 0.01 meter cube. So, P2 will be equal to is 2 lake into 0.02 divided by 0.01. So,
03:27it will be 2. So, 2 lake into 2 it will be 4 lakes Pascal or we can also write this as P2 will be equal to 400 kilo Pascal.
03:52Because 1 kilo Pascal is equal to 1000 Pascal. So, this is our final answer.
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