A sample of a gas contains 3×10^24 atoms. Calculate the volume of the gas at a temperature of 300k and a pressure of 120 kPa

Molecular Theory of Gases Numericals  Physics class 12 numericals  Physics class 12 problems  12 class physics numericals

Transcript

00:00numerical number 7 of unit 15 a sample of gaze contains 3.0 into 10 raised powers 24 atoms

00:15calculate the volume of the gaze at a temperature of 300 Kelvin and a pressure of 120 kilo Pascal

00:24so सबसे पहले हम data बनाएंगे यहां पर हमें number of atoms obtained

00:37है which is 3 into 10 raised power 24 atoms or temperature भी हमें obtained है

00:54which is 300 Kelvin हमें volume fine करना है so V will be equal to watts और

01:08pressures भी हमें obtained है so pressure is also given which is 120 kilo Pascal

01:17120 kilo Pascal को हम ऐसे भी लिख सकते हैं कि 120 into 10 raised power 3

01:26Pascal because 1 kilo Pascal is equal to 10 cube Pascal

01:38first condition में हमें number of moles को fine करना है और second condition में

01:48volume fine करना है और एवागे द्रोज numbers is also constant which is

01:596.02 into 10 raised power 23 molecules per mole

02:12और universal gas constant means capital R वो भी constant है और उसका value है 8.314

02:231 force Joule per mole per Kelvin सबसे पे ले हम number of moles fine करेंगे so for calculation

02:36number of moles in this condition number of moles is find by using formula number of atoms divided by

02:48evagadro number so number of atoms is given is 3 into 10 is power 24 divided by

02:58evagadro number which is 6.02 into 10 is power 23 molecules per mole so after

03:08simplifying this we will get number of moles is 4.983 moles so this is our first answer now

03:25finally we will find volume by using general guess equation which is PV is equal to nRT so V will be

03:37equal to nRT upon T number of moles is 4.983 into capital R the value of capital R is 8.314 multiplied with

03:59temperatures temperature temperature is obtained as 300 Kelvin divided by pressure pressure is also

04:11obtained which is 120 into 10 power 3 Pascal so when we will multiply these all values then we will get

04:21we will be equal to 1242 8.568 divided by 120 into 10 cubes so we can also write this as

04:410.104 meter cube so after simplification we will get the value of volume is 0.10357

04:590.104 meter cube so this is our final answer