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A sample of a gas contains 3×10^24 atoms. Calculate the volume of the gas at a temperature of 300k and a pressure of 120 kPa
Physics with Akhtiar Ali Bullo
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2 months ago
Molecular Theory of Gases Numericals
Physics class 12 numericals
Physics class 12 problems
12 class physics numericals
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00:00
numerical number 7 of unit 15 a sample of gaze contains 3.0 into 10 raised powers 24 atoms
00:15
calculate the volume of the gaze at a temperature of 300 Kelvin and a pressure of 120 kilo Pascal
00:24
so सबसे पहले हम data बनाएंगे यहां पर हमें number of atoms obtained
00:37
है which is 3 into 10 raised power 24 atoms or temperature भी हमें obtained है
00:54
which is 300 Kelvin हमें volume fine करना है so V will be equal to watts और
01:08
pressures भी हमें obtained है so pressure is also given which is 120 kilo Pascal
01:17
120 kilo Pascal को हम ऐसे भी लिख सकते हैं कि 120 into 10 raised power 3
01:26
Pascal because 1 kilo Pascal is equal to 10 cube Pascal
01:38
first condition में हमें number of moles को fine करना है और second condition में
01:48
volume fine करना है और एवागे द्रोज numbers is also constant which is
01:59
6.02 into 10 raised power 23 molecules per mole
02:12
और universal gas constant means capital R वो भी constant है और उसका value है 8.314
02:23
1 force Joule per mole per Kelvin सबसे पे ले हम number of moles fine करेंगे so for calculation
02:36
number of moles in this condition number of moles is find by using formula number of atoms divided by
02:48
evagadro number so number of atoms is given is 3 into 10 is power 24 divided by
02:58
evagadro number which is 6.02 into 10 is power 23 molecules per mole so after
03:08
simplifying this we will get number of moles is 4.983 moles so this is our first answer now
03:25
finally we will find volume by using general guess equation which is PV is equal to nRT so V will be
03:37
equal to nRT upon T number of moles is 4.983 into capital R the value of capital R is 8.314 multiplied with
03:59
temperatures temperature temperature is obtained as 300 Kelvin divided by pressure pressure is also
04:11
obtained which is 120 into 10 power 3 Pascal so when we will multiply these all values then we will get
04:21
we will be equal to 1242 8.568 divided by 120 into 10 cubes so we can also write this as
04:41
0.104 meter cube so after simplification we will get the value of volume is 0.10357
04:59
0.104 meter cube so this is our final answer
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