Skip to player
Skip to main content
Search
Connect
Watch fullscreen
Like
Bookmark
Share
More
Add to Playlist
Report
Calculate the root mean square speed of hydrogen molecule at 500 k ( mass of proton=1.67×10^-27 kg and K=1.38×10-23 j/molecule K)
Physics with Akhtiar Ali Bullo
Follow
2 months ago
Molecular Theory of Gases Numericals
12 class physics numericals
12 class physics problems
Category
📚
Learning
Transcript
Display full video transcript
00:00
Numerical number 9 of unit 15 molecular theory of gases is, calculate the root mean square
00:14
speed of hydrogen molecule at 500 Kelvin of proton 1.67 into 10 raised power minus 27 kilogram
00:29
and Boltzmann constant K is given as 1.38 into 10 raised power minus 23 joule per Kelvin.
00:43
So, first of all, we have to find the root mean square speed of hydrogen molecule which is equal to Watt.
01:02
Temperature हमें obtained है, that is 500 Kelvin और
01:10
proton का जो मास है, वो 1.67 into 10 raised power minus 27 kg अप्तेंड है.
01:20
So, mass of hydrogen molecule will be equal to 2 into 1.67 into 10 raised power minus 27 kg.
01:35
So, mass of hydrogen molecule will be 3.34 into 10 raised power minus 27 kg.
01:49
जब हम 2 को 1.67 के साथ multiply करेंगे, तो हमें answer मिलेगा 3.34.
01:57
So, into 10 raised power minus 27 हम same लिखेंगे.
02:02
और बोल्स में लिखेंगे लिखेंगे लिखेंगे का वेल्यू हमें उप्तेंड है, यह वेल्यू हमें लिखेंगे.
02:09
we have obtained that is 1.38 into 10 raised power minus 23 Joule per Kelvin and this is
02:23
also constant. So, for calculation we will use formula root mean square speed is equal
02:37
to under root 3 KT upon M. So, by putting the given values 3 into the value of Boltzmann constant
02:53
is 1.38 into 10 raised power minus 23 into temperature which is obtained is 500 Kelvin divided by
03:07
mass of hydrogen molecule which is 3.34 into 10 raised power minus 27 kg. So, root mean square
03:21
speed will be obtained as under root.
03:26
जब हम 3 1.38 और 500 को multiply करवाएंगे आपस में तो हमें answer मिलेगा
03:36
under root 2,070 into 10 raised power minus 23 divided by 3.34 into 10 raised power minus
03:52
27. So, जब हम 2,070 में से 3.34 divided करवाएंगे तो हमें answer मिलेगा
04:02
under root 2,070 into 10 raised power minus 23 यहाँ पर 27 minus का है तो उपर जाकर यह पिलस का हो जाएगा. So,
04:29
plus 27. So, root mean square speed will be equal to under root 619.76 into 10 raised power minus 23 plus 27. So,
04:51
it will be 4. So, under root of 619.76 will be 24.8949 into 10 raised power, the under root
05:09
of 10 raised power 4 is 10 raised power 2 meter per second. So, root mean square speed will
05:21
be obtained as 10 raised power 2 को हम ऐसे बलिख सकते हैं कि यह value 100 के
05:29
equal होता है. So, जब हम 100 इस value के साथ multiply करवाएंगे तो हमें answer मिलेगा
05:36
2489.49.49 meter per second. So, this is our final answer.
Be the first to comment
Add your comment
Recommended
11:33
|
Up next
Calculate the root mean square speed of hydrogen molecules at 0 degree centigrade and 1 atm pressure. Assuming hydrogen to be an ideal gas. The density of hydrogen is 8.99×10^-2 kg/m3
Physics with Akhtiar Ali Bullo
2 months ago
6:57
The molar mass of nitrogen gas N2 is 28 g/mol. For 100g of nitrogen, calculate the number of moles, the volume occupied at room temperature 20 degree celsius and pressure of 1.01×10^5 pa
Physics with Akhtiar Ali Bullo
2 months ago
5:18
A sample of a gas contains 3×10^24 atoms. Calculate the volume of the gas at a temperature of 300k and a pressure of 120 kPa
Physics with Akhtiar Ali Bullo
2 months ago
3:42
Calculate the volume occupied by a gram mole of a gas at 0 zero degree centigrade and a pressure of 1.0 atmosphere
Physics with Akhtiar Ali Bullo
2 months ago
4:55
A balloon contains 0.04 m3 of air at a pressure of 120kPa. Calculate the pressure required to reduce its volume to 0.025 m3 at constant temperature.
Physics with Akhtiar Ali Bullo
2 months ago
10:27
Determine the average value of the kinetic energy of the particles of an ideal gas at 10 degree centigrade and 40 degree centigrade, what is the kinetic energy per mole of an ideal gas at these temperatures
Physics with Akhtiar Ali Bullo
2 months ago
6:31
Determine the gravitational attraction between the proton and the electron in a hydrogen atom,assuming that the electron describes a circular orbit with a radius of 0.53×10⁻¹⁰ m.mass of electron=9.1×10⁻³¹ kg,mass of proton=1.67×10⁻²⁷ kg
Physics with Akhtiar Ali Bullo
7 months ago
5:15
The boiling point of liquid nitrogen is -321 degree fahrenheit. Change it into equivalent kelvin temperature.
Physics with Akhtiar Ali Bullo
2 months ago
2:38
A gas undergoes isothermal expansion at a constant temperature of 300K.If the gas absorbs 500J of heat during the process,calculate the work done by the gas
Physics with Akhtiar Ali Bullo
7 weeks ago
4:09
A piston compresses a gas adiabatically. If the initial volume is 0.02 m³ and final volume is 0.01 m³ and the initial pressure is 200 kPa, determine the final pressure. Assume the gas behaves ideally
Physics with Akhtiar Ali Bullo
5 weeks ago
3:39
How much heat is required to raise the temperature of 1kg of lead from 25⁰C to 100⁰C.Specific heat capacity of lead=0.128 J/g⁰C Physics class 12 numericals solution Inter class physics numerical solution First law of thermodynamics numericals
Physics with Akhtiar Ali Bullo
5 weeks ago
2:15
During an isochoric process,the internal energy of a gas increases by 300J.If no work is done,determine the heat added to the system
Physics with Akhtiar Ali Bullo
5 weeks ago
7:00
The freezing point of mercury is -39 degree centigrade. Convert it into degree fahrenheit and comfort level of temperature 20 degree Celsius into kelvin
Physics with Akhtiar Ali Bullo
2 months ago
4:53
A gas expands from 0.03 m³ to 0.06m³ against a constant pressure of 100kPa.Calculate the work done in both a reversible and an irreversible process and compare the results
Physics with Akhtiar Ali Bullo
5 weeks ago
4:42
An air storage tank whose volume is 112 litres contain 3kg of air at a pressure of 18 atmosphere. How much air would have to be forced into the tank to increase the pressure to 21 atmospheres, assuming no change in temperature
Physics with Akhtiar Ali Bullo
2 months ago
4:57
The torque of force F=(2i-3j+4k)N acting at the point r=(3i+2j+3k)m about the origin be
Physics with Akhtiar Ali Bullo
5 months ago
6:24
The mass of the planet Jupiter is 1.9×10 power 27 kg and that of the sun is 2×10 power 30 kg.If the average distance between them is 7.8×10 power 11m.Find the gravitational force of the sun on Jupiter
Physics with Akhtiar Ali Bullo
7 months ago
3:20
Prove that one kilo watt hour is equal to 3.6×10 power 6 J
Physics with Akhtiar Ali Bullo
1 year ago
2:08
A particle has displacement of 12m towards east and 5m towards north then 6m vertically upward. The sum of these displacements is
Physics with Akhtiar Ali Bullo
5 months ago
6:44
A 10kg mass is at a distance of 1m from a 100kg mass.Find the gravitational force of attraction when a) 10kg mass exerts force on the 100kg mass b) 100 kg mass exerts force on the 10kg mass
Physics with Akhtiar Ali Bullo
7 months ago
4:22
A system undergoes an isobaric process where the pressure is kept constant at 150 kPa. If the volume increases from 0.05 m³ to 0.08 m³. Calculate the heat added to the system
Physics with Akhtiar Ali Bullo
5 weeks ago
3:19
A wire 1.80m long carries a current of 13.0A and makes an angle of 35.0⁰ with a uniform magnetic field of magnitude B=1.50T.Calculate the magnetic force on the wire
Physics with Akhtiar Ali Bullo
2 weeks ago
4:31
One kilogram of ice at 0 degree centigrade is melted and converted to water at 0 degree celsius.Compute its change in entropy.
Physics with Akhtiar Ali Bullo
4 weeks ago
2:04
Prove that one joule is equal to 10 power 7 erg_-_Prove that 1 J=10 power 7 erg
Physics with Akhtiar Ali Bullo
1 year ago
7:47
A 50 g piece of copper at 100 degrees centigrade is placed in 200 g of water at 20 degree celsius.If the final temperature of the system is 30 degree centigrade.Calculate the specific heat capacity of copper.(Specific heat capacity of water=4.18 J/g⁰C) Ph
Physics with Akhtiar Ali Bullo
5 weeks ago
Be the first to comment