00:00Numerical number 10 of unit 15 molecular theory of gases is a determine the average value
00:16of the kinetic energy of the particles of an ideal gaze at 10 degree centigrade and 40 degree
00:28centigrade. B, what is the kinetic energy per mole of an ideal gaze at these temperatures?
00:38Sb se phele hem data banayenge, so ke1 hem find karnehe jab temperature t1 hem aptend ho 10 degree centigrade
00:56isko hem convert karenghe kelvin me, so t1 will be equal to 10, jab hem isko kelvin
01:05me convert karenghe, so isko 273 add karenghe, so t1 will be equal to 283 kelvin
01:14or ke2 be find karenghe, jab hem temperature t2 obtend ho 40 degree centigrade, so 40 degree
01:32centigrade ko bhi hem kelvin me convert karenghe, so t2 will be equal to 40 plus 273, so it will
01:42be 313 kelvin or second condition may b may kinetic energy per mole b calculate karenghe, for each condition
01:51means ke1 per mole and ke2 per mole calculate karenghe, as the value of bolzman constant k is given, means it is constant which is 1.3
01:53per mole b calculate karenghe, as the value of bolzman constant k is given, means it is constant which is 1.3
01:54per mole b per mole b calculate karenghe, as the value of bolzman constant k is given, means it is constant which is 1.38
02:01into 10 raised power minus 23 joule per kelvin, so t2 per mole b for each condition, so t2 per mole b
02:16by calculate karenghe, as the value of bolzman constant k is given, means it is constant which is 1.38 into 10 raised power minus 23 joules per kelvin, so t4 per mole b
02:263 Joule per Kelvin. So, for calculation,
02:37sab se phele hum Ke1 find karenge. So, Ke1 will be equal to 3 upon 2 KT.
02:48So, 3 upon 2 K means Boltzmann constant. The value of Boltzmann constant is
02:561.38 into 10 to the power minus 23 into T1. T1 ╪м┘И █Б┘Е█М┌║ obtained рд╣реИ 283 Kelvin.
03:09So, into 283 Kelvin. So, Ke1 will be obtained рд╣реИ.
06:54So, 3 upon 2 into K means Boltzmann constant which is 1.38 into 10 raise power minus 23 into T2.
07:09T2 is 313.
07:13After simplification, Ke2 will be obtained as 647.9 into 10 raise power minus 23 Joule.
07:32So, when we will shift decimal when we will shift decimal up to 2 digits from right to left, then we will add 2 with power.
07:45So, Ke2 will be 6.479 into 10 raise power minus 23 plus 2.
07:56So, it will be minus 21 Joule.
08:00So, рдпрд╣рд╛рдБ рдкрд░ рд╣рдореЗрдВ Ke2 рдХрд╛ value рдЬреЛ obtained рд╣реБрдЖ.
08:03That is 6.479 into 10 raise power minus 21 Joule.
08:08So, Ke2 per mole calculate рдХрд░реЗрдВрдЧреЗ, which is Ke2 into Avogadro number.
08:22So, Ke2 per mole will be equal to the value of Ke2 is 6.479 into 10 raise power minus 21 into Avogadro number is the value of Avogadro number is constant which is 6.02 into 10 raise power 23 molecules per mole.
08:49So, Ke2 per mole will be equal to the value of Ke2 per mole will be equal to рдЬрдм рд╣рдо рдЗрди рджреЛрдиреЛрдВ рдХреЛ multiply рдХрд░рд╡рд╛рдПрдВрдЧреЗ,
09:01So, then we will get 39.00358 into 10 raise power.
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