A carnot engine operates between the temperatures 850K and 300K.the engine performs 1200J of work in each cycle, which takes 0.25 sec (a) What is the efficiency of this engine ? (b) What is the average power of this engine ? (c) How much energy is extracted as heat from the high temperature reservoir ? (d) How much energy is delivered as heat to the low temperature reservoir ?
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03:14is efficiency is equal to 1 minus T2 upon T1 multiplied with 100 percent
03:25เคเฅเคฏเฅเคเคเคฟ เคฏเคนเคพเค เคชเคฐ temperatures เคเคพ value obtained เคนเฅ
03:31เคคเฅ เคเคธ conditions เคฎเฅเค เคนเคฎ efficiency เคเคพ value calculate เคเคฐเฅเคเคเฅ
03:35so eta will be equal to 1 minus T2 as T2 is given as 300 Kelvin divided by T1 which is
03:49850 Kelvin multiplied with 100 percent so efficiency will be obtained as 1 minus
04:00when we will subtract 0.3529 from 1 then we will subtract 0.3529 from 1 then we will
04:30get 0.6408 and 100 percent will remain same so efficiency will be obtained as when we
04:43will multiply 100 with this value then we will get final answer is 64.08 percent so efficiency
04:56is obtained is 64.08 percent so this is our first answer
05:06now solution for B
05:10B เคฎเฅเค เคนเคฎเฅเค power calculate เคเคฐเคจเคพ เคนเฅ is power is equal to work upon time means work done
05:22per unit time is known as power so power will be equal to work done is obtained as 1200 Joules divided
05:36by time which is also given 0.25 seconds when we will simplify these values then we will get 4800 Watt
05:47so we can also write 4800 Watt is power will be equal to 4.8 kW so this is our second answer now solution for C means Q1 is equal to Watt as we know that
06:16that efficiency is also equal to work done upon heat supplied multiplied with 100% this equation will be Q1 is equal to work done upon efficiency into 100%
06:23so Q1 is equal to work done upon efficiency into 100%
06:30so Q1 is equal to work done upon efficiency into 100%
06:38is equal to work done upon efficiency and Q2 is equal to V so Q1 will be equal to Q1
06:46so Q1 will be equal to Q1 is equal to Q1 will equal to Q1 is equal to Q1 is the value of
06:47work done done on working done is obtained as 1200 Joules divided by efficiency which are 64.08%
07:03percent into hundred percent will remain same is percentage will be get
07:12cancelled with percentage Q1 will be obtained as 1200 into 100 it will be
07:23divided by 64.08 so after simplification we will get the value of Q1 is 1872.6 J so
07:43this is the answer for Q1 now finally solution for D means Q2 as we know that
08:01work done is equal to Q1 minus Q2 so after rearranging we will get this
08:09equation is Q2 is equal to Q1 minus work done the value of Q2 will be obtained as
08:22is the value of Q1 is obtained which is 1872.6 minus work done the value of work
08:33done is given which is 1200 joules so Q2 will be obtained as after simplifying this
08:44means by subtracting 1200 from 1872.6 we will get 672.6 joules
09:00so this is our final answer for Q2 means this is our answer number 4
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