00:00Question is, the battery of a pocket calculator supplies 0.35 ampere at a potential difference
00:15of 6 volt.
00:18What is the power rating of the calculator?
00:22First of all, we will form a data as electric current is obtained as 0.35 ampere and electric
00:38potential is obtained as 6 volt, we have to find the value of power.
00:46So for solution, in this condition, we will calculate the power by using formula P is
00:55equal to I into V. So power will be obtained as the value of I is 0.35 into the value of
01:06electric potential 6 volt.
01:10So 0.35 into 6, the power will be obtained as 2.1 watt.
01:21So this is our required answer.
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