00:00question is a current of 6 ampere is drawn from a 120 volt line watt power is being developed
00:15how much energy in joule and in kilowatt hour is expended if the current is drawn steadily for
00:25one week first of all we will make a data is current is obtained is six amperes and electric potential
00:49is obtained as 120 volt so in first condition we have to find power which is developed and in
01:03second condition we have to find energy in joule and in third condition we will find energy in
01:19kilowatt hour its time is obtained is one week so first of all we will convert week into seconds
01:41so time will be t is equal to one enter is there are seven days in a week enter and there are 24
01:54hours in a day and 60 minutes in an hour and 60 seconds in a minute so after multiplying all these
02:07values we will get the time is 6.05 into 10 raised power 5 second so for solution
02:24first of all we will find the developed power is in this condition the power is calculated by using
02:42formula p is equal to i into v so power will be obtained as its current is obtained as 6 ampere into
02:53120 it will be 720 watt so power is obtained as 720 watt this is our first answer now we will find energy in
03:23energy in joule is power is equal to energy upon time or work upon time so energy will be equal to power into time because here t is dividing on the other side of
03:52feature now it will be equal it will multiply it will multiply it will multiply it will be power so by putting
03:56to be the given value values energy will be obtained
04:05aspireanda power is obtained as 720 watt so 720
04:11watt so 720 into time which is obtained as 6.05 into 10 raised power 5 second so energy
04:33will be obtained is when we will multiply 720 with 6.05 then we will get 4356 into 10 raised
04:52power 5 Joule here is decimal then we will shift decimal from right to left up to 3 digits
05:10then we will add 3 with the power so energy will be obtained as 4.356 into 10 raised power
05:228 Joule so this is our second answer finally we will find energy in kilowatt hours is 1
05:42kilowatt hour is equal to 3.6 into 10 raised power 6 Joule so 1 Joule will be equal to 1 upon
06:003.6 into 10 raised power 6 kilowatt hour so by putting this value in place of Joule so energy
06:14in kilowatt hour will be obtained as 4.356 into 10 raised power 8 into Joule the value of
06:26Joule is 1 upon 3.6 into 10 raised power 6 kilowatt hour so after simplifying this energy in kilowatt
06:42kilowatt hour will be obtained as 4.356 divided by 3.6 it will be obtained as 1.21 into S in
06:58dv and when the bases are same then we will subtract the power of denominator from the power of numerator
07:05so it is 10 raised power 8 so it is 10 raised power 8 and it this is 10 raised power 6 so 10 raised power 8 minus 6
07:17kilowatt hour so energy in kilowatt hour will be obtained as 1.21 into 10 raised power plus 8 minus 6 it will be plus 2 kilowatt hour
07:33so energy in kilowatt hour will be equal to 10 raised power 10 raised power power power 10 raised power 2 is equal to 100
07:45then we will multiply 100 with 1.21 then we will get 121 kilowatt hour so this is our third answer
07:55So, this is our third answer.
Comments