A person goes 10km north and 20km east. what will be the displacement from initial point?

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00:00Question is, a person goes 10 km north and 20 km east, what will be the displacement

00:15from initial point, a 22.36 km, b 2 km, c 5 km, d 20 km. To find the net displacement, we will

00:40take the help of direction indicator, suppose this is north, this is south, this is east

00:49and this is west. So, a person goes 10 km towards north, 10 km towards north from point A to B

01:08and then he turns from the point B and covers 20 km towards east and moves 20 km towards

01:21east from point B to C. So, we have to find its net displacement. So, to calculate net displacement,

01:31we will use the Pythagoras theorem is net displacement SC is equal to under root AB square plus BC square.

01:57So, net displacement will be the value of AB is 10. So, the square of 10 plus the value of BC is 20. So,

02:12the square on 20. So, the net displacement will be obtained as the square of 10 is 100 plus the square

02:20of 20 is 400. So, 100 plus 400, it will be under root 500. So, the under root of 500 is obtained as 22.36 km. So, the correct option will be

02:48Ok, this point will be a 22.36 km. So, here, the power of 27.36 .