A body is at rest under the action of three forces,two of which are F1=4i, F2=6j the third force is

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00:00Question is, a body is at rest under the action of three forces, two of which are F1 is equal

00:15to 4i, comma F2 is equal to 6j, the third force is a, 4i plus 6j, b, 4i minus 6j, c minus 4i plus 6j, d minus 4i minus 6j,

00:36is, when the three forces are acting on a body and it is at rest, it means the sum of

00:47three forces F1 plus F2 plus F3 is equal to 0, that's why the body is at rest,

01:03is F1 is obtained as 4i plus F2 is obtained as 6j, we have to find F3 is equal to 0, so when we will

01:25take plus 4i plus 6j on the other side of equal, then it will be, F3 will be equal to minus 4i minus 6j,

01:38so F3 is obtained as minus 4i minus 6j, so the correct option will be, d minus 4i minus 6j,

01:53if you can see F3, it will be equal to 1, and if you can see F3 is equal to 0, so that means