A battery of 24V is connected to a 10Ω load and a current of 2.2A flows.Find the internal resistance of the battery and its terminal voltage

Physics with Akhtiar Ali  Bullo

A battery of 24V is connected to a 10Ω load and a current of 2.2A flows.Find the internal resistance of the battery and its terminal voltage  Physics class 12 problem solution  Inter class physics problem solution

Transcript

00:00question is a battery of 24 volt is connected to a 10 ohm load and a current of 2.2 ampere

00:15flows find the internal resistance of the battery and its terminal voltage first of all

00:26we will make a data is emf of battery is obtained is 24 volt

00:40resistance is obtained is 10 ohm which is also called load

00:47current is obtained as 2.2 ampere and we have to find the internal resistance of the battery

01:00so for solution

01:10is when battery is connected to a circuit then emf will be greater than terminal potential

01:23so v will be equal to e minus vt is v is equal to i into r

01:38so i r will be equal to e minus vt so we have to find r means internal resistance is r will be equal

01:58to e minus terminal potential divided by electric current as emf is obtained which is 24 volt

02:09current is also obtained terminal potential is not obtained so first of all we will find terminal

02:18potential

02:22first we find terminal potential which is equal to i into capital r so terminal potential will be obtained

02:31is its current is 2.2 ampere into r means load which is 10 ohm so terminal potential will be obtained as

02:4210 into 2.2 it will be 22 volt

02:49as terminal potential is obtained as 22 volt finally

02:57we will find internal resistance which is r is equal to emf minus terminal potential divided by electric

03:07current current now putting the given values as emf of battery is 24 volt minus terminal potential which is 22

03:17divided by electric current which is 2.2 ampere so internal resistance will be obtained as 24 minus 22

03:28it will be 2 divided by 2.2 so 2 divided by 2.2

03:34it will be obtained as 0.91 ohm so internal resistance is obtained as 0.91 ohm so this is our final answer

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