00:00Locked rotor current, LRA, the American standard calls this, so it would be
00:06The current at LRA is equivalent to the starting current of the IESON standard, therefore this
00:12I have to obtain it through calculation, how is it obtained?
00:17So here I'm going to let myself be guided by the A cables about HP, so I'm going to go here to talk
00:32So, for example, he told me that my engine was a J-type engine, so this says that it's from
00:468 to 9 the value for letter J and the units KVA over HP, so which of the two do I choose
00:56I would have the worst-case scenario, the worst-case scenario, the worst-case scenario would be that
01:04I took the highest power in this case, to beat, so the worst case is 9, always
01:11The highest value, the highest value on the die that it gives me, so I have 9 KVA over HP, okay?
01:26So logically, I have to translate this into terms of current, that is, amperes.
01:30How do I do that?
01:32So here it already indicates the first option; I would have to, to stay in KVA, first of all
01:39Multiply this by the HP, then the engine power, I'm going to assume an engine of...
01:48It occurs to me, right? About 5 HP, so I multiply that power by this and it simplifies things for me.
01:56So I already have 45 KVA here, right? 45 KVA, okay? Now how do I convert from KVA to current?
02:11Well, I know that power is equal to the square root of 3 line voltage times line current,
02:19Yeah?
02:22So what do I need here? I already have the apparent power, which is what I need.
02:28It's the nominal voltage, so the same as the motor nameplate data, I have to check, right?
02:34So if the motor tells me it's 220 volts, I'm going to assume 220 volts delta and that's how I
02:42He usually says,
02:42I'm going to put 127 and
02:49Which of the two Vesiria tensions?
02:53Let's see, how did they connect with their industrial control practices?
02:59The engine tells me this: 220 Delta and 127 Y
03:03Which of the two voltages does the motor operate at?
03:13Which of the two voltages does the motor operate at?
03:17127
03:20127
03:21127
03:24Are you sure?
03:26220
03:28Remember that the motor, our network is 220, right?
03:33This is then used to perform reduced voltage starting.
03:38then I apply 127
03:43at the beginning in Y
03:44And then I'll pass it to Delta, right?
03:46In the end, my engine stayed working in delta mode.
03:48220, this is the operating voltage
03:51So what would I have to do here?
03:53simplify this current
03:54which will be equal to this power
03:57divided by the square root of 3
03:59due to the voltage of the I
04:02Yes, then
04:03The current will be equal to the power
04:05that we just calculated
04:0745 KVA
04:09between square root of 3
04:10line voltage 220
04:13ready?
04:14What is the remaining value of the current?
04:18How much does 45K give me?
04:20Remember that K equals 10 to the 3
04:32118.09
04:34and at 118.09 amps
04:38So this is my stream of
04:41rotor locked
04:42or the starting current, right?
04:45ready?
04:45So I can get the factor, right?
04:48the current factor of
04:50I could put it back like that, just as it was.
04:57in the standard on and nominal
04:59It will be equal to 118
05:030.09 amps
05:06between the nominal value
05:07of this engine
05:16then the nominal current
05:18of this engine
05:19It will be the same as
05:27I'm missing the license plate information.
05:29I'm not going to complicate things for you.
05:31How much time do I have?
05:32It's already 11
05:33I'll leave this for another time, okay?
05:36to avoid confusion
05:37to use rather
05:38the engine plate data
05:39that I was using
05:41in any case
05:42I no longer have
05:43my starting current
05:44Yeah?
05:45the rotor current
05:48That's 118.09 amps
05:52then generally
05:53the engine gives me
05:54the current data
05:55too, right?
05:56It often happens to me in some cases.
05:57the nominal current
05:58and in other cases
06:00It doesn't give me
06:01So I want to teach them
06:03to obtain this nominal current
06:04even though I've already done it
06:06but with all
06:07to make it clear
06:08and don't stay
06:09This is flying through the air, isn't it?
06:12so
06:13This would be the current
06:15that will take
06:15my engine
06:16at the moment of startup
06:18and just to complement
06:19The idea, right?
06:20then remember
06:21that the current
06:21from INDUSH
06:23is equal to 1.6 times
06:25the rotor current
06:27blocked
06:29so
06:30this current
06:31would be equal to 1.6
06:32by
06:35118.09
06:36How much would you give me?
06:47the current
06:48magnetization
06:49How much will you give me?
06:49please
06:50118.09
06:53188.14
06:55198.94?
07:01Yeah
07:0294.
07:03already
07:03then look
07:04We already have both currents
07:06we have the current
07:08magnetization
07:09and the current
07:11a rotor
07:12blocked
07:12what I'm missing
07:14is to define
07:15the current
07:16nominal
07:16that factor
07:18I'm missing
07:19Inge
07:20Tell me
07:21And in what case?
07:27Don't give us the information
07:29of the current
07:29nominal?
07:30already
07:30thank you
07:31That's what I was getting at.
07:32How do I get it?
07:33that value
07:34current
07:35nominal?
07:36Let's check
07:41How do I get
07:42This data?
07:48How does it get
07:49the manufacturer
07:50That information?
07:55to verify
07:56the doubt
07:56from the colleague
07:57let's see
07:57good
07:59and let's see
08:00this engine
08:00It is three-phase
08:01says it is
08:023 HP
08:07and he tells me
08:08that
08:09These 3 HP
08:11help me
08:12with the calculation
08:13please
08:133 HP
08:14kilowatts
08:15How much will you give me?
08:23must give me
08:242.2
08:28Did it happen?
08:30Yeah
08:32It's giving me here
08:33the manufacturer
08:34in this case
08:35redundant
08:36in this case
08:37It's on HP
08:39and it says in parentheses
08:40in kilowatts
08:41There are the two values.
08:42good
08:43good
08:45I have the power
08:47at the exit
08:51the power factor
08:53He tells me it's the same.
08:54at 0.79
08:57He tells me that
08:58230 volts
09:04consume
09:057.82
09:067.82
09:06amperes
09:16and he tells me
09:18that efficiency
09:19nominal
09:19It's from
09:2089.5%
09:26No?
09:27That's what you're telling me.
09:28so
09:28with this
09:29I have to do the same
09:30so
09:31the power
09:32at the entrance
09:32It's going to be the same.
09:33to the power
09:34at the exit
09:34what is
09:352.2
09:36kilowatts
09:37between the performance
09:38what is
09:390.89
09:405
09:41How much will you give me?
09:42please
09:43from this?
09:532.45
09:542.45
09:552.45
09:56thank you so much
09:562.45 kilowatts
09:58No?
09:59so
09:59the power
10:00three-phase
10:01we had already said
10:02is equal to the root
10:03of 3
10:03line voltage
10:04line current
10:05cosine of the angle
10:06where the current
10:08online
10:08it's the same
10:09to this power
10:11of 2.45
10:12kilowatts
10:13between root
10:15of 3
10:15line voltage
10:17230
10:20multiplied
10:21due to the factor
10:22power
10:230.79
10:26How much will you give me?
10:27This, please?
10:546.87
10:566.87
10:586.87
11:03How much will you give me?
11:04This, please?
11:20How much will you give me?
11:21This, please?
11:266.87
11:27How much will you give me?
11:27This, please?
11:29if they see
11:30is approaching
11:31No?
11:32is approaching
11:32to the value
11:33that is giving me
11:34on plate
11:34my manufacturer
11:38if we are
11:39insurance
11:40from the calculations
11:40if they are okay
11:417.78
11:43how much?
11:457.78
11:46how much?
11:477.78
11:47They already did it to me
11:48scare
11:48thank you
11:497.78
11:52approximating
11:537.8
11:54amperes
11:54So there it is.
11:55look
11:55Are you there?
11:58Yeah?
12:00verified
12:01No?
12:03How to get
12:03the current?
12:04Yeah?
12:07as I told you
12:07some manufacturers
12:09They all give me
12:09the data
12:10some do not
12:11but they give me
12:11the basics
12:12and based on them
12:13I can get
12:14the data
12:14that I'm missing
12:16What was made clear?
12:17for the
12:17who asked me
12:19about this
12:19how to obtain
12:20the current?
12:22Yeah
12:23thank you
12:23thank you
Comentarios