- hace 12 horas
Tutorial y uso del Catálogo Martín, para diseño de elementos de Máquinas.
Dadas las restricciones de YouTube, no se puede publicar directamente aquí en la descripción, el archivo y link del catalogo Martin, estará en el primer comentario
Catálogo Martín :
https://issuu.com/msg-mexico/docs/cat4000-d
https://pdf.directindustry.es/pdf/martin-sprocket-gear-9091.html
Dadas las restricciones de YouTube, no se puede publicar directamente aquí en la descripción, el archivo y link del catalogo Martin, estará en el primer comentario
Catálogo Martín :
https://issuu.com/msg-mexico/docs/cat4000-d
https://pdf.directindustry.es/pdf/martin-sprocket-gear-9091.html
Categoría
📚
AprendizajeTranscripción
00:09What are trapezoidal belts?
00:31I'm going to base myself mainly on Martin's catalog, guided respectively by this example that was
00:39In the same catalog, I would recommend that they also open the catalog to see if they can find the information they need.
00:47to also manage Martin's catalog.
00:50And since it was working well through this example, I have solved an exercise that I had set myself.
01:00What would this exercise be?
01:03It states that a 5 HP electric motor at 1750 RPM must move a compressor at 700 RPM.
01:14The centers of the pulley shafts should be approximately 20 inches apart.
01:20The service is continuous and the load is constant.
01:23We need to read this exercise carefully because it gives us data to go to the tables and select the
01:31following data.
01:33As we have, we are going to calculate, it says the diameter of the driving pulley, the diameter of the driven pulley, the number
01:39of bands and the distance between centers.
01:42The data we have includes a 5 HP motor and a 1750 mAh drive unit.
01:52We'll take the biggest one.
01:54And the one for the driven machine is 700 RPM.
01:58The distance between centers is 20 inches, and as it tells us here, the service is continuous and
02:06with a constant load,
02:07That means more or less that it operates 24 hours a day with a constant load.
02:12Okay, let's look at the first step.
02:16The first step tells us that it is to determine the power of the design in HP.
02:21For the first thing we have this formula which is the power of the design which is equal to the power
02:27from the engine data and by the service factor.
02:31We must obtain this service factor from the catalog in a table.
02:36We're going to go to table number 1.
02:39This is the catalog that I have already set aside so as not to delay and to start searching.
02:47But we can still go to the catalog to continue looking for it.
02:51It says, here we have the necessary information which is trapezoidal band transmission.
02:57We have the engine power, the engine RPM, the driving machines.
03:02Okay, as the statement of the exercise also told us, it's a continuous service, so
03:10We have a first point.
03:12This first point ranges from 1.2 to 1.8.
03:15The other point we had was that it was a continuous service.
03:19The continuous service tells us that it is from 16 to 24 hours.
03:22In our case it was 24 hours, so we are on continuous service.
03:28Okay, so let's go here to table number 1.
03:31We have the typical service factor.
03:34We have the different types of transmission machinery.
03:36In this left section we have the different machines that can be offered.
03:42We also have in this right-hand section the types and the driving units.
03:48We have electric motors that are normal torque, squirrel cage, isosynchronous, and split phase.
03:56In this section we have high torque, split phase, repulsion and induction.
04:04In our case, since it is a normal torque, we are in this section.
04:08Now we are going to choose, as he told us, that it was to transport a band.
04:13In this section we will look at what the machinery is.
04:17This section tells us that it is in this section.
04:20What do transporters tell us?
04:23Yes, so we're in this range.
04:25And as he was saying in the continuous service range, then it would be the service factor, it would be
04:33be 1.4.
04:39This would be the service factor.
04:41So we come to replace the formula that told us about the engine.
04:46Since we had a 5 HP motor due to the service factor, which is 1.4.
04:51This gives us 7 HP.
04:54We already have the first piece of information that we're going to use, so let's solve the exercise.
05:01Step number 2 says that it determines the section of the band.
05:05Okay, so in this one we're going to go to table number 3.
05:09I also have it in this section.
05:12Table number 3 tells us what the conventional bands are.
05:16Based on our calculations, the 7 HP and the revolutions we have here of 1,750 revolutions,
05:26We're going to this catalog, to this table.
05:30As it tells us here in this section, we have 7.
05:34Here's the one for 7.
05:36And from the RPM on the X-axis we get the power in HP.
05:41And on the Y-axis we have the RPM of the fastest shaft.
05:46In this case our fastest axis is 1.750.
05:51So we come from this section until we cross paths.
05:54It's on the 7th.
05:56Sorry, this one's here.
05:58And then I would be in section A.
06:02Already.
06:04Then, as point number 2 tells us, from table number A the band that will be is determined.
06:10type A.
06:11In this case, it was one of the conventional bands.
06:14We also have a section for high-capacity bands.
06:19We have what is the same way.
06:22Since it's given as 7, it's roughly around here.
06:25Equal to 7,000.
06:27This would already be included in 3B.
06:29For capacity bands.
06:31But we're going to work on the conventional bands.
06:35We already have the second step.
06:38Instead, let's go to step number 3.
06:41It tells us to check the minimum diameter of the drive pulley.
06:45We're doing the same thing, in the same way, everything comes from Martin's catalog.
06:50Let's go to the catalog, to table number 4.
06:56Here it tells us, table number 4 tells us the minimum diameters recommended for the electric motor pulley.
07:03In the section here on the right we have the engine power in HP.
07:08And in this section we have the engine RPM.
07:11As we have calculated the one for 7 HP.
07:15But we don't have here the closest one, which is 7.50 HP.
07:20And the revolutions we are working at are 1750 RPM.
07:26So we came from here.
07:28And then our minimum diameter would be 3 inches.
07:35Already?
07:38So, as we have here from table number 4, the minimum diameter would be 3 inches.
07:45So let's move on to step number 4.
07:50Step number 4 tells us about the transmission selection.
07:53I already set everything aside for myself so I wouldn't have to keep looking in the catalog.
07:59It's on page 189.
08:02What does it tell us about the transmission selection tables in existence for type A bands?
08:08We already had this information.
08:10The RPM data of the engine unit.
08:14This data gave us.
08:15And the data on the machines powered.
08:17So the data we're going to calculate is the HP per belt, the drive pulley, the driven pulley, and the
08:25distance between centers.
08:26We will calculate this using the catalog.
08:30Marti's catalog.
08:32So with this information we'll go to page 189.
08:41I already have here the catalog of transmission selection in stock.
08:46It is type A.
08:49So first we'll look at the speed of the boosts in HP per belt.
08:54Since we are using the one, it gave us a data of 1750.
08:59We are in this section.
09:02This section also includes the RPM driven.
09:08Which gave us the same data that it was 700 RPM.
09:12So we come here to the 700 RPM ones.
09:15We're going to use this entire section to get our data.
09:22So now that we have this, let's go to the HP per band that it gives us in section A.
09:28Our HP per band would be 3.24.
09:343.4 HP per belt.
09:37We got this from the catalog recently.
09:40From here.
09:42Now, it says the pulley combination.
09:44It says checking the minimum diameter.
09:46The minimum diameter we had was 3 inches.
09:49Yes, and it tells us that a formula determines whether it must be greater than or equal to the diameter of the pulley.
09:58motor.
09:58Then we go to the catalog.
10:01And in this section on the left that says pulley combination.
10:05We have the diameter of the driving pulley and the diameter of the driven pulley.
10:09The diameter of the drive pulley is 3.6.
10:13In which we will replace in this to make a difference.
10:17Which is 3 inches.
10:19And it is greater than or equal to 3.6.
10:22Sure, at 3.6 inches.
10:24So we're in this range.
10:26If we're in the same catalog.
10:29And the drive pulley would then give us 3.6.
10:343.6 inches.
10:35The diameter of the driven pulley can also be found here in the catalog.
10:40Which is 9 inches.
10:43Yes, the driven pulley diameter is 9 inches.
10:48So now, with this data, we're going to calculate the distance between centers.
10:54Firstly, as I told you in the exercise.
10:56The distance between centers tells us that it is approximately 20.
11:0220 inches.
11:03Then in the same, in the same table.
11:07Here we have the nominal center distance and arc length correction factor.
11:14This would be covered in this section.
11:17However, in this section we do not have one that is close to 20.
11:21It's in the section below.
11:23And here we see the one that comes closest to 20 inches.
11:26The one that comes closest to 20 inches is the 20.6-inch one.
11:30Which is given to us by the distance between centers.
11:34It would be the one that comes closest to 20.
11:36It would be the 20.6-inch one.
11:39So then to choose the band that is from A60.
11:42From the same catalog.
11:43How are we calculating this distance between centers?
11:48No, not her...
11:50We already calculated the distance between centers.
11:53So our band is going to be, like we're in type A.
11:59It's going to be an A60.
12:01Which would come here.
12:03Because we have the others here.
12:05But these are irrelevant facts.
12:07If it is not given this data.
12:09It would be an A60.
12:11The one we would choose.
12:15Now for the next point.
12:17This is the last step we're going to take.
12:20What is band-corrected power?
12:23Similarly, the band-corrected power.
12:25It can be calculated using...
12:28The formula.
12:29What is power per band?
12:31Due to the correction factor.
12:32By length and arc.
12:34We already calculated this data in the first section.
12:39No, we calculate the power per band in the catalog.
12:43The HP per band gives us 3.4 HP per band.
12:49So we replaced it.
12:51In contrast, the correction factor for arc length.
12:54We will obtain it through this very catalog.
12:58As the correction factor for arc length tells us here.
13:02How we are working on this series.
13:05Then it is given to us in this section or lead.
13:08The correction factor for arc length is given to us.
13:11In this case we will work with 0.93.
13:16Already.
13:18Then we replace this data.
13:24We replaced the data of 3.24 HP per band with 0.93.
13:29That gives us a total of 3.01 HP per band.
13:34We would now have the corrected bandwidth power.
13:37This will help us determine the number of bands that need to be used.
13:42We will do this by dividing the design power by the band-corrected power.
13:48Which we just obtained.
13:50By then the number of bands would be equal to 7 HP.
13:54We calculated this in step number 1.
13:58Divided by the step we calculated earlier.
14:01What is band-corrected power?
14:03That would be 3.01 HP per band.
14:07We simplified HP.
14:09It gives us 2.33 bands.
14:13We're going to use approximately all 3 bands.
14:18We already approximated this to a 3-band one.
14:22So the speed ratio tells us that it is the same in this catalog.
14:28We come here to the right-hand section.
14:30The speed relationship.
14:32It says it comes at 2.50.
14:35We obtain all of this through the catalog and the data we are working with.
14:41Then he finally says to ask Martin.
14:44This time we are going to ask Martin for about 3 bands of 36.
14:51We get this from the drive pulley.
14:53Which gave us 3.6 multiplied by 10.
14:58It gives us a band of 36 type A.
15:02This is the same for the driven pulley.
15:04That comes to us equally on 3 sides.
15:07Just like it gave us 9 on the driven pulley.
15:11In a type A.
15:15We also followed this example as a guide.
15:19That was listed here in Martin's catalog.
15:23Similarly, it was being given and all the data was being obtained from Martin's catalog.
15:30And like me, so I don't have to be searching page by page.
15:34I've already passed on all the information here.
15:38Do you have any questions about how to use the catalog or how the exercise was solved?
15:45I don't know if that was clear enough, but I'd like to explain anything else you might have questions about.
15:54No questions, mate.
15:56Yeah.
16:00None?
16:02No, none.
16:04Okay, next.
16:07I'm going to explain how to select a string, and I'll use an example.
16:14Let's...
16:15The procedure for selecting chain and sprocket transmissions.
16:19We will select using 8 steps.
16:24The first step is to determine the class or type of driven load chain.
16:29Select the service factor.
16:32As a third step, we need to calculate the design power.
16:36Select the chain step.
16:38As a fifth step we will calculate.
16:40We will select the number of teeth on the small sprocket and the number of teeth on the large sprocket.
16:45As a seventh step we will determine the distance between centers.
16:49And as the eighth step, we will calculate the length of the chain.
16:53I have chosen to explain by using an example and to write it out step by step with you.
17:00Well, here we have an example that tells us about a uniform load conveyor of a chain drive system.
17:07To determine a motor with a power of 10 HP.
17:10At a speed of one right-handed wheel of albotions per minute.
17:14With a 250 centrifuge and a center-to-center distance of 50.
17:19Design a suitable chain drive.
17:22Well, for this we relied on Martin's catalog.
17:26We have it right here.
17:27Well, as a first step we need to select our service classification.
17:34Let's take a screenshot.
17:38And we are putting together our document little by little to finally share it with you.
17:46Well, the exercise tells us that it's from a freight conveyor.
17:53Here we have it, here it is, it's a cargo conveyor system.
18:02Already.
18:05Then, we proceed to select what our uniform load is.
18:10It tells us that it is from a uniform loading system.
18:14We have it here, a uniform load conveyor.
18:17So, this is going to be step number one.
18:24Then, to perform step number two.
18:29Step number two.
18:31Let's go, maybe we need to go to our catalog.
18:35And here we're going to use the service factor.
18:38We'll take a screenshot anyway.
18:40And we're going to gradually put together our document.
18:48In our service factor we have to see which one, through step number one, which gave us that it is a
18:57uniform load.
18:58And one feature is the uniform load conveyor.
19:01We need to classify by the service which is a uniform load.
19:05And in the, in the drive unit is the, it's an electric motor that's one point a
19:11zero.
19:20That would be step number two.
19:23Let's do it step by step.
19:25as step number 3
19:30we will have to
19:32determine the design power
19:36Well, to determine the design power we have a formula
19:40what does it tell us?
19:44which tells us that the design power
19:47Let's see with this equation that the design power
19:54It's going to be the same.
19:56to the engine's power
20:01by
20:04due to the type of drive unit
20:12the power of our engine
20:15In the exercise, he told us that the engine power
20:19It's going to be from
20:22out of 10
20:24HP
20:25It's going to be 10 HP
20:32and for our unity
20:34because of our type of power unit
20:36which is an electric motor is 1.0
20:38We have to multiply it by 1.0
20:52This gives us a result
20:54out of 10
20:57HDP
21:00That's our step number 3
21:02proceeding to step number 4
21:06we have to select
21:08our streaming selection
21:11And that's it, let's go to Martin's catalog
21:13and we have on page 483
21:16to select our
21:21our streaming selection
21:23we have to select
21:25And we'll take a screenshot too.
21:27to do it step by step
21:34on the horizontal line
21:36which are the ones here
21:37There will be revolutions
21:39and on the vertical line
21:40they're going to be there
21:42the power of our engine
21:44And this is very important.
21:49point out
21:52given that
21:56then we have to take
21:58our diagonal line
22:00at the point where we collide
22:13already
22:14as we have here
22:16our image
22:18It tells us that
22:19on the vertical line
22:22The power will be there
22:24which is 10 HP
22:25We're going to point it out.
22:26with a line
22:29that gives us the power
22:3110 HP
22:32It gives us this way
22:36then we have to point out
22:38with a line
22:42as we can see
22:43There's the line
22:44of our power
22:46and then we will proceed
22:48to point out
22:48with an equal line
22:49the revolutions
22:50good in the example
22:51in the example
22:52he told us
22:52that revolutions
22:54It's going to be
22:55of a thousand revolutions
22:56per minute
22:57then we proceed
22:58equals to point out
23:02our revolutions
23:04which are
23:05of a thousand revolutions
23:06per minute
23:09Here we have
23:11the thousand revolutions
23:12per minute
23:13and we proceed to point out
23:16Well
23:17once already indicated
23:18our
23:19our
23:20our parameters
23:21we have to
23:22we have to choose
23:24a diagonal line
23:25that it is
23:26that is joining
23:27to the two lines
23:28and therefore
23:31and therefore
23:33It's going to be
23:33he
23:35the line
23:35that is uniting
23:36at two
23:37It's from here
23:39a diagonal line
23:41from here
23:44I'm going to point her out
23:45with
23:46a blue line
23:48is approximate
23:50this
23:50It's the line
23:51that is crossing
23:52at two
23:53they are being intercepted
23:55the two lines
23:55from here
23:56as you can see
23:57the diagonal line
23:57it's there
23:59already
23:59so
24:00once
24:02once selected
24:06number 50
24:07It's going to be
24:08the steps
24:08and here
24:10Therefore
24:11are
24:11number 17
24:13that is seen
24:14that can be seen
24:15very small
24:16I'm going to do it
24:17a little big
24:18number 17
24:19They're going to be
24:20the teeth
24:20that has
24:21that chain
24:24Well
24:26Step 4
24:30we are going to do
24:31Step 5
24:35Step 5
24:36he tells us
24:37that
24:38have
24:39which to select
24:40the spoken motor
24:41and it is recommended
24:42use
24:43a number
24:4417 teeth
24:45a minimum number
24:46and as we have
24:47the 50 step
24:48and the number
24:49and a minimum number
24:5017 teeth
24:51if it complies
24:52to perform
24:53to continue doing
24:54the exercise
24:54Well
24:55have
24:56the step
24:57the step
24:58chain
25:00what is
25:01of 50
25:03and
25:04a number
25:0517 teeth
25:09that gave us
25:10in the table
25:10selection
25:11quick
25:14we will proceed
25:15at a pace
25:15number 6
25:19in the step
25:20number 6
25:21he tells us
25:21that we're going
25:22to calculate
25:23spoken
25:25driven
25:25Well
25:26this
25:26this number
25:27it is calculated
25:28a base
25:28of a
25:31a base
25:31of a
25:32formula
25:32which in continuation
25:33I'm going to show you
25:36Well
25:37the formula
25:38he tells us
25:38What will it be?
25:39the number
25:39of teeth
25:40because of the revolutions
25:41per minute
25:42about the
25:43centrifuge
25:44have
25:45the number
25:46of teeth
25:49the number
25:50of teeth
25:50It's going to be
25:51equal
25:51to the
25:53at
25:55revolutions
25:57at
25:59revolutions
26:00per minute
26:02have
26:03the revolutions
26:04per minute
26:05about
26:05the centrifuge
26:12replacing
26:13this data
26:17replacing
26:18this data
26:19have
26:19that
26:19the number
26:20of teeth
26:26the number
26:26of teeth
26:28let's calculate
26:29the number
26:29of teeth
26:31the number
26:32of teeth
26:35driven
26:40as I told you
26:41It's going to be
26:41equal
26:42to the number
26:44to the number
26:44of teeth
26:46by the
26:46revolutions
26:47per minute
26:48about the
26:48centrifuge
26:52already
26:56have
26:57the number
26:58of teeth
26:58driven
26:58It's going to be
26:59equal
26:59to the number
26:59of teeth
27:03multiplied
27:03by the
27:04revolutions
27:04per minute
27:05about the
27:05centrifuge
27:06how much
27:06have
27:06of the number
27:07of teeth
27:07according to
27:09our
27:09board
27:09of
27:11selection
27:11Quick?
27:12have
27:13what is
27:13here
27:13have
27:14what is
27:1417
27:15have
27:16the number
27:16of teeth
27:17Therefore
27:18we placed
27:19here
27:19the number
27:19of 17
27:20the
27:21revolutions
27:22per minute
27:22We already talked about it.
27:23that the
27:24revolutions
27:24per minute
27:24had
27:25a revolution
27:26of a thousand
27:27and the
27:28centrifuge
27:29Well
27:29the centrifuge
27:29it gives us
27:30here
27:30in the exercise
27:31that we
27:32says
27:32that the
27:32centrifuge
27:33It's going to be
27:33of 250
27:36already
27:36we obtain
27:37we obtain
27:38of that
27:38fact
27:39of 250
27:43we replace
27:43of our
27:44equation
27:46and so?
27:47It's going to give us
27:47an equal
27:48a result
27:49of
27:54and so?
27:56It's going to give us
27:56equal
27:56a result
27:57of 68
27:58teeth
28:04Well
28:06how is
28:07a number
28:07whole
28:07we don't have
28:08that approximate
28:09But if it were
28:10with numbers
28:10decimals
28:11we have to
28:12bring him closer
28:12because
28:13for the next
28:14passed
28:14we don't have
28:16a number
28:17with decimals
28:18but we don't have
28:18just numbers
28:19exact
28:20now for the step
28:23to perform
28:24the step
28:24number
28:267
28:29it asks us
28:30calculate
28:31the distance
28:31between axles
28:33oh well
28:34here we
28:35They already give us
28:37the distance
28:38between axles
28:39in equal
28:39in the exercise
28:40It gives us a distance
28:41between axles
28:42which is from
28:43the distance
28:44between axles
28:45which is from
28:4550 thumbs
28:49equal
28:50as it gives us
28:51the distance
28:52between axles
28:54we only have
28:55that replace
28:55with the letters
28:56C
28:57What will it be?
28:57C is going to be
28:59equal
28:59at a distance
29:00between axles
29:06and C
29:09have
29:10a number
29:11of 50
29:1350 thumbs
29:14That's ours.
29:16That's ours.
29:17distance
29:17between axles
29:18if we didn't have
29:19that
29:19if we didn't have
29:20in the exercise
29:21we would have
29:22that calculate
29:23the distance
29:23elderly
29:24minus the distance
29:24minor
29:25if not
29:26porenthesis
29:27like A or B
29:27would not give us
29:29in the exercise
29:30the distance
29:31between axles
29:32Well
29:33for
29:34for
29:34for the next
29:36passed
29:38And it's the last one
29:40passed
29:40let's calculate
29:42the length
29:43of the chain
29:45to calculate
29:46the length
29:47of the chain
29:47we are going to use
29:49a formula
29:51equal
29:51just as we can
29:52notice
29:53in the
29:53in our
29:54in our
29:55catalog
29:56by Marti
29:56that is
30:02this way
30:06on the page
30:08467
30:09from the pdf
30:11Here we have
30:12how to calculate
30:13our
30:13our
30:14long
30:14our
30:15our length
30:16of the chain
30:17we are going to use
30:19these formulas
30:20but we're going to replace
30:22the letter
30:23the letter
30:23What will it be?
30:24a tabular value
30:25that we have to take out
30:27We need to take out
30:27the tabulated value
30:28of our
30:29of our issue
30:30of teeth
30:31of the major spoker
30:32minus the number
30:33of teeth
30:33of the minor spoker
30:34We need to get that out.
30:36to take out
30:36our tabular value
30:38Well
30:39let's calculate
30:41It tells us that
30:42the length
30:45the length
30:46It's going to be
30:47equal
30:49to the
30:51twice
30:52twice
30:54the c
30:54Well
30:55which was the c
30:56It was the distance
30:57between
30:58between centers
30:59that
30:59the distance
31:00between centers
31:01that we have here
31:02or the distance
31:02between x
31:03we have it here
31:06This is going to be
31:08further
31:12plus the
31:18further
31:20the n
31:21that the n
31:21I already told you
31:22which is the
31:23the number
31:24of teeth
31:24of the eldest
31:26further
31:27the n
31:28lower case
31:29What will it be?
31:29the number
31:30of teeth
31:30of the minor
31:31all that
31:32divided
31:32for two
31:34all this
31:35It's going to be
31:36further
31:39the letter
31:41the letter
31:42to
31:43that I told them
31:43which was
31:45the value
31:46tabulation
31:46But before that
31:47we need to calculate
31:48he
31:49the number
31:51of teeth
31:51of the eldest
31:52minus the number
31:53of teeth
31:53of the minor
31:55Well
31:55all
31:57all the value
31:58tabulation
31:58It's going to be
31:59divided
31:59for
32:00for the letter c
32:02What is distance?
32:02between centers
32:03or the distance
32:04between axles
32:04already
32:06once
32:08we have our
32:09equation
32:10we're going to
32:11we're going to
32:12First we're going to
32:13namely
32:15what is it equivalent to
32:16our
32:16as I already told you
32:18that our
32:19our value
32:22tabulation
32:22It's going to be
32:24equal to
32:24our value
32:25tabulation
32:26It's going to be
32:26equal to
32:29to the
32:30to the
32:31to the number
32:32of teeth
32:33of the eldest
32:33less
32:34the number
32:35of teeth
32:36of the minor
32:38What is the number?
32:39of teeth
32:40of the
32:41elderly
32:42we have here
32:43the 68
32:44teeth
32:45that we took
32:46That's the number
32:47of teeth
32:48of the eldest
32:50the 68
32:50teeth
32:51that we took
32:52This is going to be
32:53the number
32:54of teeth
32:54of the eldest
32:55And the number of teeth for the smallest one will be this one here that we found in our selection table.
33:00This will be the number of teeth the youngest child will have.
33:02Therefore, we only have to subtract
33:09We subtract them, which would be 68 teeth minus the 17 teeth we obtained from our quick selection table.
33:19That gives us a value of 51
33:30That's our tabulated value
33:35With this value, we also need to go to our Martin catalog.
33:43And look here, here it tells us the value of A for calculating the length of the string
33:49We need to find what we subtracted
33:54Our number of teeth of the largest minus the number of teeth of the smallest
33:57which came out to 51
33:59We have to look for it and it gives us 51 here
34:02And here we have our A, which is the tabular value
34:08Let's take a screenshot.
34:11to have a record
34:19We must keep this in mind
34:21in obtaining our tabular value
34:25And that's why we also said here
34:27the number of teeth has to come out
34:29It has to come out whole.
34:31because with decimals
34:33there is no
34:34does not exist
34:35as
34:36how to solve it
34:37It's going to come out with decimals
34:39and here in our table
34:41in order to observe
34:42There won't be any with decimals.
34:44we need to approximate
34:46Well, once it's been calculated
34:48our tabulated value
34:51We are now proceeding to replace it.
34:52in our formula
34:54to take out
34:55the distance
34:56the length of our chain
35:01Yes, we replaced
35:03Well
35:04It's going to be the same.
35:05the length will be the same
35:06a 2
35:07that multiplies
35:09at a distance
35:09between centers
35:10or at a distance
35:11between axles
35:11as I told you
35:12Here we have the distance
35:13between centers
35:14or between axes
35:15which gives us 50
35:15This is what we got in the exercise
35:17It gives us 50
35:20then we proceed
35:21to replace it
35:22which would be 50
35:26he tells us
35:26further
35:27the number
35:28of the largest teeth
35:29what was the number
35:30of the largest teeth
35:31we have here
35:32which had 68 teeth
35:37we proceed
35:3768 teeth
35:39further
35:40the number
35:40of the child's teeth
35:41that we had
35:43here
35:44which was
35:4517 teeth
35:46that we obtained
35:46from the table
35:47quick selection
35:49have
35:5017 teeth
35:51all this
35:51It will be divided
35:52for 2
35:52further
35:54the value
35:56tabulation
35:56the tabulated value
35:57we already obtained
35:58using the table
36:00and the table
36:01it gave us
36:02at 65.88
36:06That's ours.
36:08our tabulated value
36:0965.88
36:13we proceed
36:1465.88
36:16once
36:1865.88
36:20divided
36:21same for
36:22the
36:23the distance
36:24between centers
36:25between axles
36:25that gave us
36:26which was 50
36:28Well
36:29once
36:32replaced
36:33the data
36:33we proceed
36:35to take out
36:37our
36:38our result
36:39that gives us
36:42a total
36:42of 143.8
36:45steps
36:46143.8
36:48steps
36:50Well
36:50This has been
36:52This has been
36:52a
36:53an explanation
36:54a little fast
36:56and a little
36:57an explanation
36:58quick
36:58a bit
36:59simple
37:00also
37:00the exercise
37:01and that we have
37:01that fulfill
37:02the eight steps
37:03in order to be able to
37:03select
37:04very good
37:05our
37:06chain
Comentarios