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Physics with Akhtiar Ali Bullo
  • 1 year ago
Physics class 11th
Mdcat physics
Physics derivation
First year physics
Transcript
00:00The relation between linear and angular physical quantities so we have to get s
00:13is equal to r into theta and second is V is equal to r into omega and third is a
00:21is equal to r into alpha means here we can write linear or angular physical
00:29quantities relation. So first s is equal to r into theta
00:36equation we will obtain. As we know that angular displacement theta is
00:47equal to arc length divided by radius so here arc length denotes to linear
00:57displacement so it will be r into theta is equal to s or we can also write this
01:14equation as s is equal to r into theta which is our required condition. The
01:25second one is V is equal to r into omega is is s is equal to r into theta so by
01:43dividing t means time on both sides so this equation will be s upon t is equal
02:03to r into theta upon t is linear displacement upon time is equal to
02:11linear velocity is equal to r will remain same and angular displacement
02:18upon time is equal to angular velocity so we have obtained the required
02:26condition is V is equal to r into omega. The third one is a is equal to r into
02:35alpha means linear acceleration is equal to radius into angular acceleration is V
02:44is equal to r into omega so dividing t on both sides it will be V upon t is
03:04equal to r into omega upon t is linear velocity upon time means change in
03:14linear velocity per unit time is known as linear acceleration so it will be a
03:20is equal to r will remain same angular velocity upon time is equal to angular
03:30acceleration means alpha so this is our required condition thank you
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