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A photoelectron moves at a speed of 1.35x10⁶ m/s. What is the stopping potential?

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00:00Dear friends, be persistent, patient, and never give up in learning.
00:08The photoelectron in the photoelectric effect experiment moves in a straight line at a constant speed.
00:15Now, we are asked to calculate the stopping potential of the electron.
00:22In the problem sheet, we see the values for the electron's velocity, electron's mass, and electron's charge.
00:30The image on the monitor screen is the apparatus for conducting the photoelectric effect experiment.
00:39There are two conducting plates inside a vacuum tube.
00:45Both plates are connected to a battery.
00:50When viewed from the battery's poles, the left plate will be positively charged, and the right plate will be negatively charged.
00:57A beam of light is directed toward the left plate.
01:04Immediately after absorbing a photon, an electron from the left plate will move toward the right plate.
01:10This is the photoelectron.
01:16The photoelectron moves with an initial velocity V to the right.
01:20Observe closely.
01:25The electron is a negatively charged particle.
01:28The left plate, on the other hand, is positively charged.
01:33According to Coulomb's law, negative charges are attracted to positive charges.
01:40The electron moves to the right, but the Coulomb force is to the left.
01:44The velocity and force are in opposite directions.
01:49This means the electron will slow down to the right.
01:54The stopping potential is the voltage between the two poles that must be applied so that the photoelectron enters the right plate.
02:01Then, the electron moves back to the left toward the positively charged plate.
02:11So, there are two important points here.
02:14The first point is located at the positive pole.
02:18The second point is at the negative pole.
02:20Because energy is conserved, the energy at point 1 is the same as the energy at point 2.
02:31At point 1, the electron has kinetic energy.
02:35However, the electron is still attached to the positive pole.
02:42At point 2, the electron stops moving, but it has electrical potential energy.
02:46Half mv squared is equal to ev0.
02:53The value of v0 is the stopping potential.
02:59Some of these values are known.
03:04This is where the calculator comes in.
03:07V0 is approximately 5.2 volts.
03:11This is the answer to this question.
03:13Happy learning, everyone.
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