00:00The question is resistances of 4 ohm, 6 ohm and 12 ohm are connected in parallel and then
00:10joined to an EMF source of 6 volt.
00:13Find the value of 1 the equivalent resistance of the circuit, 2 the total current from the
00:21circuit, 3 the current passing through each resistance.
00:263 resistances R1, R2 and R3 having values 4 ohm, 6 ohm and 12 ohm are connected in parallel
00:37combination and EMF source of 6 volt is also connected with the resistors.
00:44First of all, we will form a data, R1 is obtained as 4 ohm, R2 is obtained as 6 ohm,
01:09R3 is
01:12obtained as 12 ohm and potential difference is obtained as 6 volt.
01:25So, we have to find equivalent resistance R, total current I and current passing through
01:40each resistances means I1, I2 and I3 because there are 3 resistors.
01:54First of all, we will find equivalent resistance.
02:02First, we will calculate R, is resistances are in parallel combination, so their equivalent
02:11resistance can be calculated by using formula 1 upon R is equal to 1 upon R1 plus 1 upon R2
02:20plus 1 upon R3. So, the value of R1 is 4 plus the value of R2 is 6 plus the
02:36value of R3 is 12.
02:39So, by taking LCM, the LCM of 4, 6 and 12 is obtained as 12. So, the table of 4
02:51on 12 is 3 times.
02:54times, so 3 into 1 it will be 3, the table of 6 on 12 is 2 times, so 2
03:00into 1 it will
03:01be plus 2, plus the table of 12 on 12 is 1 times, so 1 into 1 it will be
03:081, so 3 plus
03:102, 5 plus 1, 6, so 6 upon 12, 1 upon r is equal to 6 upon 12, the table
03:22of 6 on 6 is
03:231 times and on 12 is 2 times, so it will be 1 upon 2, so 1 upon r is
03:29equal to 1 upon
03:302, so r will be equal to 2 ohm, this is equivalent resistance, now we will
03:42calculate total current is total current of circuit i is equal to V upon r, this equation
04:07is taken from ohm's law, so electric potential is obtained as 6 divided by total
04:16resistance is obtained as 2, so 6 divided by 2 it will be 3 ampere, means total current
04:26is obtained as 3 ampere, now we will calculate current through each resistances,
04:35is here resistors are in parallel combination, so the current will be different in each resistor,
04:44so we will find the current in all the resistors, so current through r1, the current through r1
05:03is i1 is i1, so i1 will be equal to V upon r1, so V is 6 divided by r1,
05:12r1 is 4, so 6 upon
05:144 it will be 1.5 ampere, now current through r2, so the current through r2, so the current through
05:33r2 is i2 is i2 is i2 will be equal to V upon r2, is electric potential will be same
05:42in all the resistors,
05:43because they are in parallel combination, so 6 upon r2, the value of r2 is 6, so it will be
05:541 ampere, now current
06:04current through r3, the current through r3 is i3, which is V upon r3 will be equal to the value
06:20of V is 6, the value of r3 is 12, so it will be the table of 6 on 6
06:27is 1 times and on 12 is 2 times, so it will be 6, so it will be 2 times,
06:29it will be 1 upon 2 ampere or we can also write it as 0.5 ampere.
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