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Rohit
Let p = (x + y + z) and q = xyz. If
| x 1 1 | | 1 y 1 | | 1 1 z |
is positive, then which one of the following is correct?
(a) q > p
(b) q + 1 > p
(c) q + 2 > p
(d) q + 2 ≥ p
#NDA #NDA2026 #Mathematics #Matrices #Determinants #NDAAspirants #NDAPreparation

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Learning
Transcript
00:00Here it is given in the statement that P is equal to X plus Y plus Z then Q is equal
00:04to X into Y into Z
00:06And it has given us its determinant positive, so we have to ask which one is correct.
00:11So first let's simply say solve, this becomes X into YZ minus 1
00:20We had to open the determinant by pressing minus 1 into the middle key and the rest in the left and right keys.
00:25minus 1 into Z minus 1 plus 1 into 1 minus Y
00:34Now let's open this further and it will become XYZ minus X minus Z plus 1 plus 1
00:46minus Y
00:48Now what does this become, let's take XYZ plus 2 minus common.
00:57Taking minus X minus Z minus Y from this becomes minus common
01:02What should X plus Y plus Z keep us from doing?
01:06This is positive, so what can we write from this is greater than 0
01:11This is positive, meaning it will increase from 0.
01:14So now we solve it further in the bar.
01:17The value of XYZ is Q
01:20The value of X plus Y plus Z is P
01:23That is, Q minus P plus 2 is greater than 0
01:29Move P to this side
01:32Q plus 2 is greater than P
01:36So which option is this?
01:38C, option number C is final answer
01:40Jhal Jhal
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