00:00So here in the marks it is given that A is a six foot one of the terms
00:05A P ka jitki fat tum jo a vo to a 1
00:07That common def dirench will also make it so much 5 i.e. this type will also be made 1,6,11
00:15,16
00:16Now what will happen to Swinal Tom, we will apply the formula of AP and Yankee and then one is equal to F
00:25Term turns n minus one into the number of terms from how many even and then one minus one to hundred
00:32Into Common Deprenz
00:35So this 5 i.e. 100 into five i.e. 501 becomes the final term of the first AP.
00:42It's done
00:44A set contains all the elements from 1 to 501.
00:52There is only one B sheet, how many elements are there in it, the first term is inside B, this is nine.
01:01And from common depressant 7 then some AP of this time will also be 9,16,23 for this time and
01:12Its final term is 9 plus 71 minus 170, this n is equal to this formula.
01:21We also applied that n is equal to a plus n minus 1 d, that is, 70 into d.
01:28How much is 7 i.e. 499 499 Now we have been asked that in this intersection also
01:39How many elements so that are divisible by 3 now what will be the enter section which is times a
01:49I planned to memorize a section of the model and also to memorize it before the two meet.
01:56If I am crying then it is available in both the corners, so first of all we will start with 16 Zetas.
02:0216 se mai fivi teen ko man naygi nahi toh it was 16
02:17Let's take the LCM of 5 and 7. Now what will that be? Let's take the LCM of 5 and 7.
02:24comes
02:255 and this 7 means 7 5.35 means after every 35 the common time will be 16
02:35Plus 35 means
02:38What is this 16 plus 35, that is 1 4 4 not 11 6 plus 5 11 Jiri 1415
02:51That means it would like to go ahead in 51 such ways.
02:54So I want to find out how many terms it would take first of all. This comes in our footer.
03:00intersection B 16,51 will continue like this
03:06Plus 35 means it has become an A P in our foot whose first term is 16 plus whose
03:14The common difference is 35
03:1716 plus 35 into N-1 means what will be the number of terms in this AP N-1
03:26We are applying the formula of A P
03:28simply A plus N-1 into D is equal to S A P's final term or even better
03:40Even better, first we'll find that 16 plus N number of 35 is equal to 499. Now this isn't necessary.
03:51Hope this is not the last time 499
03:53So we will see what comes exactly before 499. Now why are we choosing this 499?
03:59Why not 501 because we have something common in both right
04:03Now, the term which is above 499, if we reduce it by 500, then it will be only in this, hence we will lower it.
04:11Choose the limit, it is 499
04:13Now we will divide it into 35, this is 499 minus 15, that is, 493 483 is 35
04:24divide by
04:26483 divided by 35 means if 483 is divided by 35 then it becomes 35
04:3813, 133, 35 3 za 105 means it has come 0 o, 33 za 5 went 28
04:51That means lava of 16 will be 13 times i.e. 1 has become 16 and its lava
04:58One time it has become 13 times, that is, total times this intersection has also happened in our
05:0514 Times in Par
05:06And what's the final term, what's the final term in our footer inside this, this 16 plus 35 into 13,
05:16Multiply 35 by 13.
05:34So we made a mistake in multiply, you will also see that multiply, so you can do it.
05:39I will give
05:3935 into 13, 5, 3, 15, 3, 3, 9, 1, 10 You forgot to put this into sign here
05:46We,
05:461, 5, 5, 1, 3, 3, 5, 5, 455 will be the last time, but 455 so we have to multiply it by minus 16
05:57It came on, it will take 16 more out which we had deducted earlier,
06:01So 455 plus 16, this simply equals 455, when we start from 0, 0, 35,
06:11By the type of 7,
06:12But there's a 16 at the beginning, 13 times 35, 13 times 35, plus 16, so we're over.
06:20The time has come,
06:21455 plus 16, that is 461, 471, 471. Now we have to see how much this is divisible by 3.
06:32Is,
06:33In the equation it is asked that, the number of elements in the entry section is also divisible by 3, then
06:40First of all,
06:41First time joi itki, this is not divisible by 3, what is the second time, 51, so first time ja 3,
06:493721, second time divisible by 3, what do we do now?
06:53Basically, if we take the sum of 35 and 3, then the sum of 35 and 3 will come to us as 105.
07:03That means it will be divisible after 105, that is, if we go by 35, then the 3rd time it will be divisible not by 4
07:13No time, and it will become divisible 5 times, how will that happen, because it is common
07:20It will be divisible, that is, not 6, not 7, but 8 will be divisible, not 9 or 10, but 11 will be divisible, 12 and
07:43Not 13, but 14 times divisible,
07:48How many divisible points did we have? The total term was 40, so 1, 2, 3, 4, 5.
07:57So, I came across that it is divisible by 3, 5, that is, an intersection also in terms of 5, which
08:04That will be divisible by 3.
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