00:00Moth him solve the system of equation using Gaussian elimination method
00:09Question number 4 is 2.6 and part 1
00:13Here is the start with Jordan method
00:17x y z equation
00:20variable x z
00:22and b all the answers are 0.5 minus 2
00:25then augmented matrix will go
00:27this is the fourth one
00:29which is 0.5 minus 2
00:31and the rest of the similarity is that
00:36here is the 3.0 and 1.1
00:38and the upper 0 is not
00:39so we can see that
00:42this is the second row
00:45which is the first row
00:47which is the first row
00:49which is the first row
00:50which is the first row
00:56we can see that
00:58this row
00:59then we can see this one
01:05so this
01:05and add up
01:07then
01:07then
01:08we can see this one
01:12this is the first row
01:14so this plus one, this minus one, this minus one
01:17Is that R2R3?
01:20No.
01:21It's not true.
01:21It's not true.
01:23Now, R3 is 3 R1 plus.
01:28This is R1 is 3 to multiply and R3 plus.
01:36So, one, three, three minus three plus.
01:40Minus one into three minus three two plus.
01:42Minus one, minus one into three,
01:44minus four.
01:45And here, minus two.
01:48Then, R2R2 plus.
01:51Twice of R3.
01:54R3R3 got twice.
02:01R3 got twice.
02:04This R3 is twice.
02:07R2R3 plus.
02:08Plus کر دیا.
02:09Now, R3R3 plus کرنا ہے.
02:12Toys of R2.
02:16R3R2
02:17R2R2
02:17Toys.
02:19Toys.
02:20Minus seven.
02:21Toys.
02:21Toys.
02:32Toys.
02:33Toys.
02:37Toys.
02:38Toys.
02:40Toys.
02:41So this minus three has been here.
02:45This one has been here.
02:46This minus four has been here.
02:50And this minus two has been here.
02:54Then we have R3 and R2 plus had been here.
02:57So this minus one has been cancelled.
02:59So minus eleven has been divided.
03:02Do we have some kind of stuff?
03:05Yes, here we have all zero.
03:09Now we will not do this.
03:10Now it is a different thing.
03:12It is a question of one.
03:13Y minus one.
03:15Z minus one is equal to zero.
03:17Then Y minus one.
03:18Z minus seven is equal to one.
03:20Z equal to one by eleven.
03:24Method remember.
03:25This method is called Goss elimination method.
03:29Jordan method is not done.
03:32Z value is one by eleven.
03:33This output is by the value.
03:37This minus seven by eleven is here.
03:39Seven by eleven.
03:40One will add up to eighteen by eleven.
03:43Now Y and Z.
03:46Here put the value.
03:48Then X value should be.
03:50Then both put the same.
03:52Take the same.
03:53Finally X, Y, Z.
03:54Our required solution.
03:57Now practice.
03:58So you'll need to be having a question about Jordan elimination method.
04:03Do you want to ask Jordan elimination method?
04:04For this Jure Report and LYBATE to be having a question in Jordan.
04:08What is it gonna give us to Jordan elimination method?
04:09It's the一个.
04:09Second.
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