00:00Question number 3, x squared plus x,
00:02first ROM is x plus 1, then x minus 2,
00:052x squared plus 3x minus 1, 3x, 3x minus 3,
00:09x squared plus 2x plus 3, 2x minus 1, 2x minus 1,
00:13equal to ax minus 12,
00:15and I'm saying that the value of the value is equal.
00:18Now, if you know the old kids,
00:19you know the basics of your old kids.
00:20Those who are new or the specials,
00:23I do something to suppose.
00:25Usually, I do something to suppose 0,
00:28but if I do something to suppose here,
00:29it's like a failure.
00:31So, I'm saying 0 and 1 are my hero.
00:34I'm not going to put 0,
00:35I'll put 1 squared plus 1,
00:381 plus 1,
00:401 minus 2,
00:42then here, 2 plus 3 minus 1,
00:463 plus 3,
00:473 plus 3 minus 3,
00:490, here, 1 plus 2 plus 3,
00:526, 2 minus 1,
00:531, now it's so easy,
00:55you can open it easily,
00:57and here, I don't know,
00:59because I've got 1,
00:59so, I'm going to save it on a minus 12,
01:01and when I open this determinant,
01:03then there will be 12 on the left,
01:04which is equal to a minus 12,
01:06and 12 plus 12,
01:07a equals to 24.
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