00:00projected along positive y axis in a magnetic field lying in a x-z plane the magnitude force
00:07on the electron will act along the answer of y axis mcq number 128 the magnitude flux through a
00:15loop of one meter cube in a 0.5 tera magnetic field is same as magnetic flux through a loop
00:27of 0.5 meter square in a magnetic field of this is mcq number 128 which is the answer is
00:36one tesla at 0
00:39degree then body of mass 10 kgs falling through a viscous medium and reach terminal velocity the net
00:47force on the body will be 0 newton cd saudi c physics involved in mcqs
01:06the value of temperature coefficient of conductor is 0 this indicate that with the rise in temperature
01:15resistance of conductor to remain same the part difference between two sound waves coming from
01:22coherent source of wavelength 50 centimeter at a point is 100 centimeter the superposition of that
01:29wave produced by loudness karegi na phir kaiten potential energy decrease in the process of
01:36releasing a straight spring when a diver of mass m is swimming at a trap that is below the sea
01:45level
01:46this is a big difference if the reference level is taken at sea level the gravitational potential energy
01:59of the force of mass imaging to rise in a constant force act on a body and displays it by
02:07distant delta
02:08In a time deltie the rate at which the force is doing work is
02:12So this is the answer CAF into deltie upon deltie
02:18So this is the answer
02:20In certain motion if angular displacement is kept constant
02:24Decreasing the radius will
02:26So answer will decrease linear displacement
02:29136 when force and displacement are in opposite direction
02:33Then the burden is set to be
02:36Now this is very technical
02:38When we go in opposite direction
02:41What should we do?
02:43Negative should we do?
02:45This answer will be negative
02:47137 in step transformer
02:50The secondary voltage is increased by a factor of 10
02:53The current in secondary coil will be
02:56The one tenth of primary current in transformer
03:00Okay
03:01Then 138 in step
03:33When the droplet reach terminal velocity acceleration of course zero
04:03Is zero between the two upper charge
04:04At an angle of 45 degree
04:06With x-axis velocity of body according to this graph
04:10Is
04:10To answer
04:11To answer
04:11Constant
04:14Then
04:16MCQs number 143
04:18Yes
04:20If
04:21If
04:21If
04:22If
04:22We
04:23If
04:23If
04:28I
04:31Think
05:00we need to take this
05:02so high two coherent forces are the option B
05:05then gas expand
05:07one meter cube
05:09constant pressure two pascal burden
05:11three or one
05:12difference two is two to the four
05:14jool answer
05:15MCQs number 146
05:18this is a big love
05:20MCQs
05:21frequency AC double inductive reactant
05:24will also be double
05:27force between
05:28two charge 28 newton
05:34vacuum
05:34or path
05:36paraffin wax
05:37permittivity 2.8
05:40so if 28
05:412.8
05:42divided
05:4210
05:43this is 148
05:47body moves
05:49along a semi conductor
05:52semi circular
05:53of 10 cm
05:55from one end of the diameter
05:57to the other
05:58the ratio of distance to displacement
06:00to bhai
06:01this is always fixed
06:02this is not a difference
06:03this is not a radius
06:04this is not a radius
06:04this is not a radius
06:05this is not a radius
06:06this is a semi circle
06:07distance or displacement
06:08where the ratio of distance to two
06:12between each
06:12there will also be ok
06:13how to simplify
06:13function c
06:14answer
06:15this can be
06:28the answer
06:30will also be
06:33If its speed is double, the new range will be.
06:35So, this is a 4-Hourer.
06:38After 150, let's see.
06:46Ball of mass M strike and rebound.
06:49It's same speed in the opposite direction.
06:52Taking the initial direction has a positive change in the momentum of ball.
06:57Minus 2 M V will be able to change.
07:06Here, point lies 3 meter from a positive 5 micro-coulomb charge and 4 meter from minus 3 micro-coulomb.
07:15The most appropriate direction of the net electric field at this point is directed.
07:21So, this option is away from plus 5 micro-coulomb charge.
07:31152 time.
07:33Increase in kinetic energy associated with decreased pressure of the fluid in a horizontal pipe is a consequence of the
07:40bandoloi.
07:42Then, 153 time.
07:44Then, 153 time.
07:44The electric field at a point due to point charge is 2,000 N per coulomb.
07:50And, if suppose a minus 4 coulomb charge is placed at that point, then the magnitude of electric field and
07:59electric force on it.
08:00So, if we have to do the same, then the number of electric field is 2,000 N per coulomb.
08:05And, if we have to do the same velocity of the bandoloi, then the electric field is 800 N.
08:13154 internal resistance reduce the terminal voltage because it causes power loss inside
08:21the battery any option b 155 angle format center of circle has a body moves from one
08:31point to another to angular displacement call it option a
08:39here 156 main during drilling of a metal surface the drill bit heats up this heat
08:47come from the to burden against friction ho jayega there 157 wave two Jules of work is
08:57done in moving two columns of charge from one point to the other in an electric field
09:03potential difference between the point one Jules per Coulomb ho jayega 158 main
09:12motion of transfer wave involve particle vibration particular perpendicular to wave propagation
09:19ho jayega laminar flow of fluid its adjacent layer slightly smoothly pass each other
09:25yani option sees kabhi ho jayega 160 walee me karen body moving circle half revolution in term of
09:32radian equal to half revolution to pi ho jayegi na full to pi ho jayegi na full to pi ho
09:40jayegi
09:55particle enter in the same magnitude with equal to pi ho jayegi na full to pi ho jayegi na full
10:08to pi ho jayegi
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