A woman with a mass of 45kg is standing on a scale in an elevator.The elevator accelerates upward with a constant acceleration of 1.2ms⁻².What is the woman's weight as measured by her in the elevator ?

Physics class 11th problem  First year physics problem  Gravitation problems

Transcript

00:00Question is, a woman with a mass of 45 kg is standing on a scale in an elevator.

00:13The elevator accelerates upward with a constant acceleration of 1.2 meter per second square.

00:22What is the woman's weight is measured by her in the elevator.

00:33First of all, we will make a data, the mass of woman is 45 kg and acceleration is given

00:501.2 meter per second square and the value of g is constant which is 9.8 meter per second

01:05square on the surface of earth.

01:08So we have to find apparent weight, R apparent weight.

01:27So apparent weight, so in solution, the apparent weight which is denoted by capital R is calculated

01:39by using formula m into g plus a when lift is accelerating in upward direction.

01:50So apparent weight will be obtained as mass is given as 45 into the value of g is 9.8 plus

02:02acceleration of elevator is given as 1.2 meter per second square.

02:09So apparent weight will be obtained as 45 into is 9.8 plus 1.2.

02:18So it will be 11.

02:22So 45 into 11, the apparent weight will be obtained as 495 newton.

02:32So this is our required answer.

02:36Means the woman's weight is measured by her in the elevator is 495 newton.

02:45So there, we can come up to approximately that space and then adjourn us live in a pair of

03:01order, in the elevator is 9.1 meter per second square.

03:03So I continue to work so on.