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What is the value of the gravitational acceleration at a distance of 1) earth's radius above the earth's surface 2) Twice earth's radius above the earth's surface
Physics with Akhtiar Ali Bullo
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4 months ago
Physics class 11th problem solution
First year physics problem solution
Gravitation problems solution
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00:00
Question says, what is the value of the gravitational acceleration at a distance of 1 Earth's radius
00:15
above the Earth's surface to twice Earth's radius above the Earth's surface?
00:24
So first of all, we will make a data is g on the surface of Earth is obtained as 9.8 meter per second squares.
00:44
In first condition, we have to find the value of the g Earth's radius above the Earth's surface.
00:54
So g dash is equal to what?
01:05
So take a suppose this is Earth and this is the radius of Earth.
01:17
So we have to find the value of g Earth's radius above the Earth's surface means from the surface
01:27
of Earth, we will move a distance equal to radius of Earth.
01:34
So here we will find g dash and this is Re.
01:46
So from the center of Earth, this distance will be equal to r dash which is equal to the twice
01:56
of the radius of the Earth and in second condition, we have to find the value of g twice Earth's
02:07
radius above the Earth's surface means double the value of the radius from the surface of
02:14
Earth's surface.
02:15
So here means it's 2r is from the center of Earth's surface.
02:26
So this value becomes r double dash which is equal to 3 Re.
02:46
So here we will find g double dash which is equal to what?
02:52
So r dash is obtained as 2 Re and in second condition we have to find g double dash.
03:07
So in this condition r double dash will be equal to 3 Re.
03:17
So for solution is on the surface of Earth, the value of g is means the formula of g is g
03:32
m e upon r square.
03:36
So this is equation number 1 above the surface of Earth, the value of g will be g dash is
03:43
equal to g into m e upon r dash square.
03:57
So g dash will be equal to g into m e upon r dash square as the value of r dash is 2 Re.
04:13
So 2 Re whole square.
04:19
So the value of g dash will be equal to g m e upon the square of 2 is 4.
04:27
The square of r is Re square.
04:32
So g dash will be equal to 1 upon force into g m e upon Re square is g m e upon Re square
04:48
is equal to g m e upon r dash is equal to g m e upon g m e upon g m e upon g m e upon g.
04:57
So this is our required condition or further we can simplify this as g dash is equal to 1
05:10
upon force into the value of g on the surface of Earth is 9.8 m per second square.
05:18
So g dash will be equal to g dash will be equal to 9.8 divided by 4.
05:27
So it will be 2.45 m per second square.
05:35
So this is our required condition.
05:39
Now we will find the value of g double dash means twice the radius from the Earth's surface.
05:55
So g double dash will be equal to g m e upon r double dash is equal to 3 Re.
06:14
So 3 Re whole square.
06:19
So g double dash will be equal to g m e upon the square of 3 is 9 and the square of Re is
06:30
Re square.
06:32
So g double dash will be equal to 1 upon 9 into g m e upon Re square is g m e upon Re square
06:51
is equal to g.
06:52
So g double dash will be equal to 1 upon 9 into g or further we can simplify this as g double
07:05
dash will be equal to 1 upon 9 into the value of g on the surface of Earth is 9.8 m per second
07:11
square.
07:12
So g double dash will be equal to g double dash will be equal to 9.8 divided by 9.8 divided
07:18
by 9 so it will be 1.088 m per second square.
07:28
So this is our required condition.
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