00:01The question is, a photon, an electron and a uranium nucleus all have the same wavelength.
00:11The one with the most energy, A is the photon, B is the electron, C is the uranium nucleus,
00:21D depends upon the wavelength and the properties of the particle.
00:29As according to de Broglie, lambda is equal to H upon P. As momentum is also calculated
00:42by the formula P is equal to under root 2m into E. Here E is kinetic energy. So, lambda
00:56will be equal to H upon under root 2m into E. So, squaring on both sides. So, lambda square
01:09is equal to H upon under root 2m into E whole square. So, lambda square will be equal to
01:22H square upon 2m into E. So, the formula of energy will be E is equal to H square upon
01:372m into lambda square. So, here energy is inversely proportional to the mass. As photon is lightest
01:52then electron and uranium nucleus. So, the correct option will be A, photon.
01:59Photo will move down.
02:01Photo will move down.
02:01public though.
Comments