00:05The temperature at which the speed of a sound in air becomes double of its value at 27 degrees
00:15C is A 54 degree C, B 327 degree centigrade, C 927 degree centigrade, D minus 123 degree
00:31C is the speed is calculated by using formula V is equal to under root gamma RT upon molecular
00:48mass or weight. The speed is directly proportional to the under root of temperature is T1 is
01:01given as 27 degree Celsius or centigrade. So, at this temperature the speed V1 is V. So, at
01:21the other temperatures which we have to find its speed V2 will become double. So, we have to find T2.
01:37First of all, we will convert T1 into Kelvin. So, T1 will be equal to 27 plus 273 Kelvin. So,
01:47it will be
01:50300 Kelvin as V1 upon V2 is equal to under root T1 upon under root T2 as V1 is obtained
02:08as V and V2 is
02:122V and T1 is obtained as 300 Kelvin divided by T2 which we have to find. As V will be
02:24get cancelled with V.
02:26To remove the square root, squaring on both sides. So, the square of 2 is 4 and under root will
02:39be get cancelled with the square.
02:40So, it will be 300 upon T2. Here T2 is dividing on the other side of equal it will multiply.
02:50So, this will be T2 upon 4 is equal to
02:54300. So, T2 will be equal to 300 into 4. So, T2 will be equal to 300 into 4. It
03:14will be 1200 Kelvin. Here option is not given in
03:20Kelvin. So, we will convert this into Centigrade. So, T2 will be equal to 1200 minus 273 degree Centigrade. So,
03:38T2 will be obtained as 1200 minus 273.
03:43It will be 927 degree Centigrade. So, this is our required temperature. So, the correct option will be C927 degree
03:58Centigrade.
03:59So, you need to continue thispassen. But, we will continue to release the highest. As always, we will mut nuestra
03:59…you get up that conversation instead of 10. So, it gives data…
04:01…eso–wrap toAlright Bayern. So, that makes sense. I'm not sure that to be...
04:01tie it…
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