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00:00Okay, this is a new example of a hollow metallic spare of radius of 5 cm is charged such that the potential on the surface is 10-molts, the potential is at the center of the spare.
00:20This is a hollow metallic spare of radius of 5 cm. The potential is at the surface of 10-molts. If it is 10-molts, then what will happen in the center?
00:37Now, which is a hollow spare? It is hollow.
00:41So, most people will solve this numerical way.
00:45How much is the formula?
00:47This is conceptual.
00:49When it is hollow spare, what will be the potential difference in the center?
00:54Zero.
00:55What will happen?
00:56Zero.
00:57This is not numerical. This is theoretical and conceptual.
01:01In order to increase the capacity of parallel plate condenser, one should introduce between a sheet of.
01:17We want to increase the capacity of parallel plate capacitor.
01:21What is the sheet?
01:23Myga's copper 10 is steel.
01:26The correct option is Myga.
01:29Why?
01:30Look here, copper 10 and steel are metals.
01:34Metal sheets are not made.
01:36The dielectric constant is non-metal.
01:39It can be rubber.
01:40It can be glass plate.
01:42It can be oil.
01:44What will happen here?
01:46The metal spare of 100 mm radius has charge of 9 into 10 minus 9 column.
01:52What is potential at its surface?
01:55The formula is V equal to KQ upon R.
01:58KQ value of 9 into 10 is 9.
02:00Q is 4 into 10 to the power minus 9.
02:04It is already given.
02:06Charging.
02:07And if it is 100 mm is 1 mm, then we will divide thousands.
02:11Now, if it is 10 to the power plus 9 minus 9, then we will die.
02:14What will be here?
02:17What will be here?
02:18Yes.
02:191 upon 10 is 0.1.
02:20And here is 4.
02:229 to 0.1 is divided by 90.
02:2490, 90, 40, 360 volt.
02:26Okay, kids?
02:27The next one is quantity minus del V upon del R.
02:32What is potential gradient?
02:35And one more important thing.
02:36We will get to work in bringing a unit positive charge from infinity to certain point keeping units in equilibrium is called.
02:45Absolute electric potential.
02:48Okay, let's go ahead.
02:50How many of us are doing it?
02:51Absolute potential at a point is burden per unit charge.
02:55When a test charge is moved from point at infinity to point under consideration.
03:02This is a good point.
03:03Absolute potential at a point is burden per unit charge.
03:08When a test charge moves from point at infinity to point under consideration.
03:13Latin is a point of point under consideration.
03:15This means this is an absolute potential.
03:20Well, I have first a theoretical path.
03:23I guess I have a great topic here.
03:25I think that this is how I know.
03:28the voltage formula q upon rb and k is equal to 1 upon 4 pi epsilon 0 q rb
03:42which we have to keep in mind that these results are very important
03:48electric field intensity due to infinite sheet of charge and electric field
03:52field of infinity between two opposite the charge in the numerical system
03:56theoretical empty use be asked the numerical
04:00thanks
04:03Delectrique strength of certain metal is 10 q power 6 volt per meter
04:08breakdown voltage to be applied across a 1 mm thick specimen is
04:12the pensa option needs to go breakdown voltage
04:16formula also dielectric constant multiplier
04:19The dielectric constant is 6V per meter
04:23Thickness is 1 mm
04:251 mm is 10 gear minus 3
04:2710 gear minus 3 is 10 gear minus 3
04:29So what is the answer?
04:3110 gear power is 3 voltage
04:33Two identical capacitors are connected
04:37First in series and then in parallel to same source
04:44Ratio of energy of system will be
04:47Capacitors are connected first in series and then in parallel to the same source
04:53Ratio of energy of system will be
04:55Capacitors in series and capacitors in parallel
05:00Thick hai?
05:06How many?
05:07Two
05:08Capacitors in series and parallel ratio
05:111 is to n square
05:132 is to
05:141 is to 2 square
05:161 is to 4
05:171 is to 4
05:18This will be our answer
05:19Now let's look at one thing
05:20What wording?
05:22First in series and parallel
05:25First in series and then parallel
05:271 is to n square
05:291 is to n square
05:312 is to n square
05:32co1 is to n square
05:333 is to n square
05:34و 2 right?
05:35όσme
05:361 equal to n square
05:371 is to n square
05:381 is to n square
05:41due to n square
05:411 is to n square
05:423 say
05:43If you choose n square
05:44How many?
05:45Everyone can handle all EE,2 is to n square
05:49Typo,2 to n square
05:501 is to n square
05:511 because does n square
05:52Tek estão sign voix
05:54density part one may charge in close in a spare charge in close in a spare part two
06:01may charge on a infinite sheets charge on a infinite sheet or a part a charge
06:09place between two opposite charge surface today possible guy was all a Gaussian
06:15launch can be used to find electric field in density or option a charge in
06:21close in a space pair will go say it charge on a infinite charge you say it or
06:26charge played between two opposite the charge surface this comes out all of
06:31above okay reach him security pass over made the total outward flux or any closed
06:39hypothetical surface call dash is equal to the total charge enclosed divided by
06:49epsilon not respective irrespective of the way in which the charge is just
06:57distributed
06:59of conscious surface
07:02column surface Gaussian surface Newton surface home surface to by close hypothetical
07:07surface کیا ہوتی ہے
07:08ڈووسی کا اور یہ بہت سے ان لوہی پورا ہے explain کیا وہ انہوں نے
07:13ٹھیک ہے ٹھیک ہے مہار اچھی امسے کی وجہ ہے
07:15three identical capacitor are connected
07:18first in series and then in parallel to the same source the ratio of energy of
07:26system will be
07:27and then in parallel to capital in series
07:35پہلے لکھا یا بعد نے پہلے لکھا ہے اس سے بہت فرق پڑھا ہے
07:37ورڈنگ سے
07:38سریز کی اگر ون ہوگی تو پیرلل کے اس سے این سکوائر ٹائم زیادہ ہوگی
07:45اور ہم یہ بھی کہا سکتے ہیں کیا پیرلل کیا پیرلل کیا پیرلل کیا پیرلل
07:49مین سریز سے این سکوائر ٹائم زیادہ ہوگی بات اکی لیکن ورڈنگ میں یہ دکھو کہ پہلے کس کا ذکر ہے
07:55سریز کا تو سریز کی پہلے آئے گی پیرلل بات میں
07:58اب کتنے کی پسٹر ہے نہیں یہاں تین ہے
08:01ٹھیک ہے چھے
08:02سو تین ہے
08:04تو اس کا آنسر ون اس ٹو تھری سکوائر یعنی ون اس ٹو
08:10ٹھیک ہے چھے
08:12when an insulated dielectric material is placed
08:16اس کی بات ہو رہی ہے insulated dielectric material
08:20is placed
08:21in an electric field
08:23it
08:24gets charge
08:26remain unchanged
08:27is polarized
08:29none of these
08:30تو کیا ہوتا ہے جب insulated dielectric material
08:33کو ہم پلیس کرتے ہیں electric field میں
08:35charge ہوتا ہے
08:36uncharged یا polarized
08:37اصل آنسر ہے
08:38polarized
08:39کہہیں voltage of capacitor is 60V
08:42then what will be the voltage of diamond
08:45is present as dielectric
08:48less than 60V
08:50more than 60V
08:52میں بار بار بتا رہا ہوں
08:54جب بھی dielectric constant آتا ہے
08:55force
08:56electric field in density
08:57and voltage
08:58کام ہو جاتا ہے
08:59ایک چیزہ جو بڑھتی ہے
09:00اور وہ ہے capacitor tense
09:02کہہ رہے ہیں
09:03flunk
09:04flux passing through
09:05an area
09:06does not depend upon
09:09change in close
09:10medium
09:11shape of hypothetical surface
09:14both ANC
09:15تو اس تک پریکٹ آنسر ہے
09:16shape of hypothetical surface
09:19flux passing through an area
09:21does not depend upon
09:22charge پہ تو کرتا ہے
09:23medium پہ بھی کرتا ہے
09:24shape of hypothetical surface پہ نہیں کرتا
09:27دیکھیں بڑھ اچھا question ہے
09:29when capacitors
09:30are combined in series
09:33quantity which remains constant is
09:36option میں energy
09:39potential difference
09:41intensity of electric field
09:43or charge
09:44so
09:45اس کا
09:46correct آنسر ہے بھائی
09:47charge
09:48charge ہمیشہ کیا رہے گا
09:50constant رہے گا
09:51جب ہم
09:52بات کس کی کر رہے ہیں
09:53capacities are combined in series
09:55the quantity which remains constant is
09:57چھوڑ اچھا ہے
09:58intensity of electric field
10:00option a
10:02degrees inversely has square of the distance
10:06increase directly has square
10:08increase rapidly by increase the distance
10:12decrease inversely with the distance
10:14decrease inversely with the distance
10:16so
10:17اس کا correct آنسر ہے
10:18decrease inversely has square of the distance
10:22کیوں بھائی
10:23electric field in density میں ہم کہتے ہیں
10:25inverse square law کی relation ہے
10:27e1 upon e2 کا ratio کیا ہوگا
10:30ulta ہوگا
10:31یعنی e1 اوپر ہے
10:32تو r1 اسکوائر نیچے ہوگا
10:34inverse square relation اسی کو کہتا ہے
10:36اور e2 نیچے
10:38تو r2 کا اسکوائر ہوگا
10:40very very important
10:41بہت سکت ایسا سال آجاتا ہے
10:42کہ وہ r2 r1 کی ویلیو دیکھے
10:44e1 اور e2 کا ratio آپ سے
10:46اوپر ہے
10:48جیسے کہ r1 آپ کو دیا ہے
10:503
10:52تو ہم 3 کا اسکوائل لے لیں گے
10:54r2 دیا ہے 4
10:564 کا اسکوائل لے لیں گے
10:58تو electric field in density کا
11:00ریشو کیا آجائے گا
11:014 کا اسکوائر 16
11:023 کا اسکوائر 9
11:04یعنی 16 upon 9
11:06ایسی ہر relation کو ہم
11:07inverse square law کیاتے ہیں
11:08جس میں opposite relation ہو
11:10square
11:11inverse بھی ہو
11:12square بھی
11:13پھر ہے
11:14particle carrying a charge
11:15of 10 qr
11:16minus 6
11:17start from rest
11:18in a uniform electric field
11:19of intensity
11:2050 volt
11:21per meter
11:22fine kinetic energy
11:23to acquire
11:24when it has
11:25moved by 1 meter
11:26to
11:28symbol
11:29سی بات ہے
11:30بھائی جب
11:31vi 0 ہوتا ہے
11:32kinetic energy
11:33ورڈن اپس میں
11:34equal ہوتا ہے
11:35kinetic energy
11:36ورڈن equal ہیں
11:37تو بھائی
11:38کافی آسان ہو گیا
11:39ورڈن ہوتا ہے
11:40force into displacement
11:41kinetic energy
11:42بھی یہی ہو جائے گا
11:43force into displacement
11:44آخر کار
11:46force کیا ہوتی ہے
11:47force ہوتی ہے
11:48charge into electric field
11:49in density
11:50charge دیا ہے
11:5110 ki power minus 6
11:52اور e دیا ہے 50
11:53multiply گیا
11:545 into 10 ki power minus 5
11:56یہ آگئی ہماری force
11:57force کو displacement
11:581 meter سے
11:59multiply گر دو
12:00answer آجائے گا
12:015 into 10 ki power minus 5
12:02there is an electric field
12:04e along x direction
12:06if the word done
12:07in moving a chart
12:090.1 column
12:10through a distance
12:112 meter
12:12along a line
12:13making an angle
12:1460 degree
12:15with the x axis
12:16is 6 0
12:17the value of e x
12:19یار
12:20یار
12:21دیکھو بات سنو
12:22وردن دیا ہے
12:24elective field in density
12:25db
12:26charge کتنا دیا ہے
12:270.1 column
12:29اور اور اور
12:30کیا دیا ہے
12:31distance
12:32جسے d is سے
12:33ظاہر کر سکتے ہیں
12:34کتنا دیا ہے
12:35میرا بھائیوں
12:362 meter
12:37اور theta
12:3860 degree
12:39میرے بنائے ہوئے
12:40اپنے فارمولوں میں سے
12:41ایک بڑا ہم فارمولا ہے
12:42w equal to e q d is
12:43e کی بات ہے
12:44cos theta
12:451000 اللہ لیلہ
12:47فارمولے بنایا ہمیں
12:48بچوں
12:49آپ لوگوں کے خطر
12:506e
12:510.1
12:52what is cos 60
12:532 اور 1 have cancel
12:540.1
12:554 to divide
12:56it
12:57آنسر
12:5860 newton
12:59meq
13:009.6 g
13:01stationery
13:02on a vertical
13:03electric field
13:041000 kilonewton
13:06per coulomb
13:07the number
13:08of fundamental
13:09quantum of charges
13:10carried by
13:11it is
13:12yes yes yes yes
13:13big soul
13:14What has been given?
13:169 points is gram
13:18on a vertical electric field
13:201000 kilo Newton per coulomb
13:22the number of fundamental quantum of charges carried by it is
13:25What is our 9.6?
13:28Our formula is used
13:30Q equal to MG upon M
13:32M is 9.6 is gram
13:34which is 1000 divided by G
13:36Yes, they gave me 10
13:38This is a 1000 kg of Newton
13:43Now, see, the cut and cut the cut and the cut and the cut and the cut.
13:46Zero has zero to cut.
13:48The brothers and sisters should be 3 and 3 should be 6.
13:52We will multiply this together.
13:5410 power 8 is minus 8.
13:569.6 into 10 power minus 8 is Q
14:00Now, number and charge is always needed.
14:02Q is divided by E.
14:04E is the charge of electron.
14:061.6 into 10 power minus 19.
14:09Final answer, what will happen to you?
14:116 will happen.
14:12The very important question is
14:14An electron is situated midway between two parallel plates 0.5 cm apart.
14:22One of the plates is maintained at a potential of 60 volts above the other.
14:31What is force on electron?
14:34Today, this formula is F equal to del V upon del S.
14:39How much del V is given?
14:4160.
14:42Del S is given.
14:435 into 10 power minus 30.
14:45And how is it?
14:460.5 cm.
14:4810 power minus 1 is equal to 0.5 to 5.
14:52And in cm, 10 power minus 2 is equal to 10 power minus 2.
14:56Overall, this will be 5 into 10 power minus 3.
14:59This will be minus 3.
15:00This will be plus 3.
15:01And with 0, it will be minus 3.
15:03Final answer will be 1.92 into 10 power minus 15 N.
15:08In this major calculation, there is no problem.
15:10Where it happens, then I will tell you the magical trick.
15:14This is easy.
15:15In this paper, find magnitude and direction of electric field that will counterbalance the gravitational fields on a proton.
15:24Let the field be E, E equal to mg.
15:26But here, there is no problem.
15:27This is the fixed value.
15:28When the electric field will counterbalance the gravitational field,
15:31So, remember, this is the fixed value.
15:33This is the fixed value.
15:34This is the fixed value.
15:35When the electric field will counterbalance the gravitational field,
15:42So, remember, that the force is always going to be 1.02 into 10 power minus 7 N.
15:49This result is going to be the same.
15:51I will remember that.
15:52By the way, in the electrostatic chapter,
15:54Why did MC curve differ?
15:56First of all, this is a linear chart.
15:59We will ask Q of E.
16:04How we ask Q of E.
16:05Spherical chart density formula is X Leonardo.
16:08As I said, they are either ness of area.
16:10I will ask Q of E.
16:14How we ask the value of K is K ?
16:164 pi Epsilon knot of Production Non ten power,
16:229 NM2.
16:24reluctant
16:25So, one of them is called dielectric constant and they know the people who don't know, the other name is specific inductive capacity.
16:32So, in the option, this can also be specific inductive capacity and IRB.
16:37In this way, we ask epsilon 0, 1 upon 36 pi into 10 to 9.
16:42We ask this value for 8.85 units.
16:45Look at the score of 10 to 10 minus 12.
16:47Here, coulomb Newton per meter square and Newton per meter square per coulomb square.
16:52And electric field intensity between infinite sheet of charges, e equal to sigma upon epsilon 0.
17:03And electric field intensity between two oppositely charge plates, e equal to sigma upon epsilon 0.
17:10Now, look, this has a theoretical answer.
17:12It doesn't have to be numerically.
17:14If we talk about infinite sheet of charges, we will use the formula.
17:19To oppositely charge plates, we will use the formula.
17:22In this way, linear charge density, spherical charge density and cubical surface charge density will be numerical.
17:28Spherical plate capacitor formula is 4 by epsilon 0.
17:35And parallel plate capacitor, c equal to epsilon 0, a upon b.
17:40This will be numerical.
17:41This will be numerical.
17:42This will be numerical.
17:43This will be numerical.
17:44Electric field lines.
17:45An electric field line is imaginary line drawn in an electric field such that direction of the target at any point represents the direction of electric field.
17:58At that point, the density, number of lines per unit area.
18:02Definition, 2-3 times.
18:04Represent strength of electric field.
18:07Actually, these are two properties.
18:09Electric lines of fields contract longitudinally or expand laterally.
18:15So, they will give it like this option.
18:18Electric lines of fields.
18:19Option A, contract longitude.
18:21B, expand that really.
18:23C, board.
18:24D, board.
18:25D, board.
18:26So, this answer is both A and B.
18:28This is the factors on which capacitor depends.
18:31This is very accurate.
18:33The capacitance of parallel plate capacitor depends upon.
18:37Option A, area of each plate.
18:39Option B, distance between the plates.
18:41Option C,
18:42D, board.
18:43This value.
18:44That means, medium between the plates.
18:47Let us know that what is the answer of all of them.
18:48The average of two capacities.
18:49C and C to me,
18:51C to me,
18:53Micro Farad.
18:54And C to me,
18:55Micro Farad.
18:56R in series across 90 volt DC supply.
19:00Calculated charges on C1,
19:03and C to,
19:05and the potential difference each.
19:07So, two capacities are.
19:08One or two.
19:09Okay.
19:10Voltage 90 volt is 3μF, 6μF
19:14Now, see, this question has come
19:16The original method is very long
19:18In an easy way, let's see the options
19:20One option is given
19:2210 and 30
19:2420 and 40
19:2670 and 20
19:2860 and 30
19:30It's fun
19:32When you get the answer without solving
19:34Let's listen
19:36Total volt is 90
19:38In this way, the answer should be 90
19:40So, option A and B
19:42So, option A and B
19:44C and D
19:46So, this can be 1
19:48The other thing, the capacitor is 3 and 6μF
19:503 and 6μF
19:52The ratio of 1 to 2
19:54So, option A and B
19:561 to 2
19:58Well, here is 1 to 2 ratio
20:00Here is 1 to 2 ratio
20:02Here is 1 to 2 ratio, but
20:0490 is not coming
20:06Who is this?
20:07This is our answer
20:08This is our answer
20:10So, next question
20:12What is the final question?
20:14Hollow metallic sphere
20:16Of radius 5 cm
20:18Is charged such death
20:20Potential on its surfaces 10 volt
20:22The potential at the center of sphere
20:26What is the center of sphere?
20:28So, people will sit in the middle of sphere
20:30In the middle of sphere
20:32But this is the concept of sphere
20:33Hollow metallic sphere
20:34Hollow metallic sphere
20:35If it is a potential at the center of sphere
20:36It will always be 0
20:38The potential at the center of sphere
20:40The potential at the center of sphere
20:41The potential at the center of sphere
20:42Now, let's see
20:43A very good one
20:44Now, let's see
20:45Let's see
20:47Electrostatic
20:48If the distance between two charged bodies is double
20:50And charge is also double
20:55The interaction force will be
20:58Tickur, charge double honne ka lab hai
21:00which relation is not correct
21:21which quantity can be measured in unit of joule per coulomb
21:42which is a good question about joule per coulomb
21:49two capacitors of 5 and 10 are connected in series
21:53the total capacitance is
21:56well in series
21:58what will happen
22:01which is not correct
22:16ampere equal to coulomb per second
22:20this is correct
22:22current formula is called charge upon t
22:29q equal to i t
22:31so i should be equal to q upon t
22:33first
22:34the statement is correct
22:36so i am wrong
22:38world equal to coulomb per second
22:40where is it?
22:41world is called burden upon charge
22:44joules per coulomb
22:46of course this statement is wrong
22:48ohm equal to 1
22:50world per ampere
22:52one coulomb equal to charge of
22:546.24
22:55or 6.25
22:56both are correct
22:57into 10
22:58power 18 electron
22:59what is it?
23:00what is it?
23:016.24
23:02or 6.25
23:03into 10
23:04power 18
23:05electron
23:06numerical
23:076.3
23:08all its
23:09this is the answer
23:10which option is wrong
23:12statement
23:13b
23:14what is it?
23:15what is it?
23:16world is equal to
23:17joules per coulomb
23:18coulomb per second
23:19not
23:20the big question was
23:21electric field intensity
23:22at a distance of
23:231 meter
23:24from a point of charge
23:27of 1 micro coulomb
23:29is
23:30this is the answer
23:31this is the answer
23:32electric field intensity
23:33at a distance of
23:341 meter
23:35from a point of charge
23:36of 1 micro coulomb
23:37is
23:38this option
23:391 upon 4
23:409 into 10
23:419 into 10
23:429 into 10
23:43power 3
23:44neutrons per coulomb
23:45so see
23:46this is a formula
23:47our electric field intensity
23:48this is the answer
23:49this is the answer
23:50is fixed
23:519 into 10
23:52power 9
23:53ok
23:54and how much charge
23:56how much is it?
23:57micropole
23:5810 to power
23:59minus 6
24:00radius
24:011 is
24:021 square 1
24:03this is plus
24:049
24:05minus 6
24:0610 to power 3
24:07correct answer
24:089 into 10
24:09power 3
24:10neutrons per coulomb
24:12this is the answer
24:13this is the answer
24:14this is the answer
24:15this is the answer
24:16this is the answer
24:17very important
24:18formula
24:19and this is the answer
24:20okay
24:21this is the answer
24:22very important
24:23total outward flux
24:25over any close hypothetical surface
24:30called dash
24:31is equal to total charge
24:33in close divided by E0
24:35irrespective of the way
24:37irrespective of the way
24:39in which the charge is distributed
24:41so what is the answer
24:42what is the answer
24:43column surface
24:44ohm surface
24:45newton surface
24:46friday surface
24:47surface
24:48surface
24:49less
24:50surface
24:51surface
24:52gaussian surface
24:53gaussian surface
24:54gauss law can be used to find electric field in death city
24:57option a
24:59charge
25:00in close and spare
25:02option b
25:04charge
25:05place between two oppositely charge plates
25:07option c
25:09charge of an infinite sheet
25:11d all of the above
25:13the answer
25:14all of the above
25:15charge in close and spare
25:16of the above
25:17charge plays between two oppositely charge surface
25:21bota
25:22or charge on an infinite sheet
25:24bota
25:25a
25:26piaara saval
25:27a level
25:29physics
25:30charges of plus two microcolumn
25:32and
25:33minus two microcolumn
25:35are situated
25:36at point between p and q respectively
25:39has shown
25:41x is midway between p and q
25:44and q
25:45will pull g x
25:46midway
25:47p plus two microcolumn
25:48and q minus two microcolumn
25:49and
25:50which of following correctly describes the electric field and the electric potential add
25:59point x
26:00electric
26:01up
26:02here option dm option a
26:04electric field towards q
26:06electric potential 0
26:08and
26:09this answer
26:10because
26:11higher to lower potential
26:12move
26:13is
26:14moving towards q
26:15and
26:16p
26:17and
26:18x
26:19between
26:20p and q
26:21electric potential
26:22is
26:230
26:24and
26:25other options
26:26are
26:27the correct answer is
26:28electric field moves towards q
26:29and electric potential is
26:310
26:32correct answer
26:33option
26:34the diagram showed two metal plates p and q between
26:37between
26:38which there is a potential difference of 700 volt
26:42plate q is earth
26:43plate q is earth
26:44plate q is earth
26:45and potential difference is 700
26:47is
26:48so
26:49diagram
26:50that
26:51is
26:52minus 700 volt
26:53it's not so volt
26:54is
26:55and
26:56distance
26:57between the plane
26:58is 5 mm
26:59and
27:00what is the magnitude and direction of the electric field at point
27:04and
27:05these are all the options
27:07so
27:08electric field
27:09one formula
27:10is
27:11force per unit chart
27:12and potential difference
27:13upon
27:14distance
27:15now
27:16millimeter
27:17so
27:18meter
27:19convert
27:205 into 10
27:21minus 3
27:223
27:232
27:2450
27:251.4
27:26into 10
27:275
27:28and
27:29high to
27:30low potential
27:31so
27:32direction
27:33from q to p
27:34option
27:35which is
27:36c
27:371.4
27:38into
27:3910
27:40per
27:41coulm
27:42from q
27:43towards
27:44b
27:45one
27:46electric field
27:47intensity
27:48unit
27:49per
27:50coulm
27:51correct answer
27:52option
27:53c
27:54electric field
27:55strength is defined
27:56as
27:57force
27:58per unit
27:59positive
28:00charge
28:01on a small test
28:02charge
28:03why
28:04is it necessary
28:05for the test
28:06charge to be small
28:07option
28:08a
28:09so
28:10that the test
28:11charge does not distort
28:12the electric field
28:13correct answer
28:14is
28:15this
28:16option
28:17so
28:18that the force on the test
28:19charge is small
28:20to be small
28:21correct answer
28:22so
28:23that the test
28:24charge does not create
28:25any force on
28:26nearby charges
28:27so
28:28that the
28:29coulm's law for
28:30point charges
28:31correct answer
28:32option
28:33then
28:34electric field
28:35strength is defined
28:36as
28:37force per unit
28:38positive charge on
28:39a small test
28:40tube
28:41why it is necessary
28:42for test charge
28:43to be small
28:44correct answer
28:45the test charge
28:46does not distort
28:47the electric field
28:48in a uniform
28:49electric field
28:50a charge of
28:51three
28:52coulm's
28:53experience of
28:55force of
28:56300 newton
28:57the potential difference
28:59between
29:00two points
29:01one centimeter apart
29:03along
29:04the electric lines of
29:06force will be
29:07force will be
29:08so
29:09potential difference
29:10is
29:11what is
29:12now
29:13what is
29:143 coulm's
29:15distance
29:16between
29:17charge is
29:181 centimeter
29:19force is
29:20300 newton
29:21and
29:23force
29:26multiplied by
29:27distance
29:28upon
29:29charge
29:30so
29:31how much force
29:32is
29:333000
29:34newton
29:35and
29:36land
29:37is
29:381 centimeter
29:3910
29:40power
29:41how much charge
29:42is
29:433
29:44minus
29:452
29:46and
29:472
29:480
29:4910
29:50answer
29:5110
29:52answer
29:5310
29:54walton
29:55answer
29:5610
29:57this character
29:58is
29:59friend
30:00and
30:01capacitors
30:02and
30:03capacitors
30:04can
30:05be
30:06asked
30:07to
30:08explain
30:09to
30:10the
30:11unit
30:12of
30:13electric
30:14intensity
30:15is
30:16Newton
30:17of
30:18conductance
30:19Okay, Henry's color doesn't have any color, so it's MHO.
30:22Capacitor depends upon density of wire, resistance of wire, thickness of wire, so this cancer is all of above.
30:29Two capacitors of Capacitor C1 and C2 are connected in parallel.
30:34Look at MMCQ.
30:36If a charge Q is given to assembly, it gets shit.
30:40It should happen.
30:42The ratio of the charge on capacitor C1 to the charge on capacitor C2 is given by.
30:48Is C1 upon 2? Is C2 upon C1? Is C1 square upon C2 square? Is C2 upon C1 square?
30:53The correct answer will be C2 upon C1.
30:58Two conductors of Capacitor, 1uF and 2uF are charged to 200V and 300V respectively.
31:06And then connected by wire.
31:08The final potential of connected system.
31:11V is equal to V1C1 plus V2C2 divided by C1 plus C2.
31:18V1 200 is C1 1 is C1 1.
31:22V2 2 is 300 and C2 2 is C2 2.
31:25300 go 2 multiplied by 600 plus 200 is 800.
31:29800 upon 3 is 266.
31:31Answer to C2.
31:32We are saying system of two conductors separated by air or any insulating material form.
31:40The problem is that system of two conductors which is separate by air or any insulating material form.
31:48In the option A, capacitor, dielectric, resistor, battery, cell.
31:54The correct answer is capacitor.
31:57Basically, capacitor is a device which is stored in energy.
32:03Capacitor is a unit of coulm per volt.
32:06Coulm per volt or ferret?
32:09How can be part of electric field looking at Google electric field
32:18E on inner sides of A.
32:20Parallel plate capacitor ?
32:24Electric field E on inner side of parallel plate capacitor ?
32:28Option A, B, C and D sufficient?
32:30The correct answer is option B
32:31Sigma upon epsilon not.
32:34in sigma upon the main capacitor topic is the other important or a spherical capacitor
32:44rota yoga ota s equal to 4 by epsilon not are or a parallel played capacitor
32:51Parallel Plate Capacitor C formula
32:55epsilon naught A upon D
32:57A upon D
33:01R
33:05radius of square
33:07epsilon R
33:09permittivity of any substance
33:13divided by relative permittivity
33:15capacitance of any substance
33:17divided by capacitance of air
33:20depend upon density of wire
33:22thickness of wire, resistance of wire
33:24all of the buff
33:25this answer is all of the buff
33:27because capacitance density of wire
33:29depends on thickness of wire
33:31and resistance of wire
33:32two conductors of capacitance
33:362 microfarad and 3 microfarad
33:392 microfarad
33:413 microfarad
33:42R charge to 300 volt
33:45and 200 volt respectively
33:46respectively when it comes to
33:48the first one is C1
33:49the second one is C2
33:50and V1 is V2
33:53V1 is 300 volt
33:55C1 is 2 microfarad
33:57V2 is 200 volt
33:58and C2 is 2 microfarad
34:00and then
34:02connected by wire
34:04the final potential of the connected system
34:07this formula
34:09this formula
34:10V1 is 2
34:11V1 C1
34:12plus C2
34:13V2 divided by C1
34:14plus C2
34:15V1 C1
34:17V1 C1
34:18V2
34:20C2
34:20C2
34:23V2
34:23C2
34:24C2
34:24V1 C2
34:28We must divide when the final answer will be 240.
34:33Two conductors of capacitor 1uF and 2uF are changed to 200V and 100V respectively.
34:47And then connected via wire, the final potential of connected system is.
34:54So V is equal to V1C1 plus C2V2 divided by V1 plus V2.
35:02C1 plus C2.
35:04Basically, in math there is a formatting mean.
35:07So there, there, there.
35:09We must not do anything.
35:10V1 is 200 and C1 is 1.
35:14You will multiply by 200.
35:17Plus.
35:19Yes.
35:20How much C2 would you like?
35:222 would you like.
35:24And V200 would you like.
35:29100 and 2 multiplied by 200.
35:32Look, this is V200 and C2 is 2.
35:37So V2C2 divided by C1 plus C2.
35:41I mean, 1 plus 2.
35:42400 upon 3.
35:45133.33.
35:47And this is our answer.
35:48It's a very good question.
35:49Look at this.
35:50You are asking the equivalent of capacitor.
35:54Now, this is 3uF.
35:563uF.
35:57Which is parallel?
35:58Parallel.
35:59When the capacitor is parallel, the capacitor will add up.
36:02And 3 plus 3 will add up.
36:04How much?
36:056 will add up.
36:06Now, let's see.
36:076 is a right and left.
36:10When the result is 6,
36:14Why?
36:15Because it's parallel.
36:17Now, let's see.
36:18Here is 6.
36:19Here is 6.
36:20Here is 6.
36:21Here is 3 and 3.
36:22Now, this is in series.
36:23It's identical.
36:24It's identical.
36:25It's identical.
36:26It's 6.
36:28So, this is 6.
36:29We divide this.
36:30We divide this.
36:31We divide this.
36:32We divide this.
36:33We divide this.
36:34The total number of capacitor.
36:35It's 3.
36:36So, it's 6.
36:37We divide this.
36:38Answer 2.
36:39And this is our answer.
36:41This is our answer.
36:42It's good.
36:43Two capacitors.
36:44C1.
36:456uF and 12uF
36:46are in series combination across a 180 volt supply and calculate the charges on C1 and C2 respectively.
36:55In this option D.A.
36:57So, God, use this.
36:59When it's in series,
37:00then the charges are the same.
37:02The same.
37:03The same option D is the same.
37:05So, the correct answer is option D.
37:08Now, let's see.
37:10Capacitant B is two types.
37:12Capacitant in series and Capacitant in parallel.
37:15In parallel, we say,
37:17C1 plus C2 plus C3.
37:20And the voltage is the same.
37:22V equal to V1 equal to V2 equal to V3.
37:25Capacitant in series.
37:27Reciprocal.
37:281 upon C equal to 1 upon C1 plus 1 upon C2 plus 1 upon C3.
37:33And the charge is the same.
37:34Q equal to Q1 equal to Q2 equal to Q3.
37:37Voltage V1 plus V2 plus V3.
37:40And the charge.
37:41In which case?
37:43Voltage V1 plus V2 plus V3.
37:46Parallel.
37:47The charge is Q1 plus Q2 plus Q3.
37:50So, if there is identical capacitance.
37:52So, identical.
37:53If we keep the same as 3 to 3,
37:55we keep the same as 3 in series.
37:57Or if we keep the same as 3 to 6 in parallel.
38:00If we keep the same as 3,
38:01then the series and the parallel ratio of the series.
38:06Are 1 to N squared.
38:07OK?
38:08If there are 3 capacitors, then the Capacitor in series will be value 1, then the Capacitor in parallel 3 square is 9 times.
38:20The big question is the separation between plates of parallel plate capacitor is D.
38:27And the area of each plate is A when a slab of material of dielectric constant K and thickness T is introduced between the plates its capacitor becomes.
38:50The correct answer is option C. E0A, D-T, 1-1 upon K.
38:57Because this is very important.
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