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EDUCATION
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00:00:00and class can link I will share you in Telegram.
00:00:03You can click on this link and then where the link goes,
00:00:09it will go, it will come.
00:00:12First of all, next class can homework.
00:00:19Today until it happened,
00:00:21it will be good to revise.
00:00:27If you have done it,
00:00:34if you have done it,
00:00:37if you haven't done it,
00:00:39please do it.
00:00:40Then you will ask ELP number 9,
00:00:431, 9, 10.
00:00:47Then you will ask ELP number 10,
00:00:522, 3, 4, 5.
00:00:566, 11, 12, 13, 13 and 14.
00:01:06Then you will ask exercise 1.
00:01:09Exercise 1,
00:01:11which you have done before,
00:01:13there are 4 questions.
00:01:1580 to 84.
00:01:16Then you will ask exercise 3.
00:01:19In exercise 3,
00:01:20there are very good questions.
00:01:22This is a good question.
00:01:24this question.
00:01:251, 2, 1, 2.
00:01:26It is a good question.
00:01:271, 2, 1, 2, 2, 1, 2, 3, 3, 4, 3,
00:01:311, 2, 2, 3, 1, 2, 3, 4, 3, 4, 3, 2, 3, 2, 3, 3, 2, 3, 4, 3.
00:01:33This is all you can do when you have a question, when you have a question, your confidence is high, then you can do it with exercise 2.
00:01:4239, 40, 42, 60, 61, 64, 65, 87, 89.
00:01:53If you do it with exercise 2, then you can do it with exercise 4.
00:02:00In exercise 4, you have to do it with exercise number 22, the number 30, the number 31.
00:02:08If you are making this fun, you think that the value of your spending is the amount of money.
00:02:23ред ред ред ред ред ред ред ред ред
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00:05:02And so with the big sharp light, you should all modomy increase in a very short part.
00:05:05So once again, one charge, you should have 0.1 mole.
00:05:09How much, 0min micromer ╨╜╨╛╤Зihow?
00:05:11And then you could try to plan before the output is 1000 to 6, ъ░Ья┐╜otti.
00:05:14You could be 50.9 instead.
00:05:15Now tell yourself what much.
00:05:16How much before the output is aso, which is the first one?
00:05:19Quite the point?
00:05:20The logic and the concept is very simple.
00:05:24Theopia is where low is instead instant.
00:05:26That here protecting the output doesn't work.
00:05:29Then you see the way.
00:05:30Whole everyone does.
00:05:32peque├▒a
00:05:34the
00:05:35good
00:05:36good
00:05:37if
00:05:39you
00:05:40you
00:05:41will
00:05:42you
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00:05:46answer
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00:05:50big
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00:05:56question
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00:06:01it is a mathematical term to measure effectiveness of a buffer, to measure effectiveness of a buffer.
00:06:30рдХрд┐рд╕реА рднреА buffer рдХрд╛, effectiveness рдирд╛ рдЕрдкрдиреЗ рдХрд╛, рдПрдХ mathematical concept рд╣реИ, buffer capacity, рд╕рд░реА рд╣реЛрддрд╛ рдХреНрдпрд╛ рд╣реИ, рд▓рд┐рдЦреЗрдЧрд╛ second point,
00:06:39it is the ratio of, number of moles of, SA рдФрд░ SB added, SA рдФрд░ SB added to pH change,
00:06:54to pH change, рдЕрдЧрд░ рдореИрдВ рдЗрд╕реЗ, рдПрдХ formula рдХреЗ рд╕рдХреНрдЯ рдореЗрдВ рд▓рд┐рдЦрдирд╛ рдЪрд╛рд╣реВрдВ, рддреЛ рдХреБрдЫ рдРрд╕реЗ рд▓рд┐рдЦреЛрдВрдЧрд╛ рдореЗрд░реЗ рдкреНрдпрд╛рд░реЗ рдмрдЪреНрдЪреЛрдВ,
00:07:01рдЬреЛ buffer capacity рд╣реИ, рдЬреЛ buffer capacity рд╣реИ, рдЗрд╕рдХрд╛ рдорддрд▓рдм рд╣реИ, рдХрд┐ рдЖрдкрдиреЗ рдХрд┐рддрдиреЗ SA рдпрд╛,
00:07:09SB рдХреЗ mole рдорд┐рд▓рд╛рдП, рдФрд░ рдЙрд╕рдореЗрдВ рд╕реЗ рдХрд┐рддрдирд╛ pH рдХрд╛ change рдЖрдпрд╛, рдЖрдк рдЙрди рджреЛрдиреЛрдВ рдХрд╛ ratio рдирд┐рдХрд╛рд▓ рджреЛ,
00:07:16рд╡реЛ рдЬреЛ ratio рд╣реИ, рдЙрд╕реЗ рд╣реА рдирд╛рдо рджрд┐рдпрд╛ рдЧрдпрд╛ buffer capacity, рдЙрд╕реЗ рд╣реА рдирд╛рдо рджрд┐рдпрд╛ рдЧрдпрд╛ buffer capacity, рдЕрдЧрд░ рдПрдХ рдмрдЪреНрдЪрд╛ numerically рд╕реЛрдЪреЗ, рддреЛ рдРрд╕реЗ рд╕реЛрдЪреЗ, рдХрд┐ рд╕рд░ рд╣рдореЗрдВ SA рдФрд░ SB рдХреЗ mole рдмрддрд╛рдПрдВрдЧреЗ, рд╡реЛ mole рдФрд░ pH рдХреЗ change рдХреЛ рд╣рдо divide рдХрд░ рджреЗрдВрдЧреЗ, рд╣рдореЗрдВ рдХреНрдпрд╛ рдорд┐рд▓ рдЬрд╛рдПрдЧрд╛ buffer, рдмрдЪреНрдЪреЛрдВ, рдПрдХ рдЫреЛрдЯрд╛ рд╕рд╛ common sense рдХрд╛ рд╕рд╡рд╛рд▓ рдкреЛрд╢рддрд╛ рд╣реВрдБ,
00:07:37pH change denominator рдореЗрдВ рд╣реИ рдХрд┐ numerator рдореЗрдВ, рддреЛ рдЕрдЧрд░ pH change рдХрдо рд╣реЛрдЧрд╛, рддреЛ buffer capacity, рдмреЛрд▓реЛ, рдпреЗ рджреЛрдиреЛрдВ directly рд╣реИ рдХрд┐ inversely, рдпрд╛рдирд┐ рдореИрдВ рдРрд╕рд╛ рднреА рдХрд╣ рд╕рдХрддрд╛ рд╣реВрдБ, рдХрд┐ buffer capacity рдЬрд╛рджрд╛, buffer capacity, рдпрд╛рдирд┐ pH рдореЗрдВ change, рддреЛ buffer рдЕрдЪреНрдЪрд╛ рдХреА рдмреБрд░рд╛, buffer рдЕрдЪреНрдЪрд╛, рддреЛ buffer action рдЬрд╛рджрд╛, рдмреЛрд▓реЛ рд╣рд╛рдпрд╛ рдирд╛,
00:08:00рддреЛ рдпрд╣рд╛рдВ рд╕реЗ рдПрдХ rule рдмрди рдЧрдпрд╛, рдПрдХ concept рдмрди рдЧрдпрд╛, concept рдпреЗ рдмрдирд╛, рдХрд┐ buffer capacity рдХрд┐рд╕реА рднреА solution рдХрд╛ рдЬрд┐рддрдирд╛ рдЬрд╛рджрд╛, рддреЛ buffer action рдЙрддрдирд╛ рдЬрд╛рджрд╛, рдФрд░ buffer action рд╣реЛрдЧрд╛ рдЬрд╛рджрд╛, рддреЛ рдмрддрд╛рдУ buffer рдЕрдЪреНрдЪрд╛ рдХреА рдмреБрд░рд╛, рдЕрдЪреНрдЪрд╛, рдмреЛрд▓реЛ, рдбрди, рдЕрдм рдЖрдк рдЬрдм рдмрдЬрд╛рд░ рдЬрд╛рддреЗ рдереЗ, рддреЛ pH range рднреА рдирд╣реАрдВ рдкреВрдЫрддреЗ рдереЗ,
00:08:26рд╕реАрдзреЗ рдХрд╣рддреЗ рддреЛ рднрд╛рдИрдпрд╛ buffer capacity рдмрддрд╛рдУ, рд╡реЛ рдХрд╣рддрд╛ рдерд╛ рдЗрд╕рдХреА 5, рдЗрд╕рдХреА 10, рдЗрд╕рдХреА 15, рдЬрд┐рд╕рдХреА buffer capacity рд╕рдмрд╕реЗ рдЬрд╝рд╛рджрд╛, рд╡реЛ buffer рд╕рдмрд╕реЗ, рдмреЛрд▓реЛ, рдбрди, рд╣рдордиреЗ рд╕реАрдЦрд╛ рдХреНрдпрд╛, рд╣рдордиреЗ рдпреЗ рд╕реАрдЦрд╛, рдХрд┐ buffer рд╣реИ рдХреНрдпрд╛, рд╣рдордиреЗ рдпреЗ рд╕реАрдЦрд╛, рдХрд┐ рдХреМрди рд╕рд╛ buffer рдЕрдЪреНрдЪрд╛ рд╣реИ, рдХреМрди рд╕рд╛ buffer, рдЙрд╕рдХреЛ рд╕рдордЭрдиреЗ рдХреЗ рджреЛ рдкреИрдорд╛рдиреЗ рд╣реИ, рдпрд╛ рддреЛ pH range рд╕реЗ рджреЗрдЦ я┐╜
00:08:56buffer capacity, рдЪрд▓реЗрдЧрд╛, рдПрдХ рд╕рд╡рд╛рд▓ рд▓рд┐рдЦ рд▓реЛ рдЬрд░рд╛, рддреЛ рдкреНрдпрд╛рд░реЗ рдмрдЪреНрдЪреЛрдВ, рдпрд╣рд╛рдВ рд╕реЗ рд╕рд┐рд▓рд╕рд▓рд╛ рд╕реБрд░реВ рд╣реЛрдиреЗ рд╡рд╛рд▓рд╛ рд╣реИ рд╕рд╡рд╛рд▓реЛрдВ рдХрд╛, рдФрд░ рдореИрдВрдиреЗ рдЖрддреЗ рд╣реА рдХрд╣рд╛ рд╣реИ, рдЖрдЬ рдХреА рдЬреЛ class рд╣реИ, as per I need equilibrium, the conclusion of all the class, рдЬрд┐рддрдирд╛ рднреА рддрдХ рдЖрдкрдиреЗ рдкрдврд╝рд╛ рд╣реИ, рдФрд░ рд╕рд╛рд░реЗ mix рд╕рд╡рд╛рд▓ рдЪрд▓рдиреЗ рд╡рд╛рд▓реЗ рд╣реИрдВ, рдЪрд▓реЗрдЧрд╛, рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ, рдЗрд╕реА topic рдХрд╛ рд╕я┐╜
00:09:26If two solution A and B are having buffer capacity of 10 and 20 respectively, then which buffer solution will be having maximum buffer capacity?
00:09:56Sorry, will be having maximum buffer action, which buffer solution will be having maximum buffer action?
00:10:05рдмрдЪреНрдЪреЛрдВ, buffer capacity рдЕрд▓рдЧ рдЪреАрдЬ рд╣реИ, buffer action рдЕрд▓рдЧ рдЪреАрдЬ рд╣реИ, рд╣рд╛рдБ рдпрд╣ рдмрд╛рдд рдЕрд▓рдЧ рд╣реИ рдХрд┐ buffer capacity рдЬреНрдпрд╛рджрд╛, рддреЛ buffer action рднреА, рдХреНрдпрд╛ рд╕рдм рдХреЛ buffer action рдХрд╛ рдорддрд▓рдм рдкрддрд╛ рд╣реИ?
00:10:19рдЬрдм рднреА buffer action рдмреЛрд▓рдирд╛ рд╣реЛрддрд╛ рдерд╛, рд╕рд░ рдмреЛрд▓рддреЗ рдереЗ buffer рдпрдд, рдХреНрдпрд╛ рдмреЛрд▓рддреЗ рдереЗ?
00:10:24рддреЛ рд╕рд╛рдпрдж, рдореИрдВрдиреЗ buffer action рдХреЛ рдПрдХ рдХреЛрдбрд╝ рд╡рд░реНрдб рдиреЗ рдмреЛрд▓рд╛ рдерд╛, рдЬрд┐рд╕рдХреЛ рдмреЛрд▓рд╛ рдерд╛, buffer рдпрдд рдмреЛрд▓реЛ рд╣рд╛рдБ рдпрд╛ рдирд╛, buffer capacity рдЬреНрдпрд╛рджрд╛, рдпрд╛рдирд┐ buffer рдореЗрдВ change рдирд╛ рд╣реЛрдиреЗ рджреЗрдирд╛, pH рдореЗрдВ change рдирд╛ рд╣реЛрдиреЗ рджреЗрдиреЗ рдХреА capacity рдЬреНрдпрд╛рджрд╛, рддреЛ buffer рдЕрдЪреНрдЫрд╛, рддреЛ buffer action,
00:10:40simple рддрд╛ рд╕рд╡рд╛рд▓, рдЕрдЧрд░ рдпрд╣ fact рдкрддрд╛ рд╣реИ, рддреЛ рдХреНрдпрд╛ рдмрди рдЬрд╛рдПрдЧрд╛? A solution рдХреА buffer capacity рдХрд┐рддрдиреА рд╣реИ? 10, B рдХреА рдХрд┐рддрдиреА рд╣реИ? 20, рдХреМрди рд╕рд╛ рдирдВрдмрд░ рдмрдбрд╝рд╛ рд╣реИ? 20, рддреЛ buffer capacity рдЬреНрдпрд╛рджрд╛, рддреЛ buffer action рдЬреНрдпрд╛рджрд╛, рддреЛ рдХреНрдпрд╛ answer рднреА рд╣реЛ рдЬрд╛рдПрдЧрд╛?
00:10:54рдЕрдм рд╕реЛрдЪреЛ, рдЕрдЧрд░ рдпрд╣реА рд╕рд╡рд╛рд▓, рдореИрдВ рдереЛрдбрд╝рд╛ рд╕рд╛ numerical рдЕрдВрджрд╛рдЬ рдореЗрдВ рд▓рд┐рдЦрддрд╛ рддреЛ рдХреБрдЫ рдРрд╕реЗ рднреА рд▓рд┐рдЦ рд╕рдХрддрд╛ рдерд╛, рд▓рд┐рдЦреЛ, рдпрд╣ рдЕрд╕рд╛рди рд╣реИ рднрдИ, рдЕрд░реЗ рдЕрд╕рд╛рди рд╣реИ рди, рджреЛ рдирдВрдмрд░ рд╣реИ рдХреМрди рд╕рд╛, рдХрд┐рд╕рдХреА рдЫрдорддрд╛ рдЬреНрдпрд╛рджрд╛, рд╕рд░ 20 рд╡рд╛рд▓реЗ рдХреА, рддреЛ рдХреМрди рдЕрдЪреНрдЫрд╛ buffer, рд╕рд░ 20 рд╡рд╛рд▓рд╛, рдХрд╣рд╛ buffer action рдЬреНрдпрд╛рджрд╛, 20 рд╡рд╛рд▓рд╛, рдЕрд░реЗ simple
00:11:24buffer capacity of a solution, if buffer capacity of a solution is 10, рдПрдХ solution рд╣реИ, рдЙрд╕рдХреА buffer capacity рдХрд┐рддрдиреА рд╣реИ, 10, then calculate, then calculate, pH change, then calculate, pH change, if, if 0.1 mole,
00:11:49of a, is added to the solution, is added to the solution, рд╕рднреА рдмрдЪреНрдЪрд╛ рд╕рд╡рд╛рд▓ рд╕рдордЭ рдЧрдпрд╛, рдПрдХ solution рд╣реИ, рдЙрд╕рдХреА buffer capacity, 10 рд╣реИ, рдФрд░ рд╕рд╡рд╛рд▓ рдореБрдЭреЗ рдХрд╣рддрд╛ рд╣реИ, рдХрд┐ рдмрддрд╛рдУ, рдЙрд╕рдореЗрдВ pH рдХрд╛ рдХрд┐рддрдирд╛ change рдЖрдПрдЧрд╛, рдЕрдЧрд░ рд╣рдордиреЗ, рдмреЛрд▓реЛ рдкреНрдпрд╛рд░реЗ рдмрдЪреНрдЪреЛрдВ, рдХрд┐рддрдирд╛ рдорд┐рд▓рд╛рдпрд╛ рд╣реИ, 0.1, рдЖрд╕рд╛рди рд╣реИ,
00:12:17рдлреЙрд░реНрдореЙрд▓реЗ рд╕реЗ рдХрд░рдирд╛ рдЪрд╛рд╣рддреЗ рд╣реИрдВ, рддреЛ рдлреЙрд░реНрдореЙрд▓реЗ рд╕реЗ рдХрд░реЗрдВ, рдирд╣реАрдВ рддреЛ рдлреАрд▓ рднреА рдЖрдкрдХреЗ рд╕рд╛рдордиреЗ рд╣реИ, рддреЛ рдЕрднреА рдореИрдВрдиреЗ рдЖрдкрдХреЛ buffer capacity рдХрд╛ formula рдХреНрдпрд╛ рдмрддрд╛рдпрд╛ рдерд╛,
00:12:24рдореЛрд▓реНрд╕ рдЖрдл рдРрд╕реЗ рдПрдбрд╝рд░ рдЕрдкрди рдкреА рдПрдЪ рдЪреЗрдВрдЧ, рдХреНрдпрд╛ рдореБрдЭреЗ buffer capacity рджреЗ рд░рдЦреА рд╣реИ, рдпрд╣ рд╕рд░реН, рдХреНрдпрд╛ рдореБрдЭреЗ рдореЛрд▓реНрд╕ рдЖрдл рдРрд╕реЗ рджреЗ рд░рдЦрд╛ рд╣реИ, рдпрд╣ рд╕рд░реН, рдХреНрдпрд╛ рд╣рдо рд╕реЗ pH рдЪреЗрдВрдЧ рдкреВрдЪрд╛ рд╣реИ, рдпрд╣ рд╕рд░реН,
00:12:38so what will be the pH change, рдЖрд░реЗ, simple рд╕реА рдмрд╛рдд рд╣реИ рдпрд╛рд░, 0.01, рдмрддрд╛рдУ рдпрд╣ change рд╣реИ, рдХрд┐ рдмрд╣реБрдд рдереЛрдбрд╝рд╛ change рд╣реИ, рдФрд░ рдРрд╕рд╛ buffer рдЬрд┐рд╕рдореЗрдВ рдЗрддрдирд╛ рдорд╛рдореБрд▓реА change рдЖ рд░рд╣рд╛ рд╣реИ, рд╕рд╛рдпрдж рдЙрд╕реЗ рдЕрдЪреНрдЫрд╛ buffer рдорд╛рдирд╛ рдЬрд╛рдПрдЧрд╛, рдХрд╣рд╛рдиреА рдХреЛ рд╕рдореЗрдЯрддреЗ рд╣реИрдВ, рдФрд░ рдзреЗрд░ рд╕рд╛рд░реЗ рд╕рд╡рд╛рд▓ рдХрд░рддреЗ рд╣реИрдВ, рдЪрд▓реЗрдЧрд╛,
00:12:55point number one, рдХреНрдпрд╛ рд╕рдмрдХреЛ buffer clear рд╣реИ, рдореИрдВ рдмреЛрд▓реВрдБрдЧрд╛, рдЖрдк рд╕реБрдирддреЗ рд░рд╣рд┐рдПрдЧрд╛, right, рдПрдХ рдРрд╕рд╛ solution, рдПрдХ рдРрд╕рд╛, рдЬрд┐рд╕рдореЗрдВ рдереЛрдбрд╝рд╛ рд╕рд╛, рдереЛрдбрд╝рд╛ рд╕рд╛, рднрд░ рднрд░ рдХреЗ, рд▓реЗрдХрд┐рди pH рдореЗрдВ рдХреЛрдИ рдЦрд╛рд╕ change, рдХреНрдпрд╛ рдпрд╣реА solution buffer рдХрд╣рд▓рд╛рдпрд╛, рдЕрдЧрд░ рдХреЛрдИ buffer рд╣реЛрдЧрд╛, рддреЛ buffer рдХрд╛ buffer action рд╣реЛрдЧрд╛,
00:13:15buffer action рдХрд╛ simple рд╕рд╛ рдорддрд▓рдм рд╣реИ, H plus рдХреЛ consume рдХрд░рдирд╛, O H рдХреЛ consume рдХрд░рдирд╛, рдлрд┐рд░ рд╕реЗ release рдирд╣реАрдВ рдХрд░рдирд╛, рдпрд╣реА рдХрд╣рд▓рд╛рддрд╛ рд╣реИ buffer action, рд╣рд░ buffer рдХрд╛ buffer action рд╣реЛрдЧрд╛,
00:13:27buffer action рдЬрд┐рддрдирд╛ рдЬреНрдпрд╛рджрд╛, buffer рдЙрддрдирд╛ рдЕрдЪреНрдЫрд╛, рдмреЛрд▓реВ рдЖрд╕рд╛рди рд╣реИ, рдХреНрдпрд╛ рд╣рдорд╛рд░реЗ рд╕рд╛рдордиреЗ рддреАрди рдкреНрд░рдХрд╛рд░ рдХреЗ buffer рдереЗ, рдПрдХ рдРрд╕рд╛ buffer рдерд╛, рдЬреЛ рдПрдХ рд╣реА substance рд╕реЗ рдмрдирд╛ рдерд╛, рдФрд░ рдПрдХ рдРрд╕рд╛ buffer рдерд╛, рдЬреЛ mixture рд╕реЗ рдмрдирд╛ рдерд╛,
00:13:45рдПрдХ рдерд╛, рдХреНрдпрд╛ рд╕рдмрдХреЛ рдпрд╛рдж рд╣реИ, рддреАрдиреЛрдВ рдХреА condition рдпрд╛рдж рд╣реИ, рдХреМрди рд╕рд╛ solution рд╣реИ, рдпрд╛рдж рд╣реИ, рддреАрдиреЛрдВ рдХрд╛ pH рдпрд╛рдж рд╣реИ, pH range рдпрд╛рдж рд╣реИ, рдЗрд╕ рдкреВрд░реА рдХрд╣рд╛рдиреА рдореЗрдВ рдмрд╕ рджреЛ рдмрд╛рдд рдпрд╛рдж рд░рдЦрдирд╛, рдЕрдЧрд░ рдХрднреА рдХреЛрдИ рд╕рд╡рд╛рд▓ рдЖрдПрдЧрд╛ рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ solution рдкрд╣рдЪрд╛рдирд╛, рдФрд░ рдЕрдЧрд░ reaction рд╣реЛрддреА рд╣реИ, рддреЛ reaction рдХрд░рд╛рдИрдП, рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ рдмрдирдиреЗ рд╡рд╛рд▓реЗ solution рдХрд╛
00:14:15рд╕реНрдЯреНрд░реЙрдВрдЧ рд╣реЛрдЧрд╛, рддрдм рддрдм reaction рдХрд░рд╛рдпрд╛ рдЬрд╛рдПрдЧрд╛, рд╢реБрд░реВ рдХрд░реЗрдВ рд╕рд┐рд▓рддрд▓рд╛ рд╕рд╡рд╛рд▓реЛрдВ рдХрд╛, рдкрд╣рд▓рд╛ рд╕рд╡рд╛рд▓, рдЕрдЪреНрдЫрд╛, рд╣рд░ рд╕рд╡рд╛рд▓ рдХреЛ рд╕реАрдЦрдиреЗ рдХреЛрд╢рд┐рд╕ рдХрд░рдирд╛, рд╕рд╛рд░реЗ рд╕рд╡рд╛рд▓ standard рд╣реИ, рдФрд░ рд╣реЛ рд╕рдХрд┐рди рд╕рд╡рд╛рд▓реЛрдВ рдХреЛ рджреБрдмрд╛рд░рд╛ рд▓рдЧрд╛рдирд╛ рдкрдбрд╝реЗ рддреЛ рд▓рдЧрд╛рдИрдПрдЧрд╛, рдЪрд▓реЗрдЧрд╛, рд▓рд┐рдЦрд┐рдПрдЧрд╛, рдкрд╣рд▓рд╛ рд╕рд╡рд╛рд▓, calculate the pH of, calculate the
00:14:45HcN solution, HcN solution, present with 10 рдХреА рдкрд╛рд╡рд░ рдорд╛рдЗрдирд╕ 3 рдореЛрд▓рд░, KcN solution, present with 10 рдХреА рдкрд╛рд╡рд░ рдорд╛рдЗрдирд╕ 3 рдореЛрд▓рд░, KcN solution, if Ka of HcN, is 10 рдХреА рдкрд╛рд╡рд░ рдорд╛рдЗрдирд╕ 6,
00:15:09HcN рдХрд╛ рд╣рдореЗрдВ рдХреЗ рджреЗ рд░рдЦрд╛ рд╣реИ, рдФрд░ рдЙрдиреНрд╣реЛрдВрдиреЗ рд╣рдорд╕реЗ solution рдХрд╛ pH рдкреВрдЪрд╛ рд╣реИ, рд░реБрдХреЛ, рдХреЛрдИ рднреА рд╕рд╡рд╛рд▓ рдЖрдПрдЧрд╛, рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ step рдХреНрдпрд╛ рд╕реЛрдЪреЗрдВрдЧреЗ, рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ solution рдХреЛ рдкрд╣ рд╣реИ, рдореБрдЭреЗ рдпреЗ method рдЖрдкрдХреЗ рджрд┐рдорд╛рдЧ рдореЗрдВ sit рдХрд░рдирд╛ рд╣реИ, рдирд╛ рдХреНрдпрд╛рди рд╕реЗ рдирд┐рдХрд▓рд╡рд╛рдирд╛ рд╕рд┐рдЦрд╛рдирд╛ рд╣реИ, рд╕рдордЭрд┐рдПрдЧрд╛, рдпреЗ chemistry рд╣реИ, рдФрд░ chemistry рдореЗрдВ рднреА рдЖрдИрд╡
00:15:39рдмрддрд╛рдУ, рдЖрдЬ reaction рд╣реЛрдЧреА рдХрд┐ рдирд╣реАрдВ рд╣реЛрдЧреА, рд╕рд┐рдВрдЧрд▓ рд╣реИ рдХрд┐ make sure, рддреЛ reaction рд╣реЛ рд╕рдХрддреА рд╣реИ рдХрд┐ рдирд╣реАрдВ рд╣реЛ рд╕рдХрддреА, reaction рдХреА condition рдмреЛрд▓реЛ, acid рд╣реЛрдирд╛, base рд╣реЛрдирд╛, рдпреЗ base рд╣реИ рдХрд┐ рдирд╣реАрдВ рд╣реИ, рддреЛ рдкрд╣рд▓реА condition рддреЛ fail рд╣реЛ рдЧрдИ, рдЕрдм рджреВрд╕рд░реА рдореЗрдВ рдЖрдУ, рдПрдХ рд╡рд░рдХрд░рд╛рдпрди рд╣реЛрдирд╛, рдордЧрд░ strong рдореЗрдВ рд╣реЛрдирд╛, рдФрд░ рд╕рд╛рде рдореЗрдВ рджреВрд╕рд░рд╛ рднреА strong рд╣реЛрдирд╛, рддреЛ strong рддреЛ рд╣реИ, рд▓реЗрдХрд┐рди рджреВ
00:16:09рдЬреЛ рд╣реИ, рдЬреЛ рд╣реЛрдирд╛ рд╣реИ рд╣реЛ рдЪреБрдХрд╛, рдЕрдм рдХреЛрдИ reaction рд╣реЛрдиреЗ рд╡рд╛рд▓реА, рдЕрдм рдмрддрд╛рдУ, рдпреЗ рдЬреЛ solution рд╣реИ, рдХреНрдпрд╛ рдпреЗ weak acid рд╣реИ, рдЕрдЪрд╛ рд░реБрдХреЛ, рдЖрдкрдиреЗ рдХрд┐рддрдиреЗ solution рдкрдврд╝реЗрдВ, рдпрд╛ рддреЛ рд╣реЛрдЧрд╛ single, рдпрд╛ рддреЛ рд╣реЛрдЧрд╛ mixture, рдпрд╛ рддреЛ рд╣реЛрдЧрд╛ mixture рдореЗрдВ рднреА, рдпрд╛ рддреЛ pure salt рд╣реЛрдЧрд╛, рдпрд╛ рддреЛ salt рдХреЗ рд╕рд╛рде рдХреБрдЫ рд╣реЛрдЧрд╛, рддреЛ рдХреБрдЫ рдерд╛, рддреЛ buffer рд╣реА рддреЛ рдмрдирд╛ рдерд╛,
00:16:39condition рд╣реИ, рдмреЛрд▓реЛ рдпреЗ buffer рд╣реИ рдХрд┐ рдирд╣реАрдВ рд╣реИ, рддреЛ рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ solution рдХреЛ рдкрд╣рдЪрд╛рдирд╛, рдЕрдм buffer рд╣реИ, рддреЛ рдЖрдк рд╕реЗ рдкреВрдЫрд╛ рдХреНрдпрд╛ рд╣реИ, рддреЛ formula рдХрд┐рд╕рдХрд╛ рд▓рдЧрд╛рдУрдЧреЗ, рд▓рдЧрд╛рдИрдП pH рдХрд╛ formula рдЖрдкрдХреЛ рджреЗрддрд╛ рд╣реЛ, 30 рд╕реЗ 40 seconds рд╕рднреА рдмрдЪреНрдЪреЗ solve рдХрд░реЗ, рдЖрдВрд╕рд░ рдмреЛрд▓рдирд╛ рдирд╣реАрдВ рд╣реИ, рдмрд╕ рд░реВрд▓ рд░рд╣реЗрдЧрд╛, рдкрд╣рд▓рд╛ рд╕рдмрд╕реЗ рд╕рд┐рдВрдкрд▓, рдХрд░рддреЗ рдЪрд▓рд┐рдП рдлрдЯрд╛-рдля┐╜
00:17:09рдореИрдВ рдХреНрдпрд╛ рдмреЛрд▓ рд░рд╣рд╛ рд╣реВрдБ, рд╕рдордЭ рдкрд╛рдП, рд╣рд░ buffer рдХреА рдЕрдкрдиреА pH range рд╣реЛрдЧреА, рдЬрд░рд╛ рдореБрдЭреЗ рдмрддрд╛рдУ, рдЗрд╕рдХрд╛ k рдХрд┐рддрдирд╛ рд╣реИ, 10 рдХреЗ рдкрд╛рд╡рд░, minus 6, рддреЛ рдЗрд╕рдХрд╛ pH range, pH range, pH range, 5 to 7, right, рдЪрд▓рд┐рдП, рд▓рдЧрд╛ рд▓рд┐рдпрд╛ formula, рд▓рдЧрд╛ рд▓рд┐рдпрд╛ formula, рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ pH рдХрд╛ formula, pH рдмрд░рд╛рдмрд░ pk plus log, concentration of conjugate iron, upon weak acid, рдмреЛрд▓реЛ рдбрди,
00:17:39рдХреНрдпрд╛ рд╣рдо pk рдирд┐рдХрд╛рд▓ рд╕рдХрддреЗ рд╣реИрдВ, pk рдпрд╛рдирд┐ рдХреА minus log of k, рд╕рд╛рд░реА value рдХреЛ рд░рдЦрд┐рдП, salt рдХрд░рд┐рдП, рдХрд┐рддрдирд╛ рдЖрдПрдЧрд╛, 6, рдЕрдм рдпрд╣рд╛рдБ рдЪрд▓рддреЗ рд╣реИрдВ, log, conjugate iron, рдореИрдВ рд╣рдореЗрд╢рд╛ рдХрд╣рддрд╛ рдерд╛, conjugate iron, рд╣рдореЗрд╢рд╛ strong рд╕реЗ рд╣реА рдЖрдПрдЧрд╛, conjugate iron, рд╣рдореЗрд╢рд╛ strong рд╕реЗ рд╣реА, рдЗрд╕ concept рдХреЛ рдореИрдВрдиреЗ salt рдореЗрдВ already рд╕рд┐рдЦрд╛ рджрд┐рдпрд╛,
00:17:59рдФрд░ рд╡рд╣рд╛рдБ рдореИрдВ рдХрд╣рддрд╛ рдерд╛, concentration рд╣рдореЗрд╢рд╛ рдЙрд╕ iron рдХреА рд▓рд┐рдЦреЗрдВрдЧреЗ, рдЬреЛ рдкрд╛рдиреА рдХреЛ рддреЛрдбрд╝реЗрдЧрд╛, рдЬреЛ рдкрд╛рдиреА рдХреЛ, рдЬреЛ рдкрд╛рдиреА рдХреЛ, рдореБрдЭреЗ рдмрддрд╛рдУ, рдХреНрдпрд╛ рдЖрдЬ рдпрд╣рд╛рдБ рдкреЗ strong рдпреЗ рд╣реИ, рдХреНрдпрд╛ рдпреЗ рдкрд╛рдиреА рдХреЛ рддреЛрдбрд╝реЗрдЧрд╛, рддреЛ рдХреНрдпрд╛ рдореБрдЭреЗ рдЗрд╕рдХреА concentration рд▓рд┐рдЦрдиреА рд╣реИ, рдЬреЛ salt рдХреА concentration рд╣реИ,
00:18:17рд╡рд╣реА cyanide рдХреА concentration рд╣реИ, рдХреНрдпреЛрдВрдХрд┐ KCN рдЬреЛ рдкрд╛рдиреА рдореЗрдВ рдЯреВрдЯреЗрдЧрд╛, рддреЛ K plus рдФрд░ CN minus рдмрдирд╛рдПрдЧрд╛, рдПрдХ рдЫреЛрдЯрд╛ рдмрдЪреНрдЪрд╛ рднреА рд╕рдордЭ рд╕рдХрддрд╛ рд╣реИ, рдПрдХ рдореБрд▓ рдЬрд╛рдПрдЧрд╛ рддреЛ рдПрдХ рдореБрд▓ рд╣реА, рддреЛ рдХрд┐рддрдирд╛ рд╣реИ рд╡реЛ, 10 рдХреА power minus 3, рддреЛ рд╡реЛ рдХрд┐рддрдирд╛ рд╣реЛрдЧрд╛, 10 рдХреА power minus 3, рдпрд╛рдирд┐ рдкреНрдпрд╛рд░реЗ рдмрдЪреНрдЪреЛрдВ рдпреЗ рдХрд┐рддрдирд╛, 10 рдХреА power minus 3, 10 рдХреА power minus 2, рдПрдХ рдПрдХ рд╕реНя┐╜
00:18:47рдкрд╛рдЗрди рдкрд░ рд╣реИ рдХрд┐ рдирд╣реАрдВ рд╣реИ, рдпреЗ passing mark рд╕реЗ pass рд╣реБрдЖ рд╣реИ, рдХреНрдпрд╛ рдЕрдЪреНрдЫреЗ рд╕реЗ pass рд╣реБрдЖ, рдЗрд╕рдХрд╛ pH range рдХреНрдпрд╛ 5 рддреЛ 7 рд╣реЛрдирд╛ рдерд╛, рдЬрд╛рджреВрдИ buffer рддреЛ рддрдм рд╣реЛрддрд╛, рдЬрдм рдЗрд╕рдХрд╛ pH 6 рд╣реЛрддрд╛, рдмреЛрд▓реЛ рдбрди, рдПрдХ рд╕рд╡рд╛рд▓ рдкреВрдЫрдиреЗ рдХрд╛ рдорди рдХрд░рд╛, рдкреВрдЫ рд▓реВрдБ, рдЬрд╛рджреВрдИ buffer рд╣реЛрдиреЗ рдХреА condition рдХреНрдпрд╛ рд╣реИ, рдЬреЛ concentration, рдЬрд╛рджреВрдИ buffer рд╣реЛрдиреЗ рдХрд╛ pH рдмрд░рд╛рдмрд░ рдк
00:19:17рдЬрдм рдЬрдм concentration рдЕрд▓рдЧ рд╣реЛрдЧрд╛, рддрдм рддрдм рд╡реЛ рдЬрд╛рджреВрдИ buffer рдирд╣реАрдВ рд╣реЛрдЧрд╛, рдмреЛрд▓реЛ рдбрди, рдмреЛрд▓реЛ рдбрди, рджреЗ рджреВрдБ рдЕрдЧрд▓рд╛ рд╕рд╡рд╛рд▓, рд▓реЗрдЦреЛ рдЬрдбрд╝рд╛, рдпреЗ рд╕рдм рдХреЛ clear рд╣реИ, рдЪрд▓рд┐рдП, рд╕рд╡рд╛рд▓ рдХрд░реЛрдЧреЗ рддреЛ рд╕реАрдЦреЛрдЧреЗ рдЬреЛ рд╕рд┐рдЦрд╛рдиреЗ рд╡рд╛рд▓рд╛ рд╣реЛ, right, please, formula рд▓рдЧрд╛рдирд╛ рд╣реИ, answer рдкрд╛рдирд╛ рд╣реИ, рдмрдврд╝реВрдБ рдЖрдЧреЗ, calculate, calculate the pH, calculate the pH of resultant solution, calculate the pH
00:19:47of resultant solution, which is formed, which is formed by mixing, which is formed by mixing 60 mg acetic acid, which is formed by mixing 60 mg acetic acid, and 20 mg NaOH,
00:20:10which is formed by mixing 60 mg acetic acid, and 20 mg NaOH, to prepare a solution of 10 liter, to prepare a solution of 10 liter, total volume рдХрд┐рддрдирд╛ рджрд┐рдпрд╛ рд╣реИ,
00:20:31if Ka of acetic acid is 1.8 into 10 рдХреА рдкрд╛рд╡рд░, minus 5, if Ka of acetic acid is 1.8 into 10 рдХреА рдкрд╛рд╡рд░, minus 5,
00:20:50рд░реБрдХреЛ, рд░реБрдХреЛ, рдХрд░ рд▓реЛрдЧреЗ, рдореИрдВ рд╕рдордп рджреВрдБрдЧрд╛, рдореБрдЭреЗ step number one, рдХреЛрдИ рднреА рд╕рд╡рд╛рд▓ рдЖрдПрдЧрд╛, reaction рд╣реЛрддреА рд╣реИ,
00:20:57рддреЛ reaction, рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ рдмрдирдиреЗ рд╡рд╛рд▓реЗ solution рдХрд╛ рдкрддрд╛, рд╕рд░ рдиреЗ reaction рдХреА рдорд╛рддреНрд░ рджреЛ рд╣реА condition рдмрддрд╛рдИ,
00:21:03рдЗрддрдиреА рдмрдбрд╝реА рдЖрдпреЛрдирд┐рдХ, рдЙрд╕рдореЗрдВ рдХреЗрд╡рд▓ рджреЛ condition, рдпреЗ рддреЛ рдпрд╛рдж рдХрд░ рд▓реЛ рдмреЗрдЯрд╛, рдЗрддрдиреА рдмрдбрд╝реА chemistry рдХреА рджреБрдирд┐рдпрд╛,
00:21:10рдорд╛рддреНрд░ рджреЛ condition рдореЗрдВ summarize рдХрд┐рдпрд╛ рд╣реИ, рд╡реЛ рддреЛ рдпрд╛рдж рдХрд░реЛ, рдпрд╛ рддреЛ acid base рд╣реЛрдирд╛,
00:21:14рдпрд╛ рддреЛ рдХреЛрдИ рд╡рд░рдХрд░ рдЖрдпрди рд╣реЛрдирд╛, рдЬреЛ рдХрд┐ strong рдореЗрдВ рд╣реЛрдирд╛, рдФрд░ рд╕рд╛рде рдореЗрдВ рдХреЛрдИ рджреВрд╕рд░ рднреА strong рд╣реЛрдирд╛,
00:21:19рдЪрд╛рд╣рд┐рдП, рдмреЛрд▓реЛ рджреЛрдиреЛрдВ acid base рд╣реИрдВ рдХреА рдирд╣реАрдВ рд╣реИ, reaction рд╣реЛрдЧреА рдХреА рдирд╣реАрдВ рд╣реЛрдЧреА,
00:21:24рдХрд░рд╛рдИрдП reaction рдмрдирдиреЗ рд╡рд╛рд▓реЗ solution рдХрд╛ рдкрддрд╛ рд▓рдЧрд╛рдИрдП,
00:21:28рд╕рдордп рджреЗрддрд╛ рд╣реВрдБ рдкреВрд░реЗ рдПрдХ рдорд┐рдирдЯ, рдЖрдЬ рдЖрдкрдХреЛ рдХрд░рдирд╛ рд╣реИ, рдЖрдкрдХреЛ рд╕реАрдЦрдирд╛ рд╣реИ,
00:21:49рдХреНрдпрд╛ рдмрд╛рдд рд╣реИ, answer рдЖ рдЪреБрдХрд╛ рд╣реИ, рдЖрдк рд╕рдм рдХреЗ рдмреАрдЪ рдореЗрдВ, рджреЛ рдмрдЪреНрдЪреЛрдВ рдХреЗ,
00:22:14рддреАрди, рдореИрдВ рддреЛ рдкреВрдЫ рднреА рдирд╡, answer рдХреНрдпрд╛ рдЖрдпрд╛ рд╣реИ, рдореИрдВ рддреЛ рдЪрд╛рд╣рддрд╛ рд╣реВрдБ рдкрд╣рд▓реЗ рдЖрдирд╛ рддреЛ рд╕реБрд░реВ рд╣реЛ, рд╕рд╣реА рддреЛ рд╣реЛрдИ рдЬрд╛рдПрдЧрд╛,
00:22:25рдЪрд▓рд┐рдП, step number one, рдХреНрдпрд╛ рд╕рдордиреЗ reaction рдХрд░рд╡рд╛ рд▓рд┐рдпрд╛, рдЪреЗрдХ рдХрд░рддреЗ, рдЬреЛ рдмрдЪреНрдЪрд╛ рдмрд┐рд▓рдХреБрд▓ рдирд╣реАрдВ рдХрд░ рдкрд╛рдпрд╛,
00:22:30рдкрд╣рд▓рд╛ рдХрджрдо рдмрдврд╝рд╛рдИрдП, рдкрд╣рд▓рд╛ рдХрджрдо рдмрдврд╝рд╛рдИрдП,
00:22:32C-S-C-O-H, рдкреНрд▓рд╕ N-A-O-H, рдмреЛрд▓реЛ рдХреНрдпрд╛ рдмрдиреЗрдЧрд╛, C-S-C-O-N-A, рдкреНрд▓рд╕ рдкрд╛рдиреА, рдмреЛрд▓реЛ рдбрди, рдореБрдЭреЗ рдмрддрд╛рдУ, рдЗрд╕рдХреЗ рдХрд┐рддрдиреЗ рдорд┐рд▓рд┐рдЧреНрд░рд╛рдо, рдФрд░ рдЗрд╕рдХреЗ рдХрд┐рддрдиреЗ, рддреЛ рдореИрдВ 20 рднреЗрдЬрд╝ рджреВ, 40 рдмрдЪреЗрдЧрд╛, 0 рдмрдЪреЗрдЧрд╛, рдХрд┐рддрдиреЗ рдмрдЪреНрдЪреЛрдВ рдиреЗ рдРрд╕рд╛ рдХрд┐рдпрд╛,
00:22:50рдХрд┐рд╕реЗ рдиреЗ рдХрд┐рдпрд╛ рд╣реЛрдЧрд╛, рдЕрд░реЗ рдХрд┐рдпрд╛ рд╣реЛрдЧрд╛, рдмрддрд╛рдУ рдЧрд░рдмрдб рдХреНрдпрд╛ рд╣реБрдЖ, Istoichiometry, рдореЛрд▓ рдмрддрд╛рддреА рд╣реИ, Istoichiometry weight рдирд╣реАрдВ рдмрддрд╛рддреА рд╣реИ, рдЖрдк рдХрднреА рднреА reaction weight рдореЗрдВ рдирд╣реАрдВ рдХрд░рд╛рддреЗ, weight рдореЗрдВ рдХрд░рд╛рддреЗ рдЗрддрдиреА рдмрдбрд╝реА chemistry рдХрд╛ рдЬрдиреНрдореА рдирд╣реАрдВ рд╣реЛрддрд╛, рдЕрд░реЗ рд╣рд╛рдпрд╛ рди, рдлрд┐рд░ рддреЛ рдХрд┐рддрдирд╛ рдЕрд╕рд╛рди рд╣реЛрддрд╛, 10 рдЧреНрд░рд╛рдо рд░рд┐рдпрдХреНрдЯрд░реНрди рдХрд╛, 10 рдЧреНрд░рд╛рдо рдЗрд╕
00:23:20ред
00:23:50Hello, one mole is 1 millimole, because I have a weight in gram.
00:23:57Mole is what is weight in gram.
00:24:00So if I write gram, then 10 to minus 3 is what I have.
00:24:05If I don't write, then I write simply 1 millimole.
00:24:08If I write a gram, then I write a gram.
00:24:11Then I write a gram.
00:24:13If I write a gram, then it is not a gram.
00:24:16Where the gram is 10 to minus 3, where the gram is 10 to minus 3,
00:24:20where the gram is 1 millimole.
00:24:20It's going to be.
00:24:21Now, I will tell you, I will tell you,
00:24:22I will tell you, how many of these are going to be?
00:24:23I will tell you, how many of these are going to be?
00:24:2820 by 40, how many will be?
00:24:30Half.
00:24:30Millimole.
00:24:31I will tell you.
00:24:32Now, start with questions.
00:24:34How many of these are going to be?
00:24:37And then, I will tell you.
00:24:39Then, I will tell you, 30-40 seconds, start with questions.
00:24:42I would like to ask you all questions.
00:24:44Because we have the last question to reach your questions.
00:24:45Which is interesting.
00:24:46What is the answering answer?
00:24:51Pretty answer?
00:25:00Check it out.
00:25:01I will tell you.
00:25:01It was not going to be.
00:25:01But it is not going to be.
00:25:02You know how many of these are going to be.
00:25:07this is not a good one.
00:25:09So,
00:25:10t equals 0
00:25:11is the number of millimoles
00:25:13and the number of millimoles
00:25:15are the number of millimoles.
00:25:17Let's go.
00:25:19If it's 0.5
00:25:21and it's 0.5
00:25:23will be done.
00:25:25So,
00:25:27how much will it be?
00:25:29Now,
00:25:31here,
00:25:33how much will it be?
00:25:35Rule for revise.
00:25:37Step number one.
00:25:39First of all,
00:25:41reaction.
00:25:43Reaction.
00:25:45As a SB
00:25:47salt.
00:25:49So,
00:25:51how much will it be?
00:25:53Now,
00:25:55it will be done.
00:25:57What's the same?
00:25:59This is what is called Acetic Acid, which is salt.
00:26:06What is called Acetic Buffer?
00:26:11So, what is the formula?
00:26:13What is the formula?
00:26:15What is the formula?
00:26:17Let's go.
00:26:18So, my children, I will put the formula in the formula.
00:26:20All right.
00:26:21So, my children, I will put the formula in the formula.
00:26:24A plus log.
00:26:25Concentration of conjugate upon weak.
00:26:29Bolo done.
00:26:30Koi mujhe pk solve karke bata saktahe?
00:26:33Banja kya?
00:26:34Mijn idhar solve karraho.
00:26:35So, pka is equal to minus log of 1.8 into 10 ke power minus 5.
00:26:41Chun-chun ke log yad karae thae.
00:26:43Kaya sabko log 1.8 yad hai?
00:26:450.26.
00:26:47So, 5 minus 0.26.
00:26:494.74.
00:26:50Bolo done.
00:26:51Kya mery pk ki value a gai?
00:26:54Pk kitna aya?
00:26:554.74 plus log.
00:26:57Ajao jarah.
00:26:58Conjugate iron ka concert bolo lenge.
00:27:00Conjugate iron.
00:27:01Strong say he.
00:27:03Conjugate iron.
00:27:04Strong say he.
00:27:06Ajao.
00:27:07Ajao.
00:27:08Ajao.
00:27:09Ajao.
00:27:10Ajao.
00:27:11Ajao.
00:27:12Ajao.
00:27:13Ajao.
00:27:14Ajao.
00:27:15Ajao.
00:27:16Ajao.
00:27:17Ajao.
00:27:18Ajao.
00:27:19Ajao.
00:27:20Ajao.
00:27:21Bola.
00:27:22Ajao.
00:27:23Ajao.
00:27:24concentration haa mili mol mili mol hai ki concentration aur mujhe yaha pere mili mol
00:27:30likhna concentration sir concentration ki jaghe mol bhi likha ja sakti mili mol bhi likha ja
00:27:38to aad me see the mili molik do koi samasya is kekit na 0.5 ye kitna 0.5 ye kitna 0.5 ye
00:27:46kitna 0.5 0.5 0.5 upon 0.5 1 log 1 ki value me see the link to ph bolo chale ga bolo
00:27:54yo ye buffer buffer hai ki jadui buffer kiya iska buffer action sabsa jadha hooga pakka
00:28:01aray bolo bhai dhe duun agla sawal thoda modify karu abo liko bolo any doubt nahi
00:28:09pahle donoh sawal mucze punch lo koi doubt ho hame door tuk jana bhi saanp cdv kheelna
00:28:13hai 4-4 saanp ayan ki kik sawal me hello koi doubt rule number one sabse pahle solution
00:28:21ko pahe hai chaliyye saab agla sawal aap sab ke samne hai agla sawal bolu bita
00:28:28if ka if ka if ka of hcn is 5 into 10 k power minus 5 minus 10 liko if ka of hcn is 5 into 10 k power minus 10
00:28:49then calculate then calculate the volume of calculate the volume of 5 molar casein required to be added
00:29:13the volume of 5 molar casein required to be added added to 10 ml of 2 molar hcn solution
00:29:29to 10 ml of 2 molar hcn solution abhi tak jitna likha usko pahdke batao
00:29:38yya single hacky mixture
00:29:39aap koji bhi sawal karo ge rule number one
00:29:43chalo chho─Сo
00:29:45jambi aap ko equilibrium рдкрдврд╝рд╛ рд░рд╣рд╛ рдерд╛ рддреЛ рдореИрдВ рд╣рдореЗрд╕реЗ рдПрдХ line рдХрд╣рддрд╛ рдерд╛ рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ reaction рдХреЛ рдЦреАрдВрдЪ рдХреА рдХреНрд░рд┐рдпрдо рдкрд░ рд▓рд╛рдирд╛ рдпрд╛рдж рд╣реИ given information
00:29:53рд╕реЗ compare рдХрд░рд╛рдирд╛ рд╡реЛ рдЧрд╛рдирд╛ рдлрд┐рд░ рд╕реЗ рдЧрд╛рдирд╛ рд╡реЛ рдПрдХ rule рдХрд╛ рд╡реЛ рдПрдХ рдордВрддреНрд░ рдерд╛ рдЬреЛ рдкреВрд░реА equilibrium рдХрд╛ рдерд╛ рдЪреАрдХ рдЙрд╕реА рдкреНрд░рдХрд╛рд░ рд╕реЗ рдЖрдпрдирд┐рдХ рдХрд╛ рдордВрддреНрд░ рд╣реИ рдХреНрдпрд╛ рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ
00:30:03solution рдХреЛ рдкрд╣ рд╣реИ рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ solution рдХреЛ рдкрд╣ рд╣реИ reaction рд╣реЛрддреА рд╣реИ рддреЛ reaction рдЖрдк рдореБрдЭреЗ рдмрддрд╛рдУ рдЬреЛ
00:30:10substance рд╣реИ single рд╣реИ рдХрд┐ mixture рддреЛ reaction рд╣реЛрдЧреА рдХрд┐ рдирд╣реАрдВ рд╣реЛрдЧреА рдХрд┐рддрдиреЗ рдмрдЪреНрдЪреЗ рдХрд╣рд░реЗ reaction рд╣реЛрдЧреА reaction рд╣реЛ рдирд╣реАрдВ
00:30:17condition рдмреЛрд▓реЛ рдПрдХ рдмрд╛рд░ рдпрд╛рдж рдХрд░реЛ рдирд╛ рдПрдХ рдмрд╛рд░ рдПрд╕реЗ рдирд╣реАрдВ acid base рд╣реЛ рдирд╛ acid рд╣реИ рд╣реИ рдХреНрдпрд╛ рдХреЛрдИ base рд╣реИ рддреЛ рдкрд╣рд▓реА condition
00:30:27cross рдЕрдм рджреВрд╕рд░реА рдореЗрдВ рдЖрдУ рдРрд╕реЗ рдирд╣реАрдВ рдЫреБрди рд▓реЛ рдПрдХ рдмрд╛рд░ рдПрдХ рдмрдврд░ рд╕реБрди рд▓реЛ рдХреЛрдИ worker рдЖрдпрди рд╣реЛ рдХреЛрдИ
00:30:34worka strong рдореЗрдВ рд╣реЛ рдХреЛ рдХреЛрдИ рдФрд░ рд╕рд╛рде рдореЗрдВ strong рднреА рд╣реЛ рдФрд░ рд╣рд╛рдпрд╛ рдирд╛ strong рдореЗрдВ рд╣реЛ
00:30:45strong рднреА рд╣реЛ strong рдореЗрдВ рд╣реЛ strong рднреА рд╣реЛ рдпрд╛ рджреЛ рдЧрдпрд╛ рдмрддрд╛рдУ reaction рд╣реЛрдЧреА рдХрд┐ рдирд╣реАрдВ рд╣реЛрдЧреА рдорддрд▓рдм рдкрдХрд╛-рдкрдХрд╛ рдпрд╛
00:30:53to maintain to maintain a constant to maintain
00:31:22a constant pH of 9
00:31:25to maintain a constant pH of 9
00:31:28рд░реБрдХреЛ, рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ рд╡рд╣рдо рддреЛрдбрд╝ рджреВрдБ, рдЖрдзреА рдЬрдирддрд╛ рдХреЛ рддреЛ рдпрд╣ рдирд╣реАрдВ рдкрддрд╛ рд╣реИ
00:31:31рдЙрдиреНрд╣реЗрдВ рд▓рдЧрддрд╛ рд╣реИ, acidic buffer рдХрд╛ pH рд╕рд╛рде рд╕реЗ рдХрдо рд╣реЛрдЧрд╛
00:31:34рдпрд╣ buffer рд╣реИ рдХрд┐ рдирд╣реАрдВ рд╣реИ
00:31:36acidic рд╣реИ рдХреЗ basic рд╣реИ
00:31:38рдЗрд╕рдХрд╛ pH рд╕рд╛рде рд╕реЗ рдХрдо рд╣реЛрдирд╛ рдЪреАрдП рдХреЛрдИ рдЬрд░реВрд░реА рд╣реИ
00:31:41рдЖрдкрдХреЗ рд╕рд╛рдордиреЗ рдореИрдВрдиреЗ рдХрд┐рддрдирд╛ pH рд▓реЗрдЦрд╛ рд╣реИ
00:31:43рддреЛ рдкрд╣рд▓реЗ рджрд┐рдорд╛рдЧ рд╕реЗ рд╡рд╣рдо рд╣рдЯрд╛ рджреЛ
00:31:45acidic salt рдХрд╛ solution, acidic рд╣реЛ рдХреЛрдИ рдЬрд░реВрд░реА
00:31:47acidic buffer рдХрд╛ solution, acidic рд╣реЛ рдХреЛрдИ рдЬрд░реВрд░реА
00:31:50рдЕрд▓реЗ рд╣рд▓реЛ, рдЖрдзреЗ AR рдпрд╣рд╛рдБ рдкрд░ рдЧрд▓рдд рд╣реЛ рдЬрд╛рдПрдВрдЧреЗ
00:31:54рдирд╛рдо acidic рд╣реИ, рд▓реЗрдХрд┐рди solution acidic рд╣реИ рдХреЛрдИ рдЬрд░реВрд░реА
00:31:56рд╕реБрд░реВ рд╣реЛ рдЬрд╛рдИрдП
00:31:57рд▓рдЧрд╛рдИрдП formula, рдкреВрд░рд╛ рд╕рдордп рд▓реАрдЬрд┐рдП
00:32:00рдХрд░рдХреЗ рдмрддрд╛рдИрдП
00:32:01рд╣реЛ рд╕рдХрддрд╛ рд╣реИ, рдмрди рдЬрд╛рдП
00:32:03рд╕рдорд╛рд▓ рдЕрдЧрд░
00:32:08force рдХреА рдмрд╛рддреЗ рдХрд░реЗрдЧрд╛ рддреЛ force рдХрд╛ formula рд▓рд┐рдЦреЛрдЧреЗ
00:32:10pH рдХреА рдмрд╛рддреЗ рдХрд░ рд░рд╣рд╛ рддреЛ pH рдХрд╛ formula рд▓рд┐рдЦреЛ
00:32:13рд▓рд┐рдЦреЛ, рдХрд┐рд╕реА рдмрдЪреНрдЪреЗ рдХрд╛ рдЕрдВрд╕рд░ рднреА рдЖ рдЪреБрдХрд╛ рд╣реИ
00:32:16рдмреЛрд▓реЗрдВрдЧреЗ
00:32:17рдЪрд▓реЛ, рдЬреЛ рдмрдЪреНрдЪреЗ рдирд╣реАрдВ рдХрд░ рдкрд╛рдП
00:32:31step number one, рдХреНрдпрд╛ рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ solution рдХреЛ рдкрд╣рдЪрд╛рдирд╛
00:32:34рдпреЗ buffer рд╣реИ рдХрд┐ рдирд╣реАрдВ рд╣реИ
00:32:36рдЪрд▓реЛ рд╕рд╛рдм, рдпреЗ рд╡рд╛рд▓рд╛ level рддреЛ cross рд╣реЛ рдЧрдпрд╛
00:32:38рдкрд╣рд▓рд╛ рд╕рд╛рдм, cross
00:32:40рд╕рдмрд╕реЗ рдкрд╣рд▓рд╛ рд╕рд╛рдм рддреЛ рдпрд╣реА рд╣реЛрддрд╛ рд╣реИ
00:32:41рдмрдЪреНрдЪрд╛ solution рдЧрд▓рдд рдирд╛ рдкрд╣рдЪрд╛рди рд▓реЗ
00:32:43рджреВрд╕рд░рд╛ рд╕рд╛рдм, рдЕрдм рд╕рд╡рд╛рд▓ рдХрд┐рд╕ рдХреА рдмрд╛рддреЗ рдХрд░ рд░рд╣рд╛ рд╣реИ
00:32:45volume, volume, рд▓реЗрдХрд┐рди рдХреБрдЫ pH рдмреЛрд▓рд╛ рд╣реИ рдХрд┐ рдирд╣реАрдВ рдмреЛрд▓рд╛
00:32:48рддреЛ buffer рдЖрддреА рд╣реИ рдЖрдкрдХреЛ pH рдХрд╛ formula рдпрд╛рдж рдЖрдПрдЧрд╛
00:32:50рдЖрдк рдмрддрд╛рдУ, pH рдХрд╛ formula рдпрд╛рдж рджреВрдЖ рдХрд┐ рдирд╣реАрдВ рдпрд╛рдж рджреВрдЖ
00:32:53рдмреЛрд▓реЛ, pH рдмрд░рд╛рдмрд░
00:32:55рдкреНрд▓рд╕ рд▓реЙрдЧ, concentration of conjugate
00:32:58upon conservative
00:33:00рдЕрдм рд░реБрдЦ рдЬрд╛рдУ, рдпрд╣рд╛рдБ рдореЛрд▓ рднреА рд▓реЗрдХ
00:33:02рдорд┐рд▓реА рдореЛрд▓ рднреА рд▓реЗрдХ
00:33:04рдЧреНрд░рд╛рдорд┐рдХ рдкреНрд░реЗрдВрдб рднреА рд▓реЗрдХ
00:33:06рдорд┐рд▓реА рдЧреНрд░рд╛рдорд┐рдХ рдкреНрд░реЗрдВрдб рднреА рд▓реЗрдХ
00:33:08рдЕрд░реЗ рдмреЛрд▓реЛ рдирдпрд╛, рджрд┐рдорд╛рдЧ рд▓рдЧрд╛рдУ
00:33:10рдЕрдЧрд░ рд╣рдо рдХреБрдЫ рднреА рд▓рд┐рдЦ рд╕рдХрддреЗ рд╣реИрдВ рддреЛ рд╕рд╡рд╛рд▓ рдореЗрдВ
00:33:12рдЬреЛ information given рд╣реИ
00:33:14information рдХреНрдпрд╛ volume рдФрд░ molarity рдХреА рд╣реИ
00:33:17рдмреЛрд▓реЛ рдирдпрд╛, рд╕реБрдиреЛ, рд╕реБрдиреЛ
00:33:19рдХреНрдпрд╛ рдореИрдВ рдпрд╣рд╛рдБ рд╕реАрдзреЗ рд╡реА рдХреИрд╕реЗ 2 molar рд▓рд┐рдЦ рджреВрдБ
00:33:21рдФрд░ рдХреНрдпрд╛ рдореИрдВ рдпрд╣рд╛рдБ 5 molar рд▓рд┐рдЦ рджреВрдБ
00:33:23рдЕрдм рджрд┐рдорд╛рдЧ рд▓рдЧрд╛рдУ, рдЕрдЧрд░ рдореИрдВ 5 molar рд▓рд┐рдЦ рджреВрдБрдЧрд╛
00:33:26рддреЛ рдЬреЛ рдЙрд╕рдиреЗ рдкреВрдЫрд╛ рд╣реИ рд╡реЛ рдЖрдПрдЧрд╛ рдХреИрд╕реЗ
00:33:28рдЬреЛ рдЙрд╕рдиреЗ рдкреВрдЫрд╛ рд╣реИ рд╡реЛ
00:33:30рддреЛ рд╕реАрдзреЗ рд▓рд┐рдЦ рджреВрдБрдЧрд╛ рдлрд┐рд░ рддреЛ рд╕рд╡рд╛рд▓реА рдирд╣реАрдВ рд╣реБрдЖ
00:33:33рдорддрд▓рдм рдореБрдЭреЗ рдХреБрдЫ рдпрд╣реАрдВ рдкреЗ рдЦреЗрд▓рдирд╛ рд╣реИ
00:33:35рд╣рд╛рдБ рдпрд╛ рдирд╛, рдХреНрдпрд╛ рдЙрд╕рдиреЗ рдореБрдЭреЗ рд╕реЗ рд╡реЙрд▓реНрдпреВрдо рдкреВрдЫрд╛ рд╣реИ
00:33:37рдорддрд▓рдм рдореБрдЭреЗ рдпрд╣рд╛рдБ рдХреБрдЫ рдРрд╕рд╛ рд▓рд┐рдЦрдирд╛ рд╣реИ
00:33:39рдХрд┐ рд╡реЙрд▓реНрдпреВрдо рдЖ рдЬрд╛рдП
00:33:40рдХреНрдпрд╛ рдЬрд╛рдП, рд░реБрдХреЛ рдЬрд░рд╛
00:33:42рдХреНрдпрд╛ рд╕рдмрдХреЛ рдореЙрд▓рд╛рдЗрдЯреА рдХрд╛ рдлреЙрд░реНрдорд▓рд╛ рдпрд╛рдж рд╣реИ
00:33:44рдмреЛрд▓реЛ M рдмрд░рд╛рдмрд░ N рдмрд╛рдИ V
00:33:47рддреЛ N рдмрд░рд╛рдмрд░ M рдЗрдВрдЯреЛ V
00:33:50рдХреНрдпрд╛ рдпрд╣рд╛рдБ рдореЙрд▓ рд▓рд┐рдЦрдиреЗ рдХреА рдкрд░реНрдореАрд╢рди рд╣реИ
00:33:52рдФрд░ рдЕрдЧрд░ рдореЙрд▓ рд▓рд┐рдЦрдиреЗ рдХреА рдкрд░реНрдореАрд╢рди рд╣реИ
00:33:54рддреЛ рдлрд┐рд░ рдореЙрд▓рд╛рдЗрдЯреА рдЗрдВрдЯреЛ рд╡реЙрд▓реНрдпреВрдо рд▓рд┐рдЦрдиреЗ рдХреА рднреА
00:33:56рдкрд░реНрдореАрд╢рди рд╣реИ
00:33:57рдлрд┐рд░ рд╕реЗ рдЯреНрд░рд╛рдИ рдХрд░реЛ
00:33:59рдореИрдВ рдЪрд╛рд╣рддрд╛ рд╣реВрдБ рдЖрдЬ рдЖрдк рд╕рд╡рд╛рд▓ рдХрд░реЗ
00:34:01рдЬрд┐рдирдХрд╛ рдЕрдВрд╕рд░ рдЖрдЧрдпрд╛ рдЕрдЪреНрдЫреА рдмрд╛рдд рд╣реИ
00:34:06I'm doing.
00:34:12I'm not saying that the 8 is correct or the 2 is correct.
00:34:15I'm saying that it's good, then the first is correct.
00:34:19What do you say? 12 is correct.
00:34:24What do you say?
00:34:26Now, this is how simple you play in this.
00:34:29Let me know how the formula is linked.
00:34:31Let me know this.
00:34:32This is where I know, this is where I know.
00:34:35рдиреА рдкрддрд╛ рдирд╣реАрдВ рд▓реЗрдХрд┐рди рдирд┐рдХрд╛рд▓рд╛ рдЬрд╛рдУ allerdings рдЬреЛ рдЬреЛ рдкрддрд╛ рд╣реИ рд▓рд┐рдЧрджреЛ
00:34:40рдЬреЛ рдЬреЛ рдирд╣реАрдВ рдкрддрд╛ рдХреЛрдЬ рдореЗрдВ рдирд┐рдХрд▓ рдкрдбрд╝реЛ рд╣реИ рд╣рд░реЗ рд╣рд▓реЛ рдЪрд▓рд┐рдП рд╕рд╛рдл рд╕рдордп рд╕рдорд╛рде рд╣реЛрддрд╛ рд╣реБрдЖ
00:34:46рдЕрдЧрд▓рд╛ рд╕рд╡рд╛рд▓ рдХрд░рдирд╛ рдЯрд╛рдЗрдо рд╕рдм рдЕрдЧрд▓рд╛ рдХрд░рдирд╛ рдЕрднреА рддреЛ рд╕рд╡рд╛рд▓ рд╢реБрд░реВрдм рднреА рдирд╣реАрдВ рд╡рдЧрд╛ рдЖ
00:34:50I'll go get some kind of work
00:34:51seeking a custom
00:34:53see you
00:34:53I'm gonna
00:34:54I'm gonna
00:34:55get some kind of
00:34:56P K
00:34:56I'm gonna
00:34:57get some kind of
00:34:58P K
00:34:58orally
00:34:59I'm gonna
00:34:59get some kind of
00:34:59P K
00:35:01minus
00:35:02minus
00:35:04log of
00:35:055 into 10
00:35:06power
00:35:07minus 10
00:35:0810 minus
00:35:08log 5
00:35:09log 5
00:35:10value 0 point
00:35:1110 minus
00:35:120 point 7
00:35:129 point
00:35:13Bolo done
00:35:14Kya me
00:35:15hapere 9
00:35:15licked u
00:35:16chalega
00:35:16yahali
00:35:17do
00:35:179.3
00:35:18chalega
00:35:19plus
00:35:19log
00:35:20bolo
00:35:20kya me
00:35:20hapere
00:35:21mullite
00:35:21into
00:35:21volume
00:35:22mullite
00:35:22into
00:35:23volume
00:35:23lego
00:35:23chalega
00:35:24aap
00:35:25bata
00:35:25ya
00:35:25jara
00:35:25mery
00:35:26piyare
00:35:26bach
00:35:26chau
00:35:26upar
00:35:27conjugate
00:35:27time
00:35:28kaha
00:35:28se
00:35:28aega
00:35:28sir
00:35:30dhohrata
00:35:30ho
00:35:30ye
00:35:30line
00:35:31ae
00:35:31concept
00:35:31kaha
00:35:32se
00:35:32aega
00:35:32strong
00:35:34pahechan
00:35:34kia
00:35:34kone
00:35:36hai
00:35:36strong
00:35:36kasi
00:35:38to
00:35:39pakka
00:35:39vahe
00:35:39wala
00:35:40mujhe
00:35:40concentration
00:35:40likna
00:35:41hai
00:35:41kitna
00:35:42liko
00:35:42five
00:35:42is
00:35:43ka
00:35:43volume
00:35:43pata
00:35:49five
00:35:50aar
00:35:52yaha
00:35:52pere
00:35:52sari
00:35:53values
00:35:53ko
00:35:53put
00:35:53karta
00:35:54ho
00:35:54aap
00:35:55ke
00:35:55saam
00:35:55nesol
00:35:55karta
00:35:56ho
00:35:56ni
00:35:56chalik
00:35:57not
00:35:57tern
00:35:57into
00:35:57two
00:35:57bolo
00:35:57done
00:35:58kya
00:35:59five
00:35:59two
00:35:59jah
00:35:59ho
00:35:59jayega
00:36:00two
00:36:01two
00:36:01jah
00:36:01v by
00:36:02four
00:36:03nine
00:36:03minus
00:36:03nine
00:36:04point
00:36:04three
00:36:04minus
00:36:06zero
00:36:06point
00:36:06bernabar
00:36:08log
00:36:08v by
00:36:09two
00:36:09abis
00:36:10ko
00:36:10kaysse
00:36:10solve
00:36:11kare
00:36:11ruko
00:36:12ruko
00:36:12log
00:36:13uther
00:36:13log
00:36:14uther
00:36:1520
00:36:16log
00:36:16bern
00:36:16bolo
00:36:18nine
00:36:18yaha
00:36:18yahi
00:36:19to
00:36:19m├йnye
00:36:19kaha
00:36:19tha
00:36:19sari
00:36:20concept
00:36:20aar
00:36:36two
00:36:37v by
00:36:38four
00:36:38chalega
00:36:39mali
00:36:40do
00:36:40v
00:36:41by
00:36:41four
00:36:41is
00:36:42equal
00:36:43to
00:36:4310
00:36:43kip
00:36:44power
00:36:44minus
00:36:44zero
00:36:45point
00:36:45three
00:36:45done
00:36:46kitn├л
00:36:47that one of the languages in the world is going to open the area for some part of this
00:36:50Laurel here to the house whatever you say again you need to play on the
00:36:53Frenkie power minus one into 10 power 0.7 I mean or any 5 into 10 power minus 1 done
00:37:00don't understand it yeah my Fikhi we need to take a power minus one just a
00:37:05character's 545-10 and then type it into 1x2 like a
00:37:12I am going to see the volume of the volume of the volume is many.
00:37:15Is 4 ml where is?
00:37:18Let's go.
00:37:19We have to understand.
00:37:20We have a simple calculation.
00:37:20One step.
00:37:21One step.
00:37:22My son.
00:37:244 people bring this.
00:37:26Is it going?
00:37:27Is it going?
00:37:28No, it's not going.
00:37:29Look, I have 3.
00:37:30I have gone.
00:37:31V is equal to 4 by 2.
00:37:33How will it be?
00:37:34That's right.
00:37:35It's 2 Newton's joules.
00:37:37Joule?
00:37:39Yes.
00:37:40foreign
00:37:46foreign
00:37:52foreign
00:37:58foreign
00:38:04foreign
00:38:08in it out follow follow follow follow follow follow follow follow follow follow follow follow
00:38:12please backslide at the top of our kill that they are a little little little chapter beta
00:38:17yes of a lead to my ego dicto same I am I am I am I am I am I am a legalita shall
00:38:30a glass of our calculate calculate the pH of calculate the pH of resulting
00:38:47solution calculate the pH of resultant solution which is obtained by mixing
00:38:570.02 mol of KCN with 0.01 mol of HCl to prepare a solution of 10 liter
00:39:25if K of HCN is if K of HCN is if K of HCN is if K of HCN is then calculate pH of the solution
00:39:47rule number one
00:39:54if you are lying out of your life and your work will be the first solution to
00:40:00I want to start the reaction or not today? How many kids will be saying?
00:40:05Concept, concept, concept.
00:40:08A workarine will be strong and will be strong and will be strong.
00:40:15Reaction will remain.
00:40:16Do the reaction.
00:40:20The answer has come.
00:40:22Why?
00:40:23Why?
00:40:30What you can't do, first of all, is the reaction to me?
00:40:34If it has come, then do it.
00:40:36Do it.
00:40:37Do it.
00:40:39Do it.
00:40:40Do it.
00:40:41Do it.
00:40:42Do it.
00:40:43Do it.
00:40:44Do it.
00:40:45Do it.
00:40:46Do it.
00:40:47Do it.
00:40:48Do it.
00:40:49Do it.
00:40:50Do it.
00:40:51Do it.
00:40:53Do it.
00:40:54Do it.
00:40:55Do it.
00:40:57Savant.
00:40:58He always knows.
00:41:03Do it too,
00:41:13yeah I'm a birthday girl I am a reaction of a time for what faster fraction of second
00:41:22me how I'm gonna be here I'm gonna be 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
00:41:34number one solution here reaction to reaction rule number three
00:41:39Yes, sir, yes, sir.
00:42:08I will look on
00:42:10I
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00:43:38I
00:43:40I
00:43:42I am
00:43:44I
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00:47:13alpha,
00:47:13bernabar under root kac.
00:47:15I write the wrong thing.
00:47:16What do I have done?
00:47:16What do I have done?
00:47:17K is 10 to power minus 6.
00:47:19Concentration is 2 into 10 to power minus 2.
00:47:21Go, say it's wrong.
00:47:27Bhol may not know.
00:47:28This is mole.
00:47:30Buffer has no difference.
00:47:32Here is the difference.
00:47:33There will be the mole.
00:47:34The mole will write the name here.
00:47:36Here will be the concentration.
00:47:37There will be the concentration.
00:47:38And concentration will be the volume.
00:47:40Divide will be the volume.
00:47:41Here will be the volume.
00:48:11I don't think I'm going to do it I don't think I'm going to do it I don't think I'm going to
00:48:30in the class of 11 years later the question is the one who does it?
00:48:35and the question is the total of 600 questions in the class and the question is the one who
00:48:42has answered question is the one who has answered question?
00:48:48what should be the concentration so concentration kiska nikala axion ka the mole but a volume
00:48:56mole kitna 0.02 or volume kitna hai thus so it comes out to into 10 ki power
00:49:06hiya na shall yeh saab yeh a chuka hai concentration or isko karengi sol to batayyeh
00:49:13kitna answer ayega 10 ki power minus 6 into 2 into 10 ki power minus 3 karloge sol
00:49:21me kar djeta hoon sol karne pyaayega 2 into 10 ki power minus 9 ab joh bachis ko nahi
00:49:28karpaate unke leye dekho kaisa karna hai dekhlo eek baar aray hum log force nikala dhe catch plus
00:49:32yahaan a chuka hai 2 into 10 ki power minus to 10 se multiply 10 se
00:49:38or 10 ki power minus 9 chalega to 10 to 20 upon 10 upar ya minus 10 right so
00:49:45to maize se dhe kehe dhu under root of 20 into 10 ki power minus 10 рдФрд░ рдЗрд╕рдХрд╛ under root
00:49:51loghe to bolu kitna aya ga hai hai hai hai hai hai hai hai hai hai hai hai hai hai hai hai hai hai hai hai
00:49:57рддреЛ concentration of h plus рдХрд┐рддрдирд╛ рдЖрдПрдЧрд╛ four point рдЪрд▓реЛ рдЫреЛрдбрд╝реЛ рд╕реЛрдЪрддреЗ рд╣реИрдВ into 10 ki
00:50:08a reference рдХрд╛ рд╕реЗ рд╣реЛрдЧрд╛
00:50:09рдпрд╣ рдХреНрдпреЛрдВ рдЙрд╕рдХреЛ рдХрд░реВрдВрдЧрд╛ рддреЛ рдирд╣реАрдВ рд╣реЛрдЧрд╛
00:50:23рдХрд┐ рдмреБрд▓реЗрдВрдЧреЗ answer рдХрд┐ рдЕрдВрдбрд░реВ рдмрддрд╛ рд░рд╣реЗ рд╣реЛ рдкреАрдПрдЪ рдмрддрд╛ рд░рд╣реЗ рд╣реЛ рдПрдХ рдмрдЪреНрдЪреЗ рдХрд╛ answer рд╣реИ four point four eight
00:50:36рдХрд┐ рд╡реЛ рдмрддрд╛ рд░рд╣реЗ рдЬрд┐рдирдХреЛ рдЕрдкрдиреЗ answer рдХрд╛ рдкрддрд╛ рдирд╣реАрдВ рд╣реИ рдЕрдЪреНрдЫрд╛ рдЖ рд░рд╣рд╛ рд╣реИ рдЕрднреА рдареАрдХ рд╣реИ рднрд╛рдИ рдЪрд▓реЛ рддреЛ рд╣рд╛рдБ
00:50:45рдХрд┐ рдЕрдм рд╣рдореЗрдВ рдЕрдВрдбрд░реВ рдЯреНрд╡рдВрдЯреА рд╕реЙрд▓ рдХрд░рдирд╛ рд░реБрдХреЛ рдЕрдЧрд░ 16 рд╣реЛрддрд╛ рддреЛ рдХрд┐рддрдирд╛ рд╣реЛрддрд╛ рдФрд░ рдкрдЪреНрдЪреАрд╕ рд╣реИ рдХрд┐ рдпрд╣ рд╕реЛрд▓реЗ рд╣реИ рдХрд┐ рдкрдЪреНрдЪреАрд╕ рд╣реИ рдХрд┐ рдмреАрд╕ рд╣реИ рддреЛ рдпрд╣ рд╣реИ рдмреАрдЪреЛ рдмреАрдЪ рддреЛ рдЖрдк рднреА рдЖ рдЬрд╛рдУ
00:50:57рдЕрдЧреНрдпрд╛рдБ рд╣реИ рд╕рдордЭрднрд╛ рд░рд╣реЗрдВ рдХреНрдпрд╛ рдФрд░ рдЬрдм рдЖрдк рдмреАрдЪреЛрдВ рднреА рдЪрд╛рд╣реЗрдВ рдХрд┐рддреНрд░рд╛ рд╣реИ рдЗрдВрдЧрд╛ 4.4 рд▓рд┐рдЦрдиреЗ рд╕рд╛ рдбрд░ рд▓рдЧрддрд╛ 4.4 рд▓рд┐рдЦреЗрдВ рд▓рд┐рдШ рд▓реЛ
00:51:08╨в╤Л led me to do citation By Alice in general and you should try to post it left
00:51:20to learn more about this.
00:51:23Right now it's the 5th
00:51:25you already think about each level means logical
00:51:29which things are concentrated by minus
00:51:34to equal to minus 5.
00:51:38do a Morgen a
00:51:45split or
00:51:554.5
00:51:56foreign
00:52:03foreign
00:52:08foreign
00:52:13foreign
00:52:18foreign
00:52:23foreign
00:52:38foreign
00:52:41foreign
00:52:47foreign
00:52:49foreign
00:52:53a
00:52:53рд╡реЛ рдФрд░рд┐рдпрдирд┐рдХ рдПрд╕рдж рдХреЗ рдирд╛рдо рд▓рд┐рдЦрддрд╛ рд╣реИ рд╢рд▓реА рд╕рд▓реАрдХ рдПрд╕рдб рдпреЗ рд╡реЛ рдПрд╕рдб рдореИрд▓реА рдХреЗ рдЖрдк рдкрд░рд┐рд╢рд╛рди рд╣реЛ рдЬрд╛рддреЗ рд╣реИрдВ рддрдВрд╕реЗрдкреНрдЯ рд╡рд╣реА рд╣реИ рдмрд╕ рдЙрд╕рдиреЗ рдирд╛рдо рдмрджрд▓ рджрд┐рдпрд╛ рддреЛ рдорд╛рд▓ рд▓реЗрдирд╛ рд╡реАрдХ рдПрд╕рдЯ рдорд╛рдирдирд╛ рд╣реИ рд╣реИ
00:53:03Hello, because you have 6, whatever you want to do, I have 6.
00:53:07I have 6.
00:53:08So, you can say something new name.
00:53:10It's not a simple concept.
00:53:11Let's write a question.
00:53:13Let's write a question.
00:53:14In the next question,
00:53:15there is a question.
00:53:17What is the difference between today?
00:53:19Cacian is 0.01
00:53:22and HCL is 0.02.
00:53:29Mole.
00:53:300.02 mole.
00:53:33This is a mole.
00:53:35This is a mole.
00:53:37Volume is 10 liters.
00:53:38And K of Cacian is 10-6.
00:53:41If I want to save you,
00:53:44Volume is 1 liters.
00:53:46I will give you a question.
00:53:48But I want to say,
00:53:51where there is concentration,
00:53:53where there is concentration,
00:53:55where there is concentration.
00:53:56In the buffer there is no difference.
00:53:58But in the other places,
00:54:00there is a difference.
00:54:05Step number one.
00:54:06First of all,
00:54:07the solution.
00:54:09I have noticed the solution.
00:54:10What is the reaction?
00:54:11What is the reaction?
00:54:12Yes sir.
00:54:13What is the one?
00:54:14It will be.
00:54:15If I have done this,
00:54:16I will cover it.
00:54:17One time,
00:54:18let us cover it.
00:54:19So,
00:54:20KCN plus HCL,
00:54:21HCl, when reaction becomes HCl, HCl plus KCl, right?
00:54:31T equals 0, KCN.
00:54:33How many more is this?
00:54:340.01, this is 0.02, this is 0.02, this is 0.01, this is 0.01, this is 0.01.
00:54:45The first thing is, if you have questions, if you have any questions, don't do any questions.
00:54:51The answer is not the answer, the answer is the synchronization.
00:54:55When you have a discussion, or you have seen it in the rhythm,
00:54:59which is not the same, so never do it, please.
00:55:02This is the school paper.
00:55:04You will have to learn a step, but if you are desynchronized,
00:55:08then you will have to learn the board.
00:55:10This is the most important problem.
00:55:12We have to keep the dependency here.
00:55:14Let's go.
00:55:15I am going to tell you, today is KCL.
00:55:18The rules are always saying that
00:55:20the first thing is the solution.
00:55:22There is a reaction.
00:55:24The reaction?
00:55:25The water, the SASB, the SASB.
00:55:28Let me tell you, today is the solution.
00:55:32Now ask yourself, who are these two?
00:55:34One is HCN, and one is HC.
00:55:37This is the weak acid or not?
00:55:39This is the strong acid or not?
00:55:41Sir said that whenever the weak acid comes,
00:55:44the strong will go.
00:55:47One thing is correct.
00:55:49This is the main case sheet.
00:55:50This is
00:56:01which you must force the consumer and you can filter out.
00:56:01I sensualize these two.
00:56:02Otherя┐╜я┐╜ theя┐╜я┐╜logic side cts.
00:56:04foreign
00:56:05okay
00:56:09okay
00:56:11okay
00:56:13hello
00:56:14mess
00:56:15I need a bottle
00:56:17I think
00:56:18I'm going to
00:56:20I'm going to
00:56:21get a
00:56:25out of
00:56:27hello
00:56:28so
00:56:29I'm going to
00:56:33concentration nika lenge sabse pahle me concentration kis kanika luna aca the number of mole upon
00:56:40volume kittanyi ke power hey you to concentration ke mine a lekin humare slaves maja bhi bolha
00:56:47molyati himana lekin sir ph nika la hai ph me strong seki week say concept number one
00:56:54Jabhi strong aega normality socha jayega bujya concentration teya ki normality alexel can factor
00:57:02foreign
00:57:09foreign
00:57:14foreign
00:57:19foreign
00:57:24foreign
00:57:30I will give you a question, I will give you a question, I will give you a question and write a question.
00:57:39I will give you a question, write a question, calculate the pH, there will be no answer.
00:57:45Calculate the pH of resultant solution which is obtained by mixing 200 ml of 0.01 mol.
00:58:14NH4OH with 200 ml of 0.01 mol.
00:58:39HCl solution, if Kb of NH4OH is 10 raised to the power minus 5.
00:58:57If Kb of ammonium hydroxide is 10 raised to the power minus 5.
00:59:02I will give you a question, I will give you a question, first of all, one component is more than one.
00:59:09Rule number one, if there is a reaction, if there is a reaction,
00:59:14condition, condition, condition, acid base,
00:59:16how do you know, acid base or not?
00:59:18So, reaction or not?
00:59:20Start, reaction, check,
00:59:22what will happen, what will happen,
00:59:23what will happen.
00:59:24What will happen,
00:59:25what will happen,
00:59:26what will happen,
00:59:27the question,
00:59:28what will happen,
00:59:29this question,
00:59:30you will give me a question.
00:59:31I don't know.
01:00:01So the answer will come, then the answer will go away.
01:00:05Think about it, think about it, think about it, think about it.
01:00:12First of all, the first solution, let's go.
01:00:15Step number one, all children will do it.
01:00:17I will not check the copy, I will not do it.
01:00:20If I want to learn two steps, three steps, when will it become?
01:00:23I will not know.
01:00:24All of you have a reaction?
01:00:26Tell me, what made it?
01:00:28NH4, CL.
01:00:29How easy are you?
01:00:31NH4, OH, PLUS, HCL.
01:00:34Same will be NH4, CL, PLUS, PANI.
01:00:38I will give you a question.
01:00:41I already had a mole, I had to give you a mole.
01:00:44Today I had a mole.
01:00:46First of all, I had to give you a mole.
01:00:48Because the molarity has no reaction.
01:00:50Hello?
01:00:51Who has to give you a mole?
01:00:53It will happen.
01:00:54It will happen.
01:00:55It will happen.
01:00:56But it will happen.
01:00:58No.
01:00:59No.
01:01:00Mole.
01:01:01No.
01:01:02Mole.
01:01:03Reaction.
01:01:04Next point.
01:01:05Mole.
01:01:06Mole.
01:01:07Mole.
01:01:08Mole.
01:01:10Mole.
01:01:18Mole.
01:01:23No.
01:01:24Mole.
01:01:25pluck.
01:01:26?"
01:01:27I will show you.
01:01:29Lol?
01:01:31Lol buradan is doctor.
01:01:33Anyway,
01:01:34I will show you.
01:01:37Ky Celsius.
01:01:382.
01:01:38We will also reveal two.
01:01:41How many millions to get in the middle?
01:01:44So,
01:01:45we have millions of millions of millions of millions of millions.
01:01:49So,
01:01:50will you start?
01:01:51Not yet.
01:01:52How much will it be?
01:01:53How much will it be?
01:01:54How much will it be?
01:01:55but we have zero to save it.
01:01:57You can't get it in the numerical
01:01:59but you don't have to get it.
01:02:01You can't get it.
01:02:03Now, you can tell me,
01:02:05how will it become?
01:02:07How will it become?
01:02:09How will it become?
01:02:11Now, tell me,
01:02:13the solution is who made it?
01:02:15Oh, you've been single.
01:02:17I felt like this mixture is
01:02:19but it's not the mixture.
01:02:21Now, which salt is?
01:02:23Weak, base, strong, acid.
01:02:27Rooko, Jara,
01:02:29рдХреНрдпрд╛ рдкрд╛рдиреА рдореЗрдВ salt рдмрди рдХреНрдпрд╛ рдЖрдпрд╛ рд╣реИ?
01:02:31рдХреНрдпрд╛ рдЙрд╕рдореЗрдВ рд╕реЗ рдПрдХ рд╡рд░реНрдХрд░ рдЖрдпрди рд╣реИ?
01:02:33рдХреЛрд╣рд░рд╛рдо рдордЪрд╛рдП,
01:02:35рдкрд╛рдиреА рдХреЗ рддреЛрдбрд╝рдХреЗ рдЬрд╛рдП,
01:02:37salt hydrolysis рдХрд╛ concept рд▓рдЧрд╛рдпрд╛,
01:02:39рдЕрд░реЗ, salt hydrolysis рдЖ рдЧрдпрд╛ рдЗрд╕рдореЗрдВ?
01:02:41Strong рднреА рдЖ рдЧрдпрд╛, weak рднреА рдЖ рдЧрдпрд╛, salt рднреА рдЖ рдЧрдпрд╛,
01:02:43рдЕрд░реЗ, рд╣рд╛рдБ рдпрд╛ рдирд╛,
01:02:45рдЙрд╕рдХрд╛ concept рд▓рдЧрд╛рдКрдВрдЧрд╛,
01:02:46рд╕реБрд░реВ рд╣реЛ рдЬрд╛рдУ,
01:02:47рдлрд┐рд░ рд╕рдордп рджреЗрддрд╛ рд╣реВрдБ рдЖрдкрдХреЛ.
01:02:49рдЕрдм salt рдХреМрди рд╕рд╛ рд╣реИ,
01:02:58рдЙрд╕рдХрд╛ pH рдХрд╛ formula рдпрд╛рдж рдХрд░реЛ,
01:03:00solution acidic рд╣реИ, basic рд╣реИ, рдпрд╣ рд╕реЛрдЪреЛ,
01:03:02рдФрд░ рдЕрдЧрд░ solution, рдПрдХ рдмрдЪреНрдЪреЗ рди рдореБрдЭреЗ answer рдмреЛрд▓рд╛,
01:03:05рдореИрдВрдиреЗ рд╕рд╛рдпрдж answer рд╕реБрдирддреЗ рд╣реА рдордирд╛ рдХрд░ рджрд┐рдпрд╛, рдХреНрдпреЛрдВ?
01:03:08рдХреНрдпреЛрдВрдХрд┐ рдореБрдЭреЗ рдкрддрд╛ рд╣реИ, salt рдЕрдЧрд░ acidic solution рд╣реИ,
01:03:11рддреЛ pH рдХрднреА рд╕рд╛рде рд╕реЗ рдЬрд╛рджрд╛ рд╣реЛ рд╣реА,
01:03:13рд╕рдордЭ рдкрд╛рдП рдмрдЪреНрдЪреЗ?
01:03:15рдмреЛрд▓рдирд╛ рдирд╣реАрдВ рд╣реИ, рд░реВрд▓ рднреВрд▓ рдЧрдП рдЖрдк?
01:03:29рдореИрдВрдиреЗ answer рдмреЛрд▓рдиреЗ рдХрд╛ рдЗрд╕рд▓рд┐рдП рдордирд╛ рдХрд┐рдпрд╛ рд╣реЛрддрд╛ рд╣реИ,
01:03:31рдХреНрдпреЛрдВрдХрд┐ рд╣рдорд╛рд░реЗ рдмрдЪреНрдЪреЗ рдРрд╕реЗ рд╣реЛрддреЗ рд╣реИрдВ,
01:03:32рд╡реЛ рдХрд╣рддреЗ рд╣реИрдВ рд╕рд░рд╛рди рд╕рд░рд╛рдВ, рдмрддрд╛рдУ рддрд░реАрдХреЗ рд╣рдо рдмрддрд╛рддреЗ рд╣реИрдВ,
01:03:35рдФрд░ рдЕрдЧрд░ рдХрднреА рдореИрдВ рдХрд╣ рджреВрдБ,
01:03:37рд╣рд╛рдБ answer 4.5 рд╕рднреА рд╕рдм рдХрд╛ рдЖ рдЬрд╛рддрд╛ рд╣реИ,
01:03:39рдХрд╣реАрдВ рд╕реЗ рднреА рдирд┐рдХрд╛рд▓ рд▓реЗрддреЗ рд╣реИрдВ,
01:03:41рдЙрд╕ рддреЛ рдЙрд▓реНрдЯрд╛ рдлреБрд▓реНрдЯрд╛ рдорд▓реНрдЯрд┐рдкреНрд▓рд╛рдИ рдХрд░рдХреЗ,
01:03:43рдЖрдИ рдЬрд╛рддрд╛ рд╣реИ,
01:03:45рд╕рд░ рдЖ рдЧрдпрд╛ рд╕рд░,
01:03:47рдЗрд╕рд▓рд┐рдП answer рдмреЛрд▓рдиреЗ рдХрд╛ рдирд┐рдпрдо рдирд╣реАрдВ рд╣реИ,
01:03:49рд╕реАрдЦреЛ рдирд╛ рдпрд╛рд░, рдЬрд▓рддрд┐рдпрд╛рдВ рдХрд░рд┐рдП, рдХреЛрдИ рджрд┐рдХрдд рдирд╣реАрдВ,
01:03:51рдордЧрд░ рд╕реАрдЦрдиреЗ рдХрд╛ рдЕрдкрдирд╛ рдордЬрд╛ рд╣реИ, рдЖрдИрдП,
01:03:53рдпрд╣рд╛рдВ рддрдХ рдкрд╣реБрдБрдЪ рдЧрдП, рд░реБрдХреЛ, рд░реБрдХреЛ, рд░реБрдХреЛ, рдЕрдм рдмрддрд╛рдУ, рдпрд╣ рд╕реЙрд▓реНрдЯ рд╣реИ рдХрд┐ рдирд╣реАрдВ рд╣реИ,
01:03:57рдЕрдм рд╕реЙрд▓реНрдЯ рдХреМрди рд╕рд╛ рд╣реИ,
01:03:59рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ рд╕реЙрд▓реНрдпреВрд╢рди рдХреЛ рдкрд╣ рд╣реИ,
01:04:01рдкрд╣рдЪрд╛рди рд▓рд┐рдпрд╛, рдЕрдм рдХреМрди рд╕рд╛ рд╕реЙрд▓реНрдЯ рд╣реИ,
01:04:03рд╕реНрдЯреНрд░реЙрдВрдЧ рдЖрд╕рд┐рдб рд╡реАрдЧ рдмреЗрд╕,
01:04:05рд▓рдЧрд╛рдУ рдХрдВрд╕реЗрдкреНрдЯ,
01:04:07рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ рд╕реЙрд▓реНрдЯ рд╣реИ,
01:04:09рд╕реБрд▓реНрдЯ рд╣реИ,
01:04:11рд╕реНрдЯреНрд░реЙрдВрд╢рди рдХрд╛ рдкрд╣рдЪрд╛ рд╕реЗ рдХрдо рд╕рд╛рде рд╕реЗ рдЬрд╛рджрд╛,
01:04:13рдкрд╣рдЪ рдХрд╛ рдлреЙрд░реНрдорд▓рд╛ рдпрд╛рдж рд╣реИ,
01:04:15рд╕реЗрд╡рди рдорд╛рдЗрдирд╕ рд╣рд╛рдл,
01:04:17рдкреА рдХреЗ рднреА,
01:04:19рдорд╛рдЗрдирд╕,
01:04:21рд╣рд╛рдл рд▓реЙрдХ рд╕реА, рдмреЛрд▓реЛ рдбрд╝рди,
01:04:23рд░реБрдЦ рдЬрд╛рдУ, рд░рд┐рд╡рд╛рдЗрд╕ рдХрд░рддреЗ рд╣реИрдВ,
01:04:25рдпрд╣ рдпрд╣ рдкреА рдирд╣реАрдВ рд╣реИ, рдмреА рд╣реИ,
01:04:27рдкреА рдЬреИрд╕реА рдХреЛрдИ рдЪреАрдЬ рдирд╣реАрдВ рд╣реИ, рдорд╛рд░рдХрд░ рдиреЗ рдзреЛрдХрд╛ рджрд┐рдпрд╛,
01:04:29рдЖрдпрд╛ рди, рдЪрд▓рд┐рдП,
01:04:31рдореБрдЭреЗ рдмрддрд╛рдУ, рд╕реЗрд╡рди рдорд╛рдЗрдирд╕ рд╣рд╛рдл,
01:04:33рдкреА рдХреЗ рднреА, рдореИрдирд╕ рд╣рд╛рдл рд▓реЙрдХ рд╕реА,
01:04:35рдХреНрдпрд╛ рдореБрдЭреЗ рд╕реЗрд╡рди рдкрддрд╛ рд╣реИ,
01:04:37рдХреНрдпрд╛ рдореИрдВ рдкреА рдХреЗ рднреА рдирд┐рдХрд╛рд▓ рд▓реВрдБрдЧрд╛,
01:04:39рд╕рдорд╕реНрдпрд╛ рдХреМрди рджреЗрдЧрд╛,
01:04:41рд╕реА рдХрд╛ рдорддрд▓рдм рдХрд╛рдВрд╕рди,
01:04:43рдЙрд╕ рдЖрдпрди рдХрд╛, рдЬреЛ рдкрд╛рдиреА рдХреЛ рддреЛрдб рд░рд╣рд╛ рд╣реИ,
01:04:46рдмреЛрд▓реЛ, рдбрди, рдЕрднреА рдмрддрд╛рдУ,
01:04:48рдХреНрдпрд╛ рд╡реЛ рдЖрдпрди рдпрд╣рд╛рдВ рд╕реЗ рдЖрдПрдЧрд╛,
01:04:50рдпрд╣ рдХрдВрд╕рдВрдЯреНрд░реЗрд╢рди рд╣реИ рдХрд┐ рдорд┐рд▓реА рдореМрд▓,
01:04:52рддреЛ рдореБрдЭреЗ рдХрдВрд╕рдВрдЯреНрд░реЗрд╢рди рдирд┐рдХрд╛рд▓рдирд╛,
01:04:54рд╕рдмрд╕реЗ рдмрдбрд╝рд╛ рд╕рд╛рдк рдпрд╣рд╛рдВ рдкреЗ,
01:04:56рдХреНрдпрд╛ рдХрдВрд╕рдВрдЯреНрд░реЗрд╢рди рдирд┐рдХрд╛рд▓ рд▓реЛрдЧреЗ,
01:04:58рдХрдВрд╕рдВрдЯреНрд░реЗрд╢рди рдХрд╛ рдлреЙрд░реНрдорд▓рд╛ рдмреЛрд▓реЛ,
01:05:00рдХрдВрд╕рдВрдЯреНрд░реЗрд╢рди рдХрд╛ рдлреЙрд░реНрдорд▓рд╛ рд▓рд┐рдЦ рд░рд╣рд╛ рд╣реИ,
01:05:03рдХрдВрд╕рдВрдЯреНрд░реЗрд╢рди рдирд┐рдХрд╛рд▓ рд░рд╣реЗ рд╣реИрдВ,
01:05:07рддреЛ рдореМрд▓ рдореЗрдВ рдЖрдкрдХрд╛ рд▓рд┐рдЦ рджреВрдБ,
01:05:09рдХрд┐рд╕рдХрд╛, рдХрд┐рддрдиреЗ рдореМрд▓ рд╣реИрдВ,
01:05:12рджреЛ, рд╡реЙрд▓реНрдпреВрдо рдХрд┐рддрдирд╛,
01:05:14рджрд╕ рд▓рд┐рдЦ рджреВрдБ,
01:05:15рдЕрд░реЗ рд╡реЛ рд╕рд╡рд╛рд▓ рджрд╕ рд╡рд╛рд▓рд╛ рдЦрддрдо рд╣реЛ рдЧрдпрд╛,
01:05:17you can buy a 200 plus 200-400-10 liter-wool-are sir
01:05:23with the previous question yes or no?
01:05:27Tell me, what volume was 400 ml?
01:05:301 min.
01:05:31This mole is a million, this is a million.
01:05:33And the million is not a million.
01:05:36I will say that 1,200 will take 1 by 2 into 10 to power minus 2.
01:05:42I will say that 0.5 into power minus 2.
01:05:44to go together to have the minus three and then the minus three to enter the
01:05:48the consultation I am asked to put formula with the salt.
01:05:52Oh sorry this is the same thing.
01:05:55Yeah, yeah, pH is equal to seven minus half.
01:05:58PKB's nusvalidic.com
01:06:00Let's do that.
01:06:02You can do that.
01:06:03Yeah.
01:06:04Yeah.
01:06:05Yeah.
01:06:06Yeah.
01:06:07Yeah.
01:06:09Yeah.
01:06:10Yeah.
01:06:11Yeah.
01:06:12Yeah.
01:06:13Yeah.
01:06:142
01:06:163
01:06:183
01:06:243
01:06:284
01:06:32minus three is this clear?
01:06:34Come here now.
01:06:34Now tell us what the next thing is going to do here?
01:06:38Yes, or no?
01:06:39No.
01:06:39When we're locked, we're going to go.
01:06:43When we're locked, we're going to go.
01:06:46Next, we're going to go.
01:06:46I mean, all the lines are repeated.
01:06:49I'm going to repeat the same concept.
01:06:50We're going to do it.
01:06:51Solve.
01:06:527 minus 5 by 2.
01:06:542.5.
01:06:55So 4 point.
01:06:56I will not repeat again I will not repeat again I will not repeat again
01:07:09I will not repeat again minus half common Leah log into be so Catholic the log a plus log B
01:07:18Bolo done a block five key value below log five key value zero point seven zero
01:07:25log five key value zero point seven or ten key power minus three minus three
01:07:32yeh kitna hooga minus two point three minus minus plus two point three by two
01:07:39to four point five plus two point three by two 230 but a two one point one five
01:07:45KITNA ANSWER рдЖрдПрдЧрд╛ four point five plus one point one five and answer is five point
01:07:50Bolo done рдирд╣реАрдВ рд╕рдордЭреЗ рд▓реЗрдХрд░ рдордЬреЗ рдХреА рдмрд╛рдд рдмрддрд╛рдКрдВ рдХреНрдпрд╛ рдЕрднреА рддрдХ рд╡реЛ рдирд╛ рджрд┐рдпрд╛
01:07:57рдЬреЛ рдореИрдВ рджреЗрдиреЗ рд╡рд╛рд▓рд╛ рдерд╛ рджреЗрджреВрдВ рд╡реЛ рд╕рд╡рд╛рд▓ рдЕрднреА рддреЛ рдЖрдкрдиреЗ рдХреБрдЫ рдХрд┐рдпрд╛ рд╣реА рдирд╣реАрдВ рдпрд╛ рдЕрднреА рддреЛ
01:08:03рд╕рд╡рд╛рд▓ рдЖрдиреЗ рд╡рд╛рд▓рд╛ рд╣реИ рдХрд┐ рджреЗрджреВрдВрд╡рд╛рд▓рд╛ рдЪрд▓рд┐рдП рд░реБрдХреЛ рдЬрдбрд╝рд╛ рдЗрд╕ рд╕рд╡рд╛рд▓ рдореЗрдВ рдЦреЗрд▓ рдХреНрдпрд╛ рдерд╛
01:08:09рдХреНрд▓рд┐рдпрд░ рд╣реИ рд╣рд░ рд╕рд╡рд╛рд▓ рдореЗрдВ рдХрд╛рдо рдПрдХ рд╣реА рдХрд░ рд░рд╣реЗ рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ solution рдХреЛ рдкрд╣ рд╣реИ
01:08:12reaction рд╣реЛрддреА рд╣реИ рддреЛ reaction рдЗрд╕реА рддрд░реНрдЬ рдкрд░ рдЕрдЧрд▓рд╛ рд╕рд╡рд╛рд▓ рд▓рд┐рдЦ рд▓рд┐рдП рдкрд╣рд▓реЗ рд╕реЗ
01:08:17рд╣рд╛рдВ рдХрд┐ рдЖрдк рдмрд╛рдд рдХрд░реЗрдВ рдмрд╣реБрдд рдЯрд╛рдЗрдо рд╣реИ рдореИрдВ рд╕рдордЭрд╛ рд░рд╣рд╛ рд╣реВрдВ рдПрдХ рдПрдХ рд╕реНрдЯреЗрдк рдЗрд╕рд▓рд┐рдП рдЖрдк рдХрд░реЗрдВрдЧреЗ рддреЛ
01:08:27рдЖрдк рдЖрдзреЗ рдХрд░реЗрдВрдЧреЗ рдлреЙрд░реНрдорд▓рд╛ рд▓рдЧрд╛ рд▓рд┐рдпрд╛ рдкреА рдХреЗ рднреА рд╣рд╡рд╛ рдореЗрдВ рдХрд░ рд▓рд┐рдпрд╛ рд╕реА рдХреЛ рд╕реЙрд▓ рдХреНрдпрд╛ рдЗрддрдирд╛ рддреЛ рдиреАрда рдбреЙрдХреНрдЯрд░ рдмрдирдиреЗ рд╡рд╛рд▓реЗ
01:08:34рдХрд┐рддрдиреА рдХреЗ Pizza рдХрд┐ рдпрд╣ рднреА рдирд╣реАрдВ рдХрд░ рд╕рдХрддреЗ рд╣реИ рд╣рд╛рд╣ рдХрд░ рд▓рд┐рдХ рд╣реЛ рдЬрд░рд╛ рдЕрдЧрд▓рд╛ рд╕рд╡рд╛рд▓ рд╣реИ рд▓рд┐рдЦреЛ рдХрд┐
01:08:43Calculate the pH of, calculate the pH of, 10k power minus 2 molar, calculate the pH of, 10k power minus 2 molar, formic acid solution mixed with 10k power minus 3 molar, HCO hole twice, barium, barium formate, mixed with 10k power minus 3 molar,
01:09:12HCO hole twice, barium, рд╣╫ЬрдХрд┐ рдРрд╕рд╛ рд╕рд╡рд╛рд▓, already рдореИрдВрдиреЗ salt рдореЗрдВ рдЖрдкрдХреЛ рдХрд░рд╛ рджрд┐рдпрд╛ рд╣реИ, рддреЛ рдЬреЛ рд╕рддрд░реНрдХ рд╣реИрдВ, рд╡реЛ рддреЛ рдХрд░реЗ рд▓реЗрдВрдЧреЗ, historical error, 10k power minus 3 molar, HCO hole twice, barium, if, Olase, barium, if, if, kb of formate ion is 10k power minus 10, if kb of format ion is 10k power minus 10,
01:09:37formate ion
01:09:38we have KB
01:09:39and we have a solution
01:09:41and we have a question
01:09:42pH
01:09:43the target
01:09:48says that
01:09:49we are acidic
01:09:50and we are
01:09:50starting
01:10:00total
01:10:024
01:10:024
01:10:03which you have
01:10:03you are
01:10:03in this
01:10:04question
01:10:04if you are
01:10:08first
01:10:09first
01:10:10is
01:10:11now
01:10:12what is
01:10:14what?
01:10:15what gets
01:10:16mentioned
01:10:16I am
01:10:17going to
01:10:18ask
01:10:18the reaction
01:10:18or not
01:10:19the reaction
01:10:21does this
01:10:24it is
01:10:24the
01:10:24question
01:10:24now
01:10:26tell
01:10:26this
01:10:26who is
01:10:28this
01:10:28is
01:10:28this
01:10:29single
01:10:29acid
01:10:30single
01:10:30base
01:10:31like
01:10:32solution
01:10:32is like a don't know I said a different solution a different way a bit of a week
01:10:40or the other way so we can solve the name of the concept of a buffer or put it or
01:10:46put it up and then it's hard to put it up and then it's not a buffer yeah yeah
01:10:50now I'm a buffer if you can see the buffer concept I can see the answer
01:10:57the question does you do?
01:11:05Yes sir, some answer was given.
01:11:12There is 3.3.
01:11:14The answer is given.
01:11:20рек рдШрдЪрд╛рди рдЧрдпрд╛ рдХрд┐ solution рдХреИрд╕рд╛ рд╣реИ buffer я┐╜ рдЕрдм рджреВрд╕рд░рд╛ рдХреНрдпрд╛ рд╕рд╡рд╛рд▓ рд╣рдорд╕реЗ pH рдкреВрдЫрд╛ рд╣реИ рддреЛ formular pH рдХрд╛ рд▓рдЧрд╛ рд▓реЛ,
01:11:37Now copy pH formula,
01:11:39formula,
01:11:40you can't write.
01:11:41pH is equal to pK,
01:11:43plus log concentration of conjugate iron upon weak acid.
01:11:49Now check.
01:11:51How many things are known?
01:11:52We don't know.
01:11:54Hello.
01:11:55How many things are known?
01:11:57And how many things are known?
01:11:58We don't know.
01:12:00So, the other thing,
01:12:01we don't know.
01:12:02How many of you can get KB?
01:12:04We don't know.
01:12:05That's so simple, right?
01:12:09So, I'll start with PKB.
01:12:12And PKB, how much will it be?
01:12:1310.
01:12:14Here, PK, how much will it be?
01:12:154.
01:12:16So, 14 minus 10, that is 4.
01:12:18Let's get 1.
01:12:19Now, all my work will be here.
01:12:21Tell me,
01:12:23conjugate iron and weak acid.
01:12:25Can I know the weak acid?
01:12:27Where are the efforts?
01:12:29Conjugate iron.
01:12:30Can I get here?
01:12:31Can I have Henderson equation salt?
01:12:34Nicho Jinko Jinko Henderson equation
01:12:36sna
01:13:04is 2 into 10 ki power minus 3, right?
01:13:06Sari values ko put karthay hain, solve karthay hain,
01:13:09to pk ka maan kitna aya? 4,
01:13:11aur yahaan liqtah hoon log,
01:13:132 into 10 ki power minus 3,
01:13:15aur weak acid kitna hai 10 ki power minus 2,
01:13:18kya aap isse solve karthay hain?
01:13:19Jab isse solve karthay hain,
01:13:21to aagla saap calculation me kiasse dhsega,
01:13:23suniye ga, 10 ki power minus 2 per gya,
01:13:25to 10 ki power 2,
01:13:26that comes out 2 into 10 ki power minus 1,
01:13:30rukho jara, kya aap b minus log ye laga dhu?
01:13:32Aap satark ho chukye hain,
01:13:34aapko pata hai,
01:13:34kahaan kahaan sawal galat hootay hain, right?
01:13:36Yeh aapke negative ko avoid karhe ga.
01:13:38Negative kyun hoota hai?
01:13:40Kaya bari ispere bhi dependent,
01:13:41aapne cheezo ko sikha kaise hai?
01:13:43Aagar bar bar un steps ko dhimang me rakhengue,
01:13:45jahaan galat hoota hai,
01:13:46aapki habit me hooga,
01:13:47to negative nahi hooga.
01:13:49Chalega?
01:13:49Aayya saab,
01:13:50isko solve karlo ge kya?
01:13:52To 2 into 10 ki power minus 1,
01:13:54mujhe proper log ka formula lagana padega.
01:13:56To log a plus log b, right?
01:14:0010 ki power minus 1,
01:14:01minus 1 log 2 ki value 0.3,
01:14:04to minus 1 0.3,
01:14:05minus 0.7,
01:14:07minus 0.7,
01:14:09to 4 minus 0.7 comes out 3.3.
01:14:12Is this clear?
01:14:14So the correct answer is 3.3.
01:14:16Sabhi bachche kar lhe.
01:14:17Step number 1,
01:14:18solution peh hai.
01:14:19Step number 2,
01:14:20PKB se PK nikaalou.
01:14:22Step number 3,
01:14:23C ki concentration.
01:14:24Step number 4,
01:14:25mtlap saap,
01:14:26log C mein galti.
01:14:28Chalega?
01:14:29Har step me sambhal ke chalenghe,
01:14:30toh antak sahih answer pehunchenghe.
01:14:32рдФрд░ рдпреЗ рдЗрд╕ profile рдХреЗ рдЕрдЪреНрдЫреЗ рд╕рд╡рд╛рд▓реЛрдВ рдореЗрдВ рд╣реИ,
01:14:35рдпреЗ рдорд╕ рд╕реЛрдЪрдирд╛,
01:14:35рдРрд╕рд╛ рд╕рд╡рд╛рд▓ рдЖрдП рдирд╣реАрдВ,
01:14:36рдореИрдВрдиреЗ J233 рдХрд╛,
01:14:38salt hydrolysis рдХрд╛,
01:14:38same profile рдХреЗ рд╕рд╡рд╛рд▓ рдЖрдкрдХреЛ рдХрд░рд╛рдпрд╛ рд╣реИ.
01:14:40рдФрд░ J233 рдореЗрдВ рд▓рдЧрднрдЧ рд▓рдЧрднрдЧ рдЬреЛ paper рдЕрдЪреНрдЫрд╛ рд╣реЛрддрд╛ рд╣реИ,
01:14:43рддреЛ рд╣рдорд╛рд░реА needs match рдХрд░ рдЬрд╛рддрд╛ рд╣реИ.
01:14:45Hello?
01:14:46рдЕрдЧрд░ рд╕рдордЭ рдкрд╛рдП рд╣реИрдВ,
01:14:47рддреЛ рдХреНрдпрд╛ рдореИрдВ рдЕрдЧрд▓рд╛ рд╕рд╡рд╛рд▓ рджреЗ рджреВ?
01:14:49рдПрдХ рдмрд╣рддрд░реАрди рд╕рд╡рд╛рд▓.
01:14:51рд╡реЛ рд╡рд╛рд▓рд╛ рджреЗ рджреВ рдХреНрдпрд╛?
01:14:52рд▓реЗрдЦреЛ рдлрд┐рд░ рдЖрдЬ рд╡реЛ рд╕рд╡рд╛рд▓ рдЖрдкрдХреЛ рджреЗ рджреЗрддрд╛ рд╣реВрдБ.
01:14:55рд▓рд┐рдЦрд┐рдП.
01:14:55рджреВрд░рд┐рдВрдЧ, рджреВрд░рд┐рдВрдЧ, рдЯрд╛рдЗрдЯреНрд░реЗрд╢рди, рдЖрдзреЗ рддреЛ рдЗрд╕реА рдореЗрдВ рдкрд░рд┐рд╢рд╛рди, рдХрдареАрди рд╣реЛрдЧрд╛ рдХреБрдЫ.
01:15:05рдЕрдЪреНрдЫрд╛, рдЕрдм рдореИрдВ рдпрд╣рд╛рдВ рд╕реЗ рджреЛ рдмрд╛рддреЗ рдХрд╣рдирд╛ рдЪрд╛рд╣ рд░рд╣рд╛ рд╣реВрдБ.
01:15:08рдПрдХ, рдпрд╣ рд╕рдмреНрдж рдХреНрдпрд╛ рд╣реИ?
01:15:10рдЗрд╕ рдЯреЙрдкрд┐рдХ рдХреА рдирд┐рд╡ рднреА рд░рдЦ рд░рд╣рд╛ рд╣реВрдБ.
01:15:11рдФрд░ рджреВрд╕рд░рд╛ рдЗрд╕ рд╕рдмреНрдж рд╕реЗ рдШрдмрд░рд╛рдиреА рдХреНрдпрд╛ рд╡рд╢реНрд░рдХреНрддрд╛ рдирд╣реАрдВ рд╣реИ.
01:15:14рдмрд╣реБрдд рд╕рд┐рдВрдкрд▓ рд╕реЗ рдХрд╣рд╛рдиреА рд╣реИ.
01:15:16рдЕрднреА рддрдХ рдЬреЛ рдЖрдкрдиреЗ рдкрдврд╝рд╛, рд╡рд╣реА рдкреВрд░реА рдХрд╣рд╛рдиреА рдЯрд╛рдЗрдЯреНрд░реЗрд╢рди рдореЗрдВ рд╕рдорд╛рд╣реА рдереЗ.
01:15:19рдХреИрд╕реЗ? рд▓рд┐рдЦрд┐рдПрдЧрд╛.
01:15:20During titration of acetic acid, 40% of acetic acid is neutralized.
01:15:3840% of acetic acid is neutralized by sufficient amount of potassium hydroxide рдХреЗ рд╣реБрдП рдЕрдЪреНрдЫ.
01:16:00рдЗрд╕рдХреЛ рдереЛрдбрд╝рд╛ рдлреАрд▓ рдХрд░ рд▓реЛ.
01:16:03Potassium hydroxide рдХреЗ рдмрд╛рд░реЗ рдореЗрдВ рдХреНрдпрд╛ рдмреЛрд▓рд╛ рд╣реИ?
01:16:06Sufficient amount.
01:16:07рддреЛ рд╡реЛ рдХрдо рд╣реИ рдХрд┐ рдЬрд╛рдбрд╝рд╛ рд╣реИ?
01:16:11Sufficient рдХрд╛ рдорддрд▓рдм рдХреНрдпрд╛ рд╣реЛрддрд╛ рд╣реИ?
01:16:13рдЬрд╛рдбрд╝рд╛ рдХреА рдХрдо?
01:16:15Sufficient рдХрд╛ рдорддрд▓рдм рдХрдо?
01:16:18рдмреЗрдбрд╝рд╛, рдЖрдкрдХреЗ рдХрд┐рддрдиреЗ рдирдордмрд░ рдЖ рд░рд╣реЗ?
01:16:20Sufficient рдорддрд▓рдм 200 рдЖ рд░рд╣реЗ.
01:16:21Sufficient рдХрд╛ рдорддрд▓рдм рдХреНрдпрд╛? рдХрдо рдХреА рдЬрд╛рдбрд╝рд╛?
01:16:24Sufficient рдХрд╛ рдорддрд▓рдм рдкрд░реНрдпрд╛рдкреНрдд.
01:16:26рдирд╛ рдЬрд╛рджрд╛ рдирд╛ рдХрдо.
01:16:28If it starts with one molar concentration of acetic acid,
01:16:57then calculate pH of solution.
01:17:04And in the bracket, we have the acetic acid that we have to do.
01:17:091.8 into 10-5.
01:17:17If you study this, you need to study this.
01:17:22When you give me a question in paper,
01:17:23then my motive will not be asked to make a question.
01:17:27So, when you ask a question,
01:17:29then try to make a question.
01:17:30Just a small concept of a concept,
01:17:32so that you will learn it.
01:17:33I am saying that you will get it,
01:17:35that you will not be able to study this paper,
01:17:37which you have to study,
01:17:39which the concept is strong,
01:17:40that you will make a question.
01:17:42Let's go.
01:17:44It will become an easy question.
01:17:47You have to make an illusion.
01:17:49You will make a concept.
01:17:50It will become an easy question.
01:17:54Step number one.
01:17:57How do you do those things up?
01:17:59What do you do?
01:17:59Acid base or no?
01:18:00Yes.
01:18:00-╤А motion ?
01:18:01Reaction or how do you turn will leave your reaction?
01:18:02Yes.
01:18:02╪иansцДЯшзЙ it happens.
01:18:03Following the reaction,
01:18:04slightly moreф╜Х?
01:18:05Acetic, acid and
01:18:06Acetic
01:18:07plus ├Йlasesniveh├б
01:18:09cooledasek ,
01:18:10strong baseцШпхХК,
01:18:11and this result will
01:18:13not be made a problem.
01:18:15Salt plusтАж
01:18:15Pants
01:18:16That will balance that.
01:18:17desire in reply is using
01:18:18so that if you keep adjusting,
01:18:19sometimes more intermediate than this error
01:18:19will not be needed to writeтАж
01:18:24It willc├нaishes up.
01:18:25Ambossate mr. relieving
01:18:29individually
01:18:31yeah
01:18:33yeah
01:18:36yeah
01:18:39yeah
01:18:42yeah
01:18:46yeah
01:18:53рдХрд┐ рдореИрдВрдиреЗ рдПрдиреЗ рд▓рд┐рдЦ рджрд┐рдпрд╛ рдХреНрдпрд╛ рдХреЗ рд╣реИ рд╕реЙрд░реА рд╕реЙрд░реА рдореИрдВрдиреЗ рдкреЛрдЯреЗрд╢рд┐рдпрдо рдмреЛрд▓рд╛ рдерд╛ рддреЛ рдЖрдЬ рдпрд╣рд╛рдВ рдкреЗ рд╣рдо рд╕рдм
01:19:02рдХреЗ рд╕рд╛рдордиреЗ рдЖ рдЪреБрдХрд╛ рд╣реИ рд╕реЙрд▓реНрдЯ рдФрд░ рд╕рд╛рде рдореЗрдВ рд╡реАрдХ рдЕрд╕рд░реНрдб рд╕реЛрд▓реВрд╢рди рдХрд╛ рдкрддрд╛ рд▓рдЧрд╛ рдпрд╣ рдХреИрд╕рд╛ рд╕реЙрд▓реВрд╢рди рд╣реИ
01:19:07рддреЛ рдХреНрдпрд╛ рдореИрдВ рдлреЙрд░реНрдореНрд▓рд╛ рдмрдлрд░ рдХрд╛ рд▓рдЧрд╛ рд▓реВрдБ рдПрдХ рд╡реАрдХ рдЕрд╕рд░реНрдб рд╣реИ рдпрд╣рд╕ рдЙрд╕рдХрд╛ рд╕реЙрд▓реНрдЯ рд╣реИ рдпрд╣рд╕ рдФрд░ рд╣рдо рдлреЙрд░реНрдорд▓рд╛ рд▓рдЧрд╛рддреЗ рд╣реИрдВ рдкреА рдПрдЪ рдХрд╛ рд░рд╛рдЗрдЯ рдЬрдм рд╣рдо рдкреА рдПрдЪ рдХрд╛ рдлреЙрд░реНрдорд▓рд╛ рд▓рдЧрд╛рддреЗ рд╣реИрдВ рддреЛ рдкреА рдПрд╕ рдЗрд╕реНрдХреЙрд▓ рдЯреВ рдкреА рдХреЗ
01:19:19plus log of
01:19:21concentration of conjugate iron
01:19:24upon weak acid
01:19:26eq bachcha ┌й█Бta ha concentration of ci
01:19:28bhai kyun galat yaad kar rho
01:19:30pura conjugate iron bolne me kya
01:19:32dhikkat hai
01:19:32jab suru se galat yaad karthay hain
01:19:34to shawal bhi aapke galat hootte hain
01:19:36yaa ap nahi sache pa rhoen
01:19:38рдФрд░ yahe karaan hai bachcha bara bara bara pardtah hai
01:19:40ek bar tabiat se pardlo na yaar
01:19:41ab batao ye ci boloo ga conjugate iron
01:19:45conjugate
01:19:45or niache kya likhar hai haom
01:19:47weak acid
01:19:49what should be the PK
01:19:59four point
01:20:00solve
01:20:01I mean
01:20:01I don't think
01:20:02I don't think
01:20:03I don't think
01:20:04I don't think
01:20:17sir
01:20:17рдкрд╣рд▓реА рдмрд╛рд░ рддреЛ рдЖрдкрдиреЗ concentration рдмреЛрд▓ рджрд┐рдпрд╛ рд╣реИ, рдФрд░ рдирд╣реАрдВ рдмреЛрд▓рд╛ рд╣реЛрддрд╛, рддреЛ рднреА buffer рдореЗрдВ mole рднреА рдЪрд▓реЗрдЧрд╛, millimole рднреА рдЪрд▓реЗрдЧрд╛, gram equivalent рднреА рдЪрд▓реЗрдЧрд╛, milligram equivalent рднреА рдЪрд▓реЗрдЧрд╛, acid рдореЗрдВ рдФрд░ base рдореЗрдВ рд╕реЛрдЪрдирд╛ рд╣реИ concentration рд╣реЛрдирд╛ рдЪрд╛рд╣рд┐рдП, рдпрд╣рд╛рдБ buffer рдореЗрдВ рдХреЛрдИ рджрд┐рдХреНрдХрдд рдирд╣реАрдВ рд╣реИ, рддреЛ link рджреЗрддрд╛ рд╣реВрдВ рдореЗрдВ, conjugate time рдХрд┐рддрдирд╛ рд╣реИ, 0.4, рдФрд░ рдпрд╣ рдХрд┐рддрдирд╛ рд╣реИ, 0.6, рдЪ
01:20:47рд╣реЛрдЪ рдЧрдпреЗ рдереЗ, рдЖрддреЛрдВ рдХрд┐ answer рдХрд┐ рдпрд╛рд░, рд╣рд╛рдпрд╛ рдирд╛, рдмрдврд╝рд┐рдпрд╛, рддреЛ pH is equal to 4.74, рдкреНрд▓рд╕, log 2 by 3, рддреЛ log 2 minus log 3, log 2 рдХреА value, log 2 рдХреА value, 0.3, log 3 рдХреА value, 0.48, рдЪрд▓реЗрдЧрд╛, рдЗрд╕рдХреЛ solve рд▓рд┐рдП рдЖрдВрд╕рд░ 4 рдкреЙрдЗрдВ, the correct answer, is clear, рдкрдХреНрдХрд╛, рдХрд╣рд╛рдиреА рдЖрдЧреЗ рдмрдврд╝рд╛рдКрдВ, рдЕрднреА рддрдХ рд╣рдордиреЗ рдХреНрдпрд╛ рдХреНрдпрд╛ рд╕реАрдЦрд╛, рд╕рдм рдХреЛ clear рд╣реИ,
01:21:17рдФрд░ рднреА рд╕рд╡рд╛рд▓ рдХрд░ рд╕рдХрддреЗ рд╣реИрдВ, рд▓реЗрдХрд┐рди рдЬрд┐рддрдиреЗ рд╕рд╡рд╛рд▓ рдХрд┐рдпреЗ рд╣реИрдВ, рд╕рдм рдореЗрдВ concept рдПрдХ рд╣реА рдерд╛, рд╕рдмрд╕реЗ рдкрд╣рд▓реЗ solution рдХреЛ рдкрд╣ рд╣реИ, рдФрд░ рдЬреЛ рдореИрдВрдиреЗ рдЖрдЬ рд╣реБрдВрдмрдЧ рджрд┐рдпрд╛, рдЖрдк рд╕реЗ request рдХрд░реВрдБ, рдЕрдк рд▓реАрдЬ рдЙрд╕реЗ рдХрд░рд┐рдПрдЧрд╛, рдареАрдХ рд╣реИ, рдкреНрдпрд╛рд░реЗ рдмрдЪреНрдЪреЛрдВ, рдЕрднреА рддрдХ ionic рдХрд╛ рдПрдХ рдмрд╣реБрдд рдмрдврд╝рд╛ рд╣рд┐рд╕реНрд╕рд╛ рдЦрддрдо рд╣реБрдЖ, рдЕрдм рдпрд╣
01:21:47рд╣реИрдВ рдХреБрдЫ рдЬрд┐рди рдореЗрдВ рд╕рдм рд▓реЛрдЧ рдкрдврд╝рд╛рдПрдВрдЧреЗ, рдЪрд▓реЗрдЧрд╛, рдЬреЛ titration topic рд╣реИ, рд╡реЛ рд╣реИ рдХреНрдпрд╛, that is the part of practical chemistry, that is the part of, рддреЛ рдРрд╕рд╛ рд╕рдордЭ рд▓реЛ, рдХрд┐ рдореИрдВ ionic рддреЛ рдкрдврд╝рд╛ рд╣реА рд░рд╣рд╛ рд╣реВрдВ, рд▓реЗрдХрд┐рди рдЬреЛ practical chemistry рдХрд╛ рд╣рд┐рд╕реНрд╕рд╛ рд╣реИ, рд╡реЛ рднреА рдпрд╣реАрдВ add рдХрд░ рд░рд╣рд╛ рд╣реВрдВ, рддреЛ рдЖрдк рдЕрд▓рдЧ рд╕реЗ рдпрд╣ рдордд рд╕реЛрдЪрдирд╛, рдХрд┐ рдЙрд╕рдХреА рдЕрд▓рдЧ рд╕реЗ class рд╣реЛрдЧреА, рдЪрд▓реЗрдЧрд╛,
01:22:17рдПрдХ-рдПрдХ рд╕рд╡рд╛рд▓ рд▓рдЧрд╛рдИрдП, 600 рд╕рд╡рд╛рд▓ рдХрд╛ target рдореЗрд░рд╛ рдирд╣реАрдВ рдЖрдкрдХрд╛ рд╣реЛрдирд╛ рдЪрд╛рд╣рд┐рдП, рдЕрдЪреНрдЫрд╛, рдЗрдирдХрд╛ рдЗрдирдХреЛ рдХрд░рдиреЗ рджреЛ, рдЖрдкрдХреЛ рдХрд░рдирд╛ рд╣реИ, рдЪрд▓реЗрдЧрд╛, рджреВрд╕рд░рд╛, paper рдореЗрдВ рдмрдврд╝рд┐рд╣рд╛рдВ рд╕рд╡рд╛рд▓ рдорд┐рд▓реЗрдВрдЧреЗ, рд╕рдорд▓ рдХрд░рдирд╛, negative рдордд рдХрд░рд╛рдирд╛, рдФрд░ discussion рдХрд▓ online, offline, рджреЛрдиреЛрдВ рд░рд╣реЗрдЧрд╛, that's all for today, thank you so much, offline doubt рдореЗрдВ рд░рд╣реЗрдВрдЧреЗ, online discussion рд░рд╣реЗрдЧрд╛, рдЪрд▓

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