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A block with a mass of 0.8 kilograms is connected to a 100 N/m spring on a smooth floor. One end of the spring is connected to a wall. The block is pulled to the right 5 centimeters and then released. What is the total energy of the system?

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Transcript
00:00Hi friends, education breeds trust. Trust breeds hope. Hope breeds peace.
00:11One end of a spring is connected to a block, while the other end is fixed to a wall.
00:17Both objects lie on a smooth floor.
00:22The spring is then pulled to the right and released.
00:24Now, we are asked to calculate the potential energy of the spring when the block reaches a certain point.
00:36Let's discuss it. Here is a spring block system.
00:42Initially, the system is in equilibrium. This means the spring has not experienced any change in length at all.
00:49We can draw a dotted line through the center of mass of the block to mark the equilibrium point.
00:59An external force pulls the block to the right, then releases it.
01:05Of course, the block will move left and right periodically.
01:11This is simple harmonic motion.
01:13The block will always move like this as long as there is no energy dissipation.
01:23How do we calculate the magnitude of the spring force?
01:27The potential energy of the spring is calculated from the spring.
01:31So we will not pay attention to the block at all.
01:36Let's say at some point the block reaches this point.
01:39This point is at a distance x measured from the equilibrium point.
01:46Then the potential energy of the spring is half k x squared.
01:51Because the potential energy of the spring is based on the length of the spring's displacement from its equilibrium condition.
02:00From the problem sheet, the value of the spring constant is 200 newtons per meter,
02:05and the spring's displacement is 0.03 meters.
02:09It seems this calculation is quite easy.
02:12The potential energy is about 0.09 joules.
02:17This is the magnitude of the spring's potential energy.
02:23Happy learning everyone!
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