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00:00:00foreign
00:00:14foreign
00:00:18photoelectric effect k elp2
00:00:20nikaal away
00:00:24x
00:00:26elp2
00:00:28E lp2 рдореЗрдВ рдПрдХ рд╕реЗ рд▓реЗрдХрд░ One to seven. Photo electric effects E lp2. One to seven рдореЗрдВ рдХреЛрдИ рдбрд╛рдЙрдЯ ?
00:00:451 to 15 рдореЗрдВ рдХреЛрдИ рдбрд╛рдЙрдЯ ?
00:00:5310th
00:00:5610th number
00:01:1310th number
00:01:15laser light DIY
00:01:165 milliwatt
00:01:195 milliwatt
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00:01:48I am going to get the incident energy of the incident energy of the photon, or H new, or H C by lambda.
00:01:57The question is P, and the number of photons per second is the combined question.
00:02:03The hand value is 5 into 10 to the power 24, P into lambda.
00:02:08How much is this value? 8 into 10 to the power 15.
00:02:125 into 10 to the power minus 24, P value is 5 milliwatts.
00:02:18Here is lambda.
00:02:20Here is lambda.
00:02:22Here is 21.
00:02:24Here is 10 to the power minus 6.
00:02:27Here is 8 upon 25.
00:02:30Here is 100 to the power minus 6.
00:02:33Here is this value.
00:02:36Now, this value is 4.
00:02:37Here is 32 into 10 to the power minus 8 meter, or 300 to the power minus 8.
00:02:43Now, this value is lambda.
00:02:47So, this value is lambda.
00:02:49So, the incident of photon energy is 12400 upon me, 32.
00:02:53So, here is how much value is this value?
00:02:56Awesome.
00:02:57He's 4.
00:02:59Okay, if that value is 120 it is ъ░Аъ▓й higher, that's 4.
00:03:01The value is to the power minus 6 of alpha is bigger.
00:03:03It does look like╤В╨╛╤А╨░ъ┤А.
00:03:05Otherwise, from 2 of working technique for 8, the power minus 4 dimin ╤Б╤В╨╛╤А velocity is 1 and 0.
00:03:08If that's how 4 of arbeiten is of 9 meter, then the power minus 3 percent is over 9,
00:03:09the power minus 7, the power chorus isiantly 0.
00:03:14Which is the power of 9 meter because of star wastewater vape sine.
00:03:15nowadays of the power charge is 100 scalar energy.
00:03:16This powerhalf is of 2 and a power HVL wafko One X.
00:03:18potential 2.1
00:03:2011 number
00:03:27рдореЗрдВ рджрд┐рдпрд╛ рд╣реБрдЖ рд╣реИ threshold frequency
00:03:29рдЬреЛ рд╣реИ metallic
00:03:30surface рдЬрд┐рд╕рдХреА energy рдЗрддрдиреА рд╣реИ
00:03:33рд╡реЛ metallic surface
00:03:34corresponding to energy of рдЗрддрдирд╛
00:03:36and stopping potential
00:03:38for a radiation incident
00:03:41рдЗрддрдирд╛, рдЕрдЪреНрдЫрд╛ stopping potential
00:03:43рдЖрдпрд╛ рд╣реИ
00:03:4311 number, stopping potential рд╣реИ
00:03:465 volt, рдЗрд╕рд╕реЗ рдХреНрдпрд╛ рдкрддрд╛ рдЪрд▓рд╛?
00:03:49рд╡рд╣ maximum kinetic energy
00:03:51electron рдХреА 5 electron volt
00:03:53рд░рд╣реА рд╣реЛрдЧреА
00:03:53рддреЛ рдЙрд╕рдиреЗ рдмреЛрд▓рд╛ рдХрд┐ incident radiation
00:03:57рдХрд┐рд╕ range рдореЗрдВ рд░рд╣рддреА рд╣реИ, ultraviolet,
00:03:59visible, infrared, рдпрд╣ рдЬреЛ рд╕рдм рджрд┐рдпрд╛ рд╣реБрдЖ рд╣реИ
00:04:01рдЗрд╕ рдореЗрдВ рд╕реЗ, рддреЛ рдпрд╛рд░
00:04:02question рдореЗрдВ рдХреНрдпрд╛ рджрд┐рдпрд╛ рд╣реБрдЖ рд╣реИ, рдзреНрдпрд╛рди рд╕реЗ рд╕реБрдиреЗ
00:04:05рдЕрдм wavelength рдЕрдЧрд░ рдкрддрд╛ рд╣реЛ
00:04:07рддреЛ рдпрд╣ рд╡рд╛рд▓рд╛ question рдХрд░ рд╕рдХрддреЗ рд╣реИрдВ
00:04:08рдпрд╣ рд╡рд╣ рд╣рдо рдмрдирд╛ рджреЗрддреЗ рд╣реИрдВ рдЕрднреА
00:04:10threshold frequency рдЬреЛ рджрд┐рдпреЗ рд╣реБрдИ рд╣реИ, рдЙрд╕рдХреЗ corresponding energy
00:04:136.2 рд╣реИ, рдпрд╛рд░ рдЗрд╕рдХрд╛ рдорддрд▓рдм рдХреНрдпрд╛ рд╣реИ?
00:04:17рдпрд╣ рд╡рд╛рд▓реА value рдХрд┐рддрдиреА рд╣реИ?
00:04:185
00:04:19рддреЛ 5 рдХреА value рдЖрдЧрдИ energy 6.2
00:04:21рдЕрд░реЗ рдпрд╛рд░ рдЗрди рджреЛрдиреЛрдВ рд╕реЗ
00:04:23рдХреНрдпрд╛ incident рдХреА 11.2 рдЖрдпрд╛ рд╣реЛрдЧрд╛?
00:04:26incident 11.2 рдЖрдпрд╛ рд╣реЛрдЧрд╛, рддреЛ рдпрд╛рд░
00:04:29lambda рдХреА value
00:04:3012,400 рдЕрдкреЛрди рдореЗрдВ energy
00:04:33рдЕрд░реЗ рдЗрд╕рдХреЛ рдЗрдзрд░ рд▓реЗ рдЬрд╛рддреЗ, рдЗрдзрд░ рд▓реЗ рдЬрд╛рддреЗ
00:04:36рддреЛ formula рдмрдиреА рдЬрд╛рддрд╛, рддреЛ рдпрд╣рд╛рдВ рд╕реЗ
00:04:38рдПрдВрдЧрд╕реНрдЯреЛрди рдореЗрдВ рд▓рдЧрдмрдЧ рдХрд┐рддрдирд╛ рдЖ рд░рд╣рд╛ рд╣реИ?
00:04:43рдЕрд░реЗ 12,400, рдЕрдЪреНрдЫрд╛, рдмрд╛рдЧреНрдпрд╛рд░рд╛ рдорд╛рди рд▓реЛ
00:04:46рддреЛ рд╣рдЬрд╛рд░ рд▓рдЧрдмрдЧ
00:04:48рдФрд░ 11 рд╣реЛрддрд╛ рд▓рдЧрдмрдЧ
00:04:521000
00:04:531000 рд╣реЛрддрд╛ рдпрд╛рд░реА рдХрд┐ 1000 рдХреЗ рдЖрд╕рдкрд╛рд╕
00:04:561000 рдХреЗ рдЖрд╕рдкрд╛рд╕
00:04:581000 рдПрдВрдЧрд╕реНрдЯреЛрди
00:04:59рдЕрдЪреНрдЫрд╛, рд╡рд┐рдЬрд┐рдмрд▓ рдХреЗ рдмрд╛рд░реЗ рдореЗрдВ рдмрд╛рдд рдХрд░рддреЗ рд╣реИрдВ
00:05:02рд╡рд┐рдЬрд┐рдмрд▓
00:05:03рд╡рд┐рдЬрд┐рдмрд▓ рдЬреЛ рд╣реИ, рд╡реЛ 400 рд╕реЗ
00:05:06рдпрд╛ рднреА 4000 рд╕реЗ
00:05:087000
00:05:09рдЕрдЪреНрдЫрд╛, рдЗрдзрд░ рдЬрд╛рдПрдВрдЧреЗ, рддреЛ
00:05:11ultraviolet, visible, infrared, micro radio
00:05:15рддреЛ infrared рдХрд╛ рддреЛ рдЗрд╕рд╕реЗ рднреА рдЬрд╝реНрдпрд╛рджрд╛ рдЖрдПрдЧрд╛
00:05:17рд▓реЗрдХрд┐рди рдпрд╣ рддреЛ рдХрдо рд╣реИ, рдпрд╛рдирд┐
00:05:19рдХреА infrared рдирд╣реАрдВ рд╣реЛрдЧрд╛
00:05:21visible рднреА рдирд╣реАрдВ рд╣реЛрдЧрд╛
00:05:23рдЕрдЪреНрдЫрд╛, рдЕрдм рдЖрдм рдЖрд░реЗ рдкрд╛рд╕ рдореЗрдВ рдСрдкреНрд╢рди рдореЗрдВ
00:05:25рджреЛ рдмрдЪреНрдЫреЗ рдореЗрдВ, ultraviolet рдФрд░ X-ray
00:05:27X-ray рдХреА value рдмрд╣реБрдд рдЫреЛрдЯреА рд╣реЛрддреА рд╣реИ
00:05:291.1 рд╕реЗ
00:05:31рд▓рдЧрдмрдЧ 10 рдпрд╛ 100
00:05:33angstron рдХреЗ рдмреАрдЪ рдореЗрдВ рд╣реЛрддрд╛ рд╣реИ
00:05:34рдпрд╣ X-ray рд╣реЛрддрд╛ рд╣реИ, рдЬрдм X-ray рдкрдврд╝реЗрдВрдЧреЗ
00:05:37рдЗрд╕ topic рдореЗрдВ рддрдмрд╛рдпрд╛рдПрдЧрд╛, рддреЛ рдЗрд╕рдХрд╛
00:05:38рдорддрд▓рдм рдпрд╣ ultraviolet рд╡рд╛рд▓ рд▓рд┐рдП
00:05:401.2.15 рддрдХ
00:05:45X рд╕реЗ рд▓реЗрдХрд░
00:05:4715 рдХреЗ рдмреАрдЪ рдореЗрдВ
00:05:4812, 10 рд╣реЛрдЧреЗ
00:05:5111 рд╣реЛрдЧреЗ, рдЕрдм 12 рднреА рдЖрдЧрдпрд╛
00:05:52100 angstron рд╕реЗ рд▓реЗрдХрд░
00:06:004000 рддрдХ
00:06:01рдХрд╣реАрдВ 100 рддрдХ
00:06:08soft рдФрд░ hardness рдХреЗ according рдХрднреА
00:06:10рдЗрд╕ рджрд╕реНрддрдХ рд╣реЛрддреА рдХрднреА 100 рддрдХ рд╣реЛрддреА рд╣реИ
00:06:1112 рдирдордмрд░ рджреЗрдЦреЗ, collector plate рдХрд╛
00:06:15potential emitter рдХреЗ respect рдореЗрдВ
00:06:182 volt рд░рдЦрд╛ рд╣реБрдЖ рд╣реИ
00:06:19рдпрд╛рдж рд╣реЛрддрд╛ рд╣реИ, рдпрд╣рд╛рдБ рдкрд░ рдпрд╣ collector plate рд╣реЛрддреА рдереА
00:06:22рдФрд░ рдпрд╣рд╛рдБ рдкрд░ рдпрд╣ emitter рд╣реЛрддреА рдереА
00:06:23рдФрд░ рдЗрд╕рдХрд╛ potential plus 2 рд░рдЦрд╛ рд╣реИ
00:06:26рдЗрд╕рдХреЗ respect рдореЗрдВ, рдпрд╛рдирд┐ рдХрд┐ рдмреИрдЯрд░реА
00:06:27рдпрд╣ 2 volt рдХреА рдЬреЛрдбрд╝реА рдереА
00:06:29plus рд╡рд╛рд▓рд╛, рдЗрд╕рдХрд╛ рдорддрд▓рдм рдпрд╣ рд╣реИ
00:06:32next рджреЗрдЦреЗ, light рдЬреЛ рд╣реИ
00:06:34рд╡реЛ рд╣рдордиреЗ emitter рдкрд░ рдбрд╛рд▓рд╛ рд╣реИ
00:06:36200 nanometer, 200 nanometer рдпрд╛рдирд┐ рдХрд┐
00:06:382000 рдПрдВрдХреНрд╕реЛрдВ рдФрд░ 2000 рдПрдВрдХреНрд╕реЛрдВ рдХреА рдбрд╛рд▓реА рд╣реИ
00:06:41рдпрд╛рдирд┐ рдХрд┐ energy рдХрд┐рддрдиреА рдЖрдПрдЧреА
00:06:4212,400 рдЕрдкрди
00:06:44200 nanometer рдирд╣реАрдВ, 2000 рдПрдВрдХреНрд╕реЛрдВ
00:06:46рдХрд┐рддрдирд╛ рд╣реИ, 6.2
00:06:496.2 рд╡рд╛рд▓рд╛рдЗрд╕ рдкрд░ рдбрд╛рд▓ рджрд┐рдпрд╛
00:06:50рдЗрд╕рдХреЗ рдмрд╛рдж рдореЗрдВ рдмреЛрд▓рд╛ рдЬрд╛ рд░рд╣рд╛ рд╣реИ
00:06:52рдХрд╣рд╛рдВ рдЧрдпрд╛
00:06:53work function 4.5 рд╣реИ
00:06:55рддреЛ maximum рдФрд░ minimum kyanating energy
00:06:58рдЬреЛ рдЖрдк рдЕрдиреЗ рд╡рд░реНрдмрд▓реА рднреА рдмрддрд╛рдпрд╛ рдереЗ
00:07:01рдЕрдЪреНрдЫрд╛ рдЕрдЧрд░ рдпрд╣ battery рдирд╣реАрдВ рд╣реЛрддреА
00:07:03рдпрд╣ рдЕрдЧрд░ рд╣реЛрддреА рд╣реА рдирд╣реАрдВ
00:07:05рддреЛ рдпрд╣ рдпрд╣рд╛рдБ рдкрд░ рдпрд╣ рдХрд┐рддрдирд╛ рдЖ рд░рд╣рд╛ рд╣реИ
00:07:076.2
00:07:09work function рдХрд┐рддрдирд╛ рд╣реИ
00:07:101.45
00:07:114.5
00:07:13рддреЛ difference рдХрд┐рддрдирд╛ рд╣реИ
00:07:141.5
00:07:15рддреЛ electron рдЬреЛ рд╣реИ рдЙрд╕рдХреА kyanating energy
00:07:180 рд╕реЗ 1.7 electron volt рддрдХ рд░рд╣рддреА
00:07:21difference рдХреЗ current
00:07:22рд▓реЗрдХрд┐рди рдЬреИрд╕реЗ рдпрд╣ рдЖрдпрд╛
00:07:24рддреЛ рдЗрд╕рдиреЗ рдХреНрдпрд╛ рдХрд┐рдпрд╛ рд╣реЛрдЧрд╛
00:07:25kyanating energy рдФрд░ рдмрдврд╝рд╛рдИ рд╣реЛрдЧреА
00:07:27рддреЛ рдпрд╣ рдЬреАрд░реЛ рд╡рд╛рд▓реЗ рдХреА 2 рд╕реЗ рдмрдврд╝рд╛рдИ рд╣реЛрдЧреА
00:07:29рдЖрдЪреНрдЫрд╛ рдХрд┐рддрдиреА electron volt рджреЗ рдЧрдИ рд╣реИ
00:07:312 electron volt рдХреНрдпреЛрдВрдХрд┐ рдмреИрдЯрд░реА рдХрд┐рддрдирд╛ рд╣реИ рдХрд┐
00:07:332 рдХреА
00:07:33рддреЛ рдЗрд╕рдиреЗ рджреЛрд░ рдмрдврд╝рд╛рдпрд╛ рд╣реЛрдЧрд╛ рддреЛ
00:07:35рдпрд╣ 2 electron volt рд╣реЛ рдЬрд╛рдПрдЧрд╛
00:07:36рджреЛрд░ рдмрдврд╝рд╛рдпрд╛ рд╣реЛрдЧрд╛ рддреЛ
00:07:383.7
00:07:39рддреЛ minimum 2 electron volt maximum 3.7
00:07:41рдпрд╣ рдмрддрд╛рдпрд╛ рдерд╛ рд╣рдордиреЗ
00:07:4220 рддрдХ
00:07:4619 рдирдордмрд░ рджреЗрдЦреЗ
00:07:5220 рддрдХ рдкреВрдЫ рд░рд╣рд╛ рд╣реВрдБ
00:07:53рджреЗрдЦ рд▓реЛ рдмрд╛рдХреА рдЬрд┐рд╕рдХреЛ рднреА рдЕрдЪреНрдЫрд╛ рд▓рдЧ рд░рд╣рд╛ рд╣реИ рдХрд┐
00:07:55рд╣рд╛рдБ рд╣рд╛рдБ рдпрд╣ рдкреВрдЫ рд▓реЗрддреЗ рд╣реИ
00:07:5690 рдирдордмрд░
00:07:59frequency рдФрд░ intensity of light source
00:08:02рджреЛрдиреЛрдВ рдбрдмрд▓ рдХрд┐рдпреЗ рд╣реИрдВ
00:08:04рдпрд╛рд░ рдпрд╣ рд╡реЛ рдЧреБрд╡рд╛рдиреЗ рд╡рд╛рд▓рд╛ рдХреНрдпреЛрд╢ рд╣реИ
00:08:05intensity рдХреА value
00:08:08NH new by A
00:08:10рдпрд╣ рднреА рдбрдмрд▓ рдХрд┐рдпрд╛ рд╣реИ рдФрд░ рдпрд╣ рднреА рдбрдмрд▓ рдХрд┐рдпрд╛ рд╣реИ
00:08:12рдпрд╛рдирд┐ рдХрд┐ рдпрд╣
00:08:13constant
00:08:14рдмрддрдм photons рдЬреЛ рдЧрд┐рд░ рд░рд╣реЗ рд╣реИрдВ рд╡реЛ fix рд╣реИ
00:08:17рддреЛ рдмреЛрд▓рд╛ рдЬрд╛ рд░рд╣рд╛ рд╣реИ рдЗрди рдореЗрдВ рд╕реЗ рдХреМрди рд╕рд╛
00:08:19statement
00:08:20saturation current remains the almost same
00:08:23рдФрд░ рдирдордмрд░ of photons
00:08:25change рдирд╣реАрдВ рд╣реЛ рд░рд╣реЗ рд╣реИрдВ
00:08:27рддреЛ number of electron рднреА change рдирд╣реАрдВ рд╣реЛрдВрдЧреЗ
00:08:29рдФрд░ number of electron рдЪреАрдЬ рдирд╣реАрдВ рд╣реЛрдВрдЧреЗ
00:08:31рддреЛ saturation current change рдирд╣реАрдВ рд╣реЛрдЧрд╛
00:08:33рд╕рд╣реА рд▓рдЧ рд░рд╣рд╛ рд╣реИ рд╣реИ
00:08:34maximum kinetic energy of photo electron
00:08:37is double
00:08:37рдЕрдЧрд░
00:08:40frequency double рдХрд░рддреЗ рд╣реИрдВ
00:08:43рддреЛ maximum kinetic energy double
00:08:45рд╕реЗ рдЬрд╝реНрдпрд╛рджрд╛
00:08:46рдпрд╣ рднреА рдЧрд▓рдд рд╣реИ
00:08:4724 рддрдХ
00:08:5627 рддрдХ total
00:09:0125
00:09:07рдЕрднреА
00:09:08рдереЛрдбрд╝рд╛ рд╕реЗ рдЕрднреА рдХреБрдЫ рднреА рдкреВрдЫ рд▓реЗ рдЙрдЯ рдкрдЯрд╛рдВрдЧ рджреБрд╡рд╕
00:09:12current рдФрд░ рдЕрдЪреНрдЫрд╛ рдлрд░реНрд╕ рд╡рд░реНрдб рд▓рд┐рдЦрд╛ рд╣реБрдЖ рд╣реИ
00:09:17point source
00:09:19point source рдореЗрдВ current рдХреЗ рдмрд╛рд░реЗ рдореЗрдВ рдмреЛрд▓ рд░рд╣рд╛ рд╣реИ рдХрд┐ current рдХреА value
00:09:24рд╕реЗ рдЬреЛ рдЖрдИ рд╣реИ рдЕрдЪреНрдЫрд╛ рдХрд░реНрд╡ рдореЗрдВ saturation current рд╣реИ рдпрд╛рдирд┐ рдХрд┐ maximum current рд╣реИ
00:09:31рдЕрдЪреНрдЫрд╛ рдХреНрдпрд╛ maximum current рдЬреЛ рд╣реЛрддрд╛ рд╣реИ saturation current рд╡реЛ intensity рдХреЗ рдкреНрд░рдкреЛрд░реНрд╢рди рд╣реЛрддрд╛ рд╣реИ
00:09:36рдФрд░ рдпрд╣ рдПрди рдПрдЪ рдирд┐рдпреВ рдЕрдкреЙрди рдореЗрдВ рдП рдпрд╣ frequency рдХрд╣реАрдВ рдЪреЗрдВрдЬ рдирд╣реАрдВ рдХрд░ рд░рд╣рд╛ рд╣реИ рдХреНрдпреЛрдВрдХрд┐ рдЙрд╕рдиреЗ source
00:09:41рдирд╣реАрдВ рдХрд┐рдпрд╛ рд╣реИ рддреЛ distance рдЕрдЪреНрдЫрд╛ рдХреНрдпрд╛ рдпрд╣ distance рдХреЗ point source рддреЛ рдЗрд╕ рдкрд░ рдкрд╛рд╡рд░ рд╡рди рдЗрд╕ рдкрд░ рдкрд╛рд╡рд░ рдЯреВ рдХреНрдпрд╛ рдЧреНрд░рд╛рдл рдмрдиреЗрдЧрд╛
00:09:50рд╣рд╛рдИ рдкрд░ рдмреЛрд▓рд╛ рд╡рди рд╡рди рд╣реЛрддрд╛ рд╣реИ рдЗрдиреНрд╡рд░реНрд╕ рдореЗрдВ рддреЛ рд░реЗрдХреНрдЯреЗрдВрдЧреБрд▓ рдФрд░ рдпрд╣ рд╣рд╛рдИ рдкрд░ рдмреЛрд▓рд╛ рдРрд╕рд╛ рдЧреНрд░рд╛рдл рдмрди рд░рд╣рд╛ рд╣реИ рдлреВрд░реНрдЯ
00:09:57рд▓рд╛рд╕реНрдЯ рд╡рд╛рд▓рд╛
00:10:00рдпреВрд╡реА рд░реЗрд╕ рджреА рд╣реБрдИ рд╣реИ рдореЗрдВрдЯрд░ рдкреНрд▓реЗрдЯ рдкрд░ рдЧрд┐рд░ рд░рд╣реА рд╣реИ рдХрд┐рд╕реА photocell рдХреЗ рдирд╡рд╛рд▓ рдерд╛ рдлреЛрддреЛ рдЖрдЬрд▓ рддреЛ рдкрд╛рд▓ рдРрд╕реЗ рд░рд╣реА рд╣реИ рдХрд┐ рдореЗрдВрдЯрд░ рд╣реБрдЯ рд░реЛрд▓рдд рд░рд┐рдХ рдкреНрд▓реЗрдХреНрдЯрд░ рд░реВрдЯ рд░рд╣ рд╕рдХрддреА рд╣реИ рд╕рдм рдлреЛрдиреНрд╕ рдЕ рдореЗрд▓ рдХрд░ рдмрдирд╛
00:10:14the stopping potential is found minus one the ratio of charge to the mass of electron
00:10:22itna yeh kya dhiya wa hai e or m ka ratio maximum speed photo electron ki puchhi jaha rahi hai
00:10:31maximum speed photo electron ki kaise nik laghi maximum kinetic energy
00:10:37a maximum kinetic energy kaise nik laghi stopping potential kitna hai one to kitna
00:10:43aega one evi hatam
00:10:46yahaan se wapas se dekho one stopping potential kitna dhiya one is it maximum kinetic energy
00:10:59hai jayegi one electron volt lakin kinetic energy speed pocha half mv maximum square one electron
00:11:06world yeh nikalna hai to v square ki value one e by m at two wither jayega or yeh
00:11:13kya yeh value dhi hui hai hai oh pyr root lena
00:11:15e lp2 khatm
00:11:20a model me kya dhiya tha
00:11:24xs2 me jobi question dhiya thai us me one to nine ke beech me
00:11:31seven
00:11:39seven
00:11:41ред ред ред ред ред ред
00:12:11ред ред ред ред ред
00:12:41ред ред ред ред ред
00:13:11ред ред ред ред
00:13:41ред ред ред ред ред
00:14:11Yes, that is what we want to tell. But how is this? How is this?
00:14:25How is the current?
00:14:28Threshold per?
00:14:39Yes, will it be?
00:14:41Yes, it will not be.
00:14:45I have not done this.
00:14:47It is in the graph.
00:14:49It will not be done, but it will not be done.
00:14:54The second option will not be done.
00:14:5917th
00:15:0617th
00:15:0717th
00:15:0917th
00:15:1417th
00:15:1917th
00:15:2817th
00:15:3018th
00:15:3418th
00:15:3618th
00:15:3817th
00:15:4317th
00:15:4518
00:15:4918
00:15:5018
00:15:5118
00:15:53when a photon of H-New
00:15:56When a photon of H new falls on an aluminum plate, work function E naught dya hoa hai, maximum kinetic energy K hai, maximum kinetic energy K jho hai hooghi, maximum kinetic energy K jho hai hooghi,
00:16:14Woh H new jho gira, uus mei se E naught minus kiya hoogha, agar frequency radiation ki double kare hooghi, to maximum kinetic energy kiteri hooghi,
00:16:23To yaar, yeh mahi na maan liya, maximum kinetic energy double hai, acha double kare hooghi, to yu 2H new, or a yu minus me 5, acha option mei dya hoa hai,
00:16:35kabhi kisime K or H new, to dho nohi options dhekne pade ghi hao, wiesse to mujhe pata hai, agar main work function ke form mei baat kero,
00:16:44To mujhe pata hai, is ki value, K2 ki value, jho hai, 2 times of initial K plus 5, E naught aya tha, humara, yaad hai,
00:16:53Us time pa, jab humare paas mei yeh aya tha, woh humne kya hata aya tha, H new, kya yeh kahin par hai, kya, 2K plus naihi hai,
00:17:01Iska matlab yeh wala tariqa naihi hai, is wala mei, humne kya kiya hai, H new ko hata aya, H new ko hata nai ke liye,
00:17:09H new ki value, h new ki value, yaha se kitnay haigi, K plus E naught,
00:17:14Toh, yaha rakh diya, K plus E naught, toh, pher yeh result aya, agar haam, E naught ko hata hai,
00:17:21Agar haam E naught ko hata te hai, E naught ki value, yaha se kitnay haigi, H new minus K,
00:17:30Toh, yaha par haamare paas mei, K2 ki value, 2H new minus, yaha jaya ega, H new minus ke,
00:17:39Toh, yaha minus or minus plus, yaha aya, agar, aur idhar se, plus H new,
00:17:45Toh, yaha se yeh bhi aaga, ab dheklo, yari, woh to depend karta hai na,
00:17:48Kyanki, doonoh chijay dhi hui hai, aur option mei doonoh hai,
00:17:51Toh, humne ek bar ek ko hata ke dekha, woh match naihi karao, jabki yeh bhi sahih hai,
00:17:54Lekin option mei naihi hai, toh, minus ke baad mei, E naught ko hata ke dekha,
00:17:57Toh, yaha option fourth wala, hum match kari hai, 27, tak, joh bhi dhiye thhe,
00:18:07Dekh ya, 25, number dhekhe, eek particle hai, jiska mass, eek mili gram hai,
00:18:16Nahi dhiya thai, haj ho gaya, 30, dhiya thai, 31, dhekhe, kuch hai gaya,
00:18:27Kis nai puchay hai, 31, 31, mei bola hai, sodium lamp nai, itnay photon per second, small end dhe dhyya,
00:18:34Kitnay photon per second ho nikal raha hai,
00:18:36Toh, wo did, aray yeh, wo thoda sa ee mba mei bhi aya gaya, yeh wala question ho, hum yaha par bhi kare saktay,
00:18:41Maan lijiya, hum aray paas mei, eek sodium lamp dhya hua hai, acha sodium lamp hai,
00:18:48Tube light toh hai nini, yani kaisa source hai, point source,
00:18:51Or point source se photon nikal raha hai, itnay, wo bhol raha hai, ki eek second mein,
00:18:57Eek centimeter square per, kitna, wo distance batau, jahaan par eek photon per second per centimeter square,
00:19:05Yeh kya bola jara hai, wake photon gir hai, per second per centimeter square,
00:19:12Yeh kya bola jara hai, yeh second into centimeter square, yeh kya hai, intensity,
00:19:27Yeh na, yeh photon, yani ki eech niyo gir hai, toh question ho, wo distance poochhi ja raha hai,
00:19:32Per second sa, yeh haan par yeh wali distance nikalne ke liye, yeh haan sa yeh distance,
00:19:37R distance, R distance, R distance per yeh, achaa is ka yaad ho, wav optics vay, point source ka wavefront,
00:19:43Spherical ho ta hai, toh wo distance batau, jahaan par it, na yeh wala part gir raha hai,
00:19:47kya sa nikalne ke, yeh intensity ki value, energy per unit area, per unit time, yeh hota hai,
00:19:57Acha, yeh ski value, humare paas mei area, yeh haan sa yeh ee ki value, yeh kita na jayega,
00:20:02acha 4 pi r square, aur yeh t, yeh haan sa r ki value, agar mein nikalna chao,
00:20:09yeh jayega e upon mei, 4 pi t, yeh second mein, achaa is ki value kaise nikal ho ga,
00:20:18energy, per unit area, per unit time, so energy sa energy kiya, yeh haan par area hai ga, time hai ga,
00:20:26yeh haan sa r square, phir uske baad mein root le lo, distance aje, em wave ke anndar,
00:20:31jaadha, acha sa zonjma hai ga yeh wala part, 35 tuk, 35 tuk,
00:20:3938 tuk, 38 tuk,
00:20:49yeh third mein bhi diya ta kya, third mein joh diya thay un mein se, third mein,
00:20:57third mein, third question dhekhen, access third mein, photon ka charge zero hota hai,
00:21:10aray saari em wave, gamma se lhekar radio tuk, saari em wave, neutral yani ki charge less hota hai,
00:21:20yari ki photon koye koji charge, nahi hota hai, saari hai, rest mass of photon is zero,
00:21:27yeh bhi saari hai, isma answer ee diya hooga, correct explanation maala,
00:21:34yeh na, ab yaar, yehaan par haamare paas, isma bulge rest mass zero hai, rest mass zero hai,
00:21:40aur charge zero hone ka kuch relation hai kiya,
00:21:52aur kuch explanation,
00:21:53aur kuch
00:22:06jab ispar koji potential nahi lag raha hai toh,
00:22:11hai potential the charge ko hai, potential do ka neti energy hai,
00:22:14I will repeat this question.
00:22:21The first line is written.
00:22:26The photon is not charged.
00:22:30The rest mass photon is 0.
00:22:33The second statement.
00:22:35The second statement.
00:22:45The photon is not charged.
00:22:47The rest mass is not charged.
00:23:03This is a correction, it doesn't happen, it doesn't work.
00:23:07This answer is second, because if you read the electro,
00:23:14when you read the electro, you read the motion,
00:23:18the mass varies, but the motion doesn't vary.
00:23:23So the rest mass, whether it's moving mass,
00:23:26the charge doesn't have to be related to the motion.
00:23:30If a sphere has two kilometers,
00:23:33then whether it's running or running,
00:23:36then if it's running or running,
00:23:38then if it's running or running,
00:23:40then the mass is different.
00:23:42Einstein's theory.
00:23:44This is the second answer.
00:23:48Fourth reason.
00:23:50Photoelectric effect in the electrons comes out from the inner orbit of an atom.
00:24:00Haan?
00:24:05Photoelectric effect in the photoelectrons comes out from the inner orbit of an atom.
00:24:12It's all right.
00:24:14Free electron of metal cannot absorb photon.
00:24:20What?
00:24:25Photoelectric effect in the inner orbit of more,
00:24:27all in the outer orbit of an atom will absorb it.
00:24:30What are the other planes from the outer orbit of an atom?
00:24:32So, what does that mean?
00:24:33The option for the other...
00:24:35Fifth.
00:24:36Fourth...
00:24:37Photons do not carry momentum.
00:24:40Momentum is the same.
00:24:41P, E, Y, C, H by lambda.
00:24:45Photon is a material particle.
00:24:50Photon is a material particle.
00:24:54If you understand, material particle means
00:24:57electron. Material. Mass.
00:25:01Proton. Alpha. Photon is a energy bundle.
00:25:06Photon is a energy bundle.
00:25:08If there is a energy bundle,
00:25:10like this photon is not a material.
00:25:12Photo is a energy.
00:25:13We have told that the hydrogen atom from 4 to 3rd orbit, if the electron has a transition from the third orbit,
00:25:21then the energy came from the form of photon.
00:25:25It is like light or ultraviolet or x ray.
00:25:28It is not energy.
00:25:29The energy is not material.
00:25:31The material means electronic material.
00:25:36This is a material because it is made from electron, but it is not made from photon.
00:25:41The electron is not made from atom, the energy is made from photon.
00:25:48The atom becomes a photon.
00:25:50Time to be forced.
00:25:52Is it forced to be forced?
00:26:00Yes, yes.
00:26:03Yes.
00:26:05I am
00:26:08I
00:26:10I
00:26:12I
00:26:14I
00:26:16I
00:26:18I
00:26:20I
00:26:22I
00:26:24I
00:26:26I
00:26:28I
00:26:30I
00:26:32I
00:26:34I
00:26:35I
00:26:37I
00:26:39I
00:26:41I
00:26:43I
00:26:45I
00:26:47I
00:26:50I
00:26:53I
00:26:54I
00:26:55of a particle the proton or alpha particle
00:26:58can't bend the power of a mass
00:27:01I am going to ask if I am going to ask
00:27:03what I am going to ask for times
00:27:05to tell us that is 4
00:27:07if you want to ask that charge to you
00:27:09said that question in K
00:27:12he was a mob of the
00:27:15part of a market is a
00:27:16wavelength card ratio cut the momentum
00:27:19same or so here will be value
00:27:21we know that lambda value is h by mv.
00:27:25Let's listen to this formula.
00:27:28This formula is 12.27, 0.286, 0.202, 0.101
00:27:36but it doesn't matter.
00:27:39The momentum is the same.
00:27:42This is the same.
00:27:44This is the same.
00:27:46Lambda is the same.
00:27:48This is the same.
00:27:53Second question.
00:27:55What is the same?
00:27:57V is the same.
00:27:59If it is the same,
00:28:01lambda value is the same.
00:28:03This is the same.
00:28:05V is the same.
00:28:07This is the same.
00:28:09This is the same.
00:28:11It is the same.
00:28:13Alpha.
00:28:15Alpha is the same.
00:28:17Here is the answer.
00:28:184 by 1.
00:28:20Third.
00:28:21We have the third question.
00:28:22Kinetic energy is the same.
00:28:24Now, we have to remove the deep wave length.
00:28:28Kinetic energy part.
00:28:30Use the same.
00:28:32Kinetic energy is the same.
00:28:34This question is the same.
00:28:36Two is the same.
00:28:37H is the same.
00:28:38The same.
00:28:39Kinetic energy is the same.
00:28:40same.
00:29:01potential same
00:29:02and accelerating potential same
00:29:04same
00:29:05we know
00:29:06this formula
00:29:07will be
00:29:08the same
00:29:09so kinetic energy
00:29:11Q into V
00:29:12now let's see
00:29:13what is the same
00:29:14H
00:29:15is the same
00:29:16H
00:29:17is the same
00:29:18two same
00:29:19and the equation
00:29:20accelerating potential
00:29:21is the same
00:29:22lambda value
00:29:23under root
00:29:24is the particle
00:29:25of mass
00:29:26and the charge
00:29:27of product
00:29:28is the inverse
00:29:29so first
00:29:30is the proton
00:29:31and after
00:29:32is the alpha
00:29:33so now
00:29:34the mass
00:29:35is the proton
00:29:36charge
00:29:37and the mass
00:29:38is the mass
00:29:39so alpha
00:29:40four times
00:29:41and this
00:29:42will go
00:29:43through
00:29:45two
00:29:59the
00:30:02the
00:30:03the
00:30:20the
00:30:21the
00:30:26Okay, next question.
00:30:42Okay, next question.
00:31:12Change from 1 angstrom to 0.5 angstrom.
00:31:32Then find out.
00:31:40Change in kinetic energy of electron.
00:31:43Change in kinetic energy.
00:32:07Lambda is given that how much change in kinetic energy?
00:32:13Value, percentage change, fractional change.
00:32:18Value, percentage change, fractional change.
00:32:28Fractional change is not asked.
00:32:31Like in lambda, how much change is?
00:32:350.5.
00:32:371 to 0.5.
00:32:392 to 0.5.
00:32:432 to 0.5.
00:32:453 to 0.5.
00:32:483 to 0.5.
00:32:503 to 0.5.
00:32:523 to 0.5.
00:32:543 to 0.5.
00:32:563 to 0.5.
00:32:583 to 0.5.
00:33:003 to 0.5.
00:33:023 to 0.5.
00:33:033 to 0.5.
00:33:053 to 0.5.
00:33:063 to 0.5.
00:33:073 to 0.5.
00:33:083 to 0.5.
00:33:24I don't know why I said I will have an electron and I'll go back to kinetic energy to H upon
00:33:29my underwood way to M kinetic energy huh is that a time lagging
00:33:36oh yeah our past my electron key like a knee in a underwood may if I'm 50 upon my accelerating
00:33:43potential are you the other starting my initially get right yeah the other one and strong to
00:33:51yeah say you only value are a bank of a yeah the accelerating potential get around 150
00:33:58there is fire card open to be there but the one fifty volt palera how go give one fifty
00:34:04rate at a bit of one eye over at a bank of piramidic initial kinetic energy 150 electron world
00:34:11initial head up second case may you are you only value point five oh yeah those while a case may
00:34:19have stop is accelerating potential camera over the planet square current the point to fight
00:34:27oh yeah or point to five years ago maripas miss parker neighbor one fifty upon me
00:34:31your value value the second max letting potential a day got chase so
00:34:38is that one by four there's a guy chase or a chase away at the final kinetic energy
00:34:43chase so electron world
00:34:47the palette needy abitri hoi to his up change
00:34:50How much is this? 450 electron volt. This is the chain. Can we remove the values of this chain?
00:35:07If it is 3 times of initial, then you can remove the initial.
00:35:153 times of date.
00:35:44How much is this?
00:35:46Let me read it.
00:35:51How much is this?
00:36:09Find out ratio of kinetic energy.
00:36:21Find out ratio of de Broglie wavelength of hydrogen and helium molecules.
00:36:43At 27 and 127 degrees Celsius.
00:36:50At 27 and 127 degrees Celsius temperature respectively.
00:36:55This is the mole gas molecule.
00:37:02This is the part of the gas molecule.
00:37:14How much is this?
00:37:23How much is this?
00:37:26How much is this?
00:37:30How much is this?
00:37:45How much is this?
00:37:49How much is this?
00:37:50How much is this?
00:37:52How much is this?
00:37:56How much is this?
00:37:57How much is this?
00:37:58How much is this?
00:37:59So, this is the volume
00:38:08KT. Thermal Neutron,
00:38:10maybe I think Thermal Neutron
00:38:11is a result of 25.6
00:38:14by root T.
00:38:16So here,
00:38:16this is a variable
00:38:17M or T.
00:38:19So here,
00:38:19Lambda under root
00:38:21M or T
00:38:22inverse
00:38:24So first,
00:38:25hydrogen,
00:38:26then helium.
00:38:28So here,
00:38:29here under root
00:38:30hydrogen,
00:38:31hydrogen,
00:38:311 mole
00:38:33molecular weight
00:38:36temperature
00:38:3627
00:38:37yianni ki 300
00:38:38helium ke liye 4
00:38:40ye
00:38:40400
00:38:41kitna ayega?
00:38:484 by root 6
00:38:50iya or bhi chiche hai
00:38:53ya haa se ye 2
00:38:56ya jaga root 8 by 3
00:38:58acha question
00:39:02mujhe or karanay te abhi
00:39:03lekin eek chiz yaad ai hai
00:39:04jo mahi har bar miss
00:39:06kar deta ho modern
00:39:07me.
00:39:07Eek question
00:39:08tuhae milayega
00:39:09joh
00:39:09sab ke sab
00:39:10garbada
00:39:10karee hai
00:39:11ar ka
00:39:12ascension reason
00:39:13karee
00:39:13abhi
00:39:13ikdam se
00:39:14yada
00:39:14hai
00:39:15karee hai
00:39:16Okay.
00:39:17Yeah.
00:39:18Okay.
00:39:19Okay.
00:39:21Okay.
00:39:22Okay.
00:39:24Okay.
00:39:25Okay.
00:39:26Okay.
00:39:27I have a good particle.
00:39:29Come momentum.
00:39:30Same.
00:39:31Hey.
00:39:32So deep.
00:39:33Well, and purchase a car.
00:39:35Okay.
00:39:36See, okay.
00:39:37Okay.
00:39:38Okay.
00:39:39So, I'm going to see.
00:39:40Okay.
00:39:41Okay.
00:39:42Okay.
00:39:43Okay.
00:39:44Okay.
00:39:45Okay.
00:39:46Okay.
00:39:47Okay.
00:39:48You can sue cloud.
00:39:50Lambda equals to H by P.
00:39:53P.
00:39:54I'm.
00:39:55Hey.
00:39:56Other particle cut.
00:39:57Lambda Same BienveniClwynn.
00:39:59body forwards elements M in momentum.
00:40:07Yeah.
00:40:08Okay.
00:40:11Then you produce a dollar.
00:40:13I said that you can think about it.
00:40:18If it's the same, it will be the same.
00:40:22But if it's the same, it will be the same.
00:40:26If it's the same, it will be the same.
00:40:31I mean, it's the same.
00:40:33The momentum of the value of both of them is fixed.
00:40:37The momentum of the value of the magnitude is fixed.
00:40:40The momentum of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the value of the
00:41:10of two particles, if momentum of two particles are same, then their Debrouille wavelength
00:41:28are always same, then their Debrouille wavelength are always same.
00:41:49If Debrouille wavelength of two particles are same, then magnitude of their momentum
00:42:14are always same, but their momentum may differ due to direction.
00:42:43Next question.
00:43:14If a stationary large particle suddenly
00:43:21explodes into two different particles.
00:43:22If a stationary large particle suddenly explodes into two different particles.
00:43:28A stationary large particle suddenly explodes into two different masses.
00:43:35Then find out.
00:43:36A stationary large particle suddenly explodes into two different masses.
00:43:42Then find out.
00:43:43A stationary large particle suddenly explodes into two different particles.
00:43:50Then find out.
00:43:51The ratio of Debrouille wavelength of these parts.
00:43:57Then find out ratio of Debrouille wavelength of these parts.
00:44:04Then find out ratio of Debrouille wavelength of these parts.
00:44:11Then find out ratio of Debrouille wavelength of these parts.
00:44:18The answer is a stationary object.
00:44:19The stationary object is a stationary object.
00:44:25If a stationary object is actually a constant, it is a stationary object.
00:44:26The stationary object is a stationary object.
00:44:28The stationary object is because it is a stationary object.
00:44:31So it is aхе╜хРГ part, then it is a momentum.
00:44:34It is a momentum.
00:44:36It is momentum.
00:44:37If I am why, I am why.
00:44:38Momentum рдХреНрдпреЛрдВ рд▓реЗ рд░рд╣рд╛ рд╣реВрдБ рдХреНрдпреЛрдВ рдХреЗ рд▓рд┐рдП momentum рдЪрд╛рд╣рд┐рдП рдЗрд╕рдХреЗ рдмрд╛рдж рдореЗрдВ explosion рд╣реЛ рд░рд╣рд╛ рд╣реИ рдЬрд╣рд╛рдВ рдкрд░ explosion рд▓рд┐рдЦрд╛ рд╣реБрдЖ рд╣реИ equation рдореЗрдВ рд╡рд╣рд╛рдВ рдкрд░ рдЙрд╕ рдкрд░ circle рдХрд░рдХреЗ рд░рдЦ рджреЛ рдЬрдм рднреА explosion рд╣реЛрддрд╛ рд╣реИ рддреЛ explosion internal force рдХреЗ рдХрд╛рд░рдг рд╣реЛрддрд╛ рд╣реИ рдФрд░ рдПрдХ рдЕрдВрджрд░ chemical energy рдЬреЛ рд╣реИ рд╡реЛ рдЙрд╕рдХреЛ explode рдХрд░рд╡рд╛рддреА рд╣реИ рдмрд╣рд╛рд░ рд╕реЗ explosion рдирд╣реАрдВ рд╣реЛрддрд╛ рд╣реИ
00:45:03internal рдХрд░рдгреЛрдВ рд╕реЗ рд╣реЛрддрд╛ рд╣реИ рддреЛ external force 0 рдФрд░ рд╢рд╛рдпрдж рдкрддрд╛ рд╣реЛ NLM рдореЗрдВ f equals to dp by dt рдЕрдЧрд░ рдпреЗ рд╡рд╛рд▓реА value 0 рд╣реЛрддреА рд╣реИ рддреЛ momentum conserve рддреЛ momentum constant рд░рд╣реЗрдЧрд╛
00:45:17рдорддрд▓рдм рдЬрдм рднреА explosion рдХреЗ question рдЖрдЬрд╛рдП collision рдХреЗ question рдЖрдЬрд╛рдП рдпреЗ conservation of linear momentum рдФрд░ collision chapter рдореЗрдВ рдЖрддрд╛ рд╣реИ рдЙрд╕ time рдкрд░ collision рдпрд╛ explosion рд╕реЗ just рдкрд╣рд▓реЗ рдФрд░ just рдмрд╛рдж рдореЗрдВ рдХрд╛ momentum same рд╣реЛрддрд╛ рд╣реИ
00:45:33рдЕрдм рдЪрд╛рд╣реЗ рдЗрд╕рдореЗрдВ рд╕реЗ рдПрдХ part рдЪрд╛рд╣реЗ рдмрдбрд╝рд╛ рд╣реЛ рдФрд░ рдПрдХ part рдЬреЛ рд╣реИ рд╡реЛ рдЫреЛрдЯрд╛ рд╣реЛ
00:45:39рдпрд╛рд░ рдЗрд╕рдХрд╛ final momentum рднреА total рдХреНрдпрд╛ рд╣реЛрдирд╛ рдЪрд╛рд╣реЗ рдерд╛ zero рдХреНрдпреЛрдВрдХрд┐ рдЬрдм explosion рд╣реЛ рд░рд╣рд╛ рд╣реИ рддреЛ
00:45:45external for zero рд╣реЛрдиреЗ рдХреЗ рдХрд░рдг momentum conserve рдкрд╣рд▓реЗ рдерд╛ zero рддреЛ рдмрд╛рдж рдореЗрдВ рднреА zero рдЕрд░реЗ рдмрд╛рдж рдореЗрдВ zero рдХреИрд╕реЗ рд░рд╣рд╛ рд╣реЛрдЧрд╛
00:45:53рдЕрд░реЗ рдкрд╣рд▓реЗ рдХрд╛ momentum рдФрд░ рджреВрд╕рд░реЗ рдХреЗ momentum рдХрд╛ sum рд╣реА рддреЛ zero рд╣реЛрдирд╛ рдЪрд╛рд╣реЗ рдерд╛ рдпрд╛рдирд┐ рдХрд┐ рдкрд╣рд▓реЗ рдХрд╛ momentum рдФрд░ рджреВрд╕рд░реЗ рдХрд╛ momentum
00:46:01рдПрдХ рджреВрд╕рд░реЗ рдХреЗ opposite рдореЗрдВ рдЗрдзрд╛рд░ рдЕрдЧрд░ рдХрд┐рд╕реА рдХрд╛ momentum 10 рд╣реИ рддреЛ рдЙрд╕рдХрд╛ minus 10 рд░рд╣рд╛ рд╣реЛрдЧрд╛ рд▓реЗрдХрд┐рди рд╣рдореЗрдВ
00:46:08рдЖрд░реЗрдХреНрд╢рди рд╕реЗ рдорддрд▓рдм рдирд╣реАрдВ рд╣реИ рд╣рдореЗрдВ рддреЛ рдХреНрдпрд╛ рдЪрд╛рд╣рд┐рдП рд▓реЗрдордбрд╛ рдХреА value h by p magnitude sum рдореЗрдВ same
00:46:15рддреЛ рдлрд┐рд░ рддреЛ рд▓реЗрдордбрд╛ рднреА same рддреЛ рдкрд╣рд▓реЗ рдФрд░ рджреВрд╕рд░реЗ рдХрд╛ рдЬрд┐рд╕рдХрд╛ ratio one rest to one рдЪрд╛рд╣реЗ рдПрдХ рдмрдбрд╛ рд╣реЛ рдФрд░ рдПрдХ рдЫреЛрдЯрд╛
00:46:23рдорд╛рд╕ рд╣реЛ рдХреЛрдИ рдлрд░рдХ рдирд╣реАрдВ рдкрдбрд╝рддрд╛ рдЬреЛ рдмрдбрд╝рд╛ рдорд╛рд╕ рд╣реЛрдЧрд╛ рдЙрд╕рдХреА рд╡реЗрд▓рд╕рд┐рдЯреА рдХрдо рдЖрдПрдЧреА рдЬреЛ рдЫреЛрдЯрд╛ рд╡рд╛рд▓рд╛ рдорд╛рд╕ рд╣реЛрдЧрд╛ рдЙрд╕рдХреА рд╡реЗрд▓рд╕рд┐рдЯреА рдЬреНрдпрд╛рдж рдЖрдПрдЧреА рддреЛ рдкрд╣рд▓реЗ рдЪреАрдЪ рдмреИрд╕рд┐рдХ рд╕реА
00:46:31explosion mechanics рдкрд░ рд╡реЗрд╕реНрдЯ
00:46:53mammal рдЭрд╛рд▓ рдЭрд╛рд▓
00:47:23and
00:47:29.
00:47:33Perhaps, if you go to the community, the community comes back to the community,
00:47:39the community comes back.
00:47:44For a second, the community is the work power energy,
00:47:48If the potential energy of a particle
00:48:14having total energy
00:48:24if potential energy of a particle
00:48:29having total energy 2E0
00:48:32is given as
00:48:44u equals to E0
00:48:46for
00:48:49x рдХреА value
00:48:52рдпрд╣рд╛рдВ рд╕реЗ рдпрд╣рд╛рдВ
00:48:56рдЬрдм x рдХреА value 0 рд╕реЗ 1 рдХреЗ рдмреАрдЪ рдореЗрдВ рд╣реЛ
00:48:59рддреЛ рдЙрд╕рдХреА potential energy рдХрд┐рддрдиреА рд╣реИ
00:49:00E0 рдФрд░ u рдХреА value 0 рд╣реИ
00:49:03рдХрдм?
00:49:04рдЬрдм x рдХреА value 1 рд╕реЗ рдЬрд╝реНрдпрд╛рджрд╛ рд╣реЛ
00:49:07if deep row a wavelength of this particle
00:49:25if deep row a wavelength of this particle
00:49:33is lambda 1 for
00:49:39lambda 1 for 0
00:49:46and lambda 1 for 0
00:49:46from 1 to 1
00:49:47from x to the value
00:49:48then
00:49:49lambda 1
00:49:53lambda 2 for
00:49:55x greater than 1
00:49:57then
00:49:59then
00:50:00this wave length of square
00:50:06ratio
00:50:07this is the question
00:50:09this is the question
00:50:25listen to the question
00:50:26Yeah, if I have a particle
00:50:31So, this is a deep wavelength
00:50:35The way to write the way
00:50:36H upon P
00:50:37H upon M
00:50:39H upon Underwood
00:50:422M
00:50:43K E
00:50:44H upon 2M
00:50:48QV
00:50:49Excelling potential
00:50:50Now, question of potential energy
00:50:54that
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01:13:17we
01:13:19have
01:13:21I
01:13:23like
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01:13:27like
01:13:29I
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01:13:33I
01:13:35like
01:13:37I
01:13:39like
01:13:41V 0
01:13:43Y
01:13:45E 0
01:13:46m
01:13:47by T
01:13:48this
01:13:49net
01:13:50velocity
01:13:51under
01:13:53V 0
01:13:54square
01:13:55plus
01:13:56E 0
01:13:57t
01:13:58by m
01:13:59square
01:14:00this
01:14:01is
01:14:02momentum
01:14:03t
01:14:04time
01:14:05this
01:14:06is
01:14:07value
01:14:08m
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01:14:10if
01:14:11m
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01:14:14under
01:14:15v
01:14:16not
01:14:17square
01:14:18e
01:14:19e
01:14:20not
01:14:21t
01:14:22m
01:14:23square
01:14:24lambda
01:14:25not
01:14:26v
01:14:27v
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01:14:30not
01:14:31common
01:14:32v
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01:14:36square
01:14:37common
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01:14:39v
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01:14:41upon
01:14:42m
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01:14:57square
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01:15:38m
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01:15:51m
01:15:52m
01:15:53m
01:15:54photoelectric,
01:15:56all of these
01:16:01these
01:16:03first and second
01:16:05enter
01:16:07this
01:16:08first
01:16:09first
01:16:10first
01:16:11first
01:16:12first
01:16:13first
01:16:15first
01:16:16second
01:16:17first
01:16:18first
01:16:19second
01:16:20first
01:16:21first
01:16:22next
01:16:23second
01:16:25uh
01:16:27electro
01:16:28dynamics
01:16:29I
01:16:31mean
01:16:32last
01:16:33year
01:16:34have
01:16:36given
01:16:37130
01:16:38question
01:16:39of
01:16:40current
01:16:42questions
01:16:43extra
01:16:44more and more.
01:16:51Can you tell us that students are not saying anything about this?
01:16:54The last time they stopped saying that this is what they are doing.
01:16:59They are not saying anything.
01:17:06They are not saying anything.
01:17:10in France, even in J-Mans, we don't have to do all of these things, but in J-Mans, we don't have to do all of these things.
01:17:24So, physics is easy to do this.
01:17:27This is what we will do in physical chemistry.
01:17:30There are two things that we don't have to do in bio-care, and bio-care students.
01:17:37It isn't.
01:18:02It doesn't happen to me, but in the physical level, it can be bad for me.
01:18:07In the unit, in the calculation, in the concept, there are many.
01:18:12There are physical and physics, which can be bad for me.
01:18:16Levels can be improved. Lending to be.
01:18:19This time, the level was improved. Lending to be with the level of physics.
01:18:23If there is a level of length, then it will increase in physics or physical chemistry.
01:18:29If you learn more, the level of physics will increase.
01:18:34The teacher tells me.
01:18:36I agree.
01:18:39I agree.
01:18:41I agree.
01:18:44When I agree, there is no level of physics.
01:18:47I agree.
01:18:49But I agree.
01:18:52I agree.
01:18:54foreign
01:19:01foreign
01:19:06foreign
01:19:15foreign
01:19:18foreign
01:19:23yes
01:19:25yes
01:19:27yes
01:19:29yes
01:19:31yes
01:19:33no
01:19:35next question
01:19:39yes
01:19:47yes
01:19:49a little little question at all well I make not look around for Calisco explain
01:19:58carrying a speculation carrying a bought famous question mistake if
01:20:02are not man if the bro a wavelength of electron
01:20:16moving with V speed
01:20:19is similar to
01:20:28wavelength of photon
01:20:39then
01:20:41kinetic energy of electron upon my energy of photon
01:20:53and
01:20:55its value V by 2C
01:21:00and
01:21:02we will prove this tomorrow
01:21:03we will do a lot of questions in my work
01:21:04to listen to my question
01:21:06I have written a lot of things
01:21:08and
01:21:10if you have a question
01:21:15that
01:21:16is
01:21:17This is the equivalent word used.
01:21:18Because if photon has a energy, then what will be deep-royd?
01:21:21The particle, which is the material?
01:21:22So it's energy.
01:21:23So it's just wavelength and electron particles.
01:21:27So deep-royd.
01:21:28The second thing is for electron-related energy and photon-related energy.
01:21:35Energy of photon-related energy is at sea by lambda.
01:21:40So this is the electron- kinetic energy of lambda.
01:21:44In the same way, I have not written the photon speed.
01:21:47Photon, light of photon, EM wave.
01:21:50What speed is going on?
01:21:52C.
01:21:53And what speed is going on in the question?
01:21:55V.
01:21:56This is V's value.
01:21:58Electron is not going on C.
01:22:00EM wave.
01:22:02C is going on in vacuum.
01:22:04Electron is going on 10 to the power of 5, 6.
01:22:06We will now prove this.
01:22:08We will have two questions.
01:22:10In the module,
01:22:13Exercise 1
01:22:1741
01:22:2941
01:22:3141
01:22:3241
01:22:3441
01:22:3541
01:22:36E.
01:22:41E.
01:22:42E.
01:22:43Apple 1
01:22:44E.
01:22:45E.
01:22:46E.
01:22:47E.
01:22:49Model 1
01:22:50я┐╜
01:22:53E.
01:22:54E.
01:22:55E.
01:22:56E,
01:22:57P.
01:22:58E.
01:22:59E.
01:23:00E.
01:23:01E.
01:23:02E.
01:23:02E.
01:23:03E.
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