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10th Class Exams 2025-FBISS-Q NO iv a b-SSC II-Complete solution
digilearnerspoint
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9 months ago
10th Class Exams 2025-FBISS-Q NO iv a b-SSC II-Complete solution
part a
4(22x+1)-9(2x)+1=0
part b
Resolve into Partial fraction:
2x-1 / (2x-1)/((x+2)^2 (x-3))
Category
📚
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00:00
foreign
00:02
foreign
00:06
foreign
00:10
assalamu alaykum dear students
00:12
this video
00:14
section b question number two
00:16
part four
00:18
part a
00:20
part a
00:22
computer is matematic mean by taking
00:24
a degree 25
00:26
this video is a table
00:28
so
00:30
you have to
00:32
determine
00:34
so
00:36
you have to
00:38
determine
00:40
so
00:42
this
00:44
is
00:46
a
00:48
a
00:50
a
00:52
a
00:54
0 to 10
00:56
10 to 20
00:58
20 to 30
01:00
30 to 40
01:02
40 to 50
01:04
now
01:06
we can have
01:08
20
01:10
4
01:12
5
01:14
9
01:16
6
01:17
15
01:18
15
01:19
17
01:20
17
01:21
17
01:22
17 plus 3
01:23
20
01:24
now we are going to take the midterm of the classes which labeled as x here
01:26
we get
01:28
preceding values of x by adding 10
01:30
15 plus 10 25
01:32
25 plus 10 35
01:34
35 plus 10 is equal to 45
01:36
now d is equal to x minus a
01:38
we are going to follow the section of the equation where a is equal to 25
01:42
so x minus a
01:44
5 minus 25 is equal to minus
01:46
20
01:48
15 minus 25 is equal to minus 10
01:50
25 minus 25 is equal to 0
01:52
35 minus 25 is equal to 10
01:54
35 minus 25 is equal to 10
01:56
45 minus 25 is equal to 20
01:58
so sum of definition from mean is always equal to 0
02:02
when you are going to add this d column
02:04
so sum will be equal to 0
02:06
now we are going to find fd
02:10
minus 16 minus 20
02:12
2 into raised power
02:14
2 into minus 10 is equal to minus 26
02:16
into 0 is 0
02:18
5 into 10 is 50
02:20
4 into 20 is equal to 80
02:22
then we have
02:24
summation fd is equal to 50
02:26
because
02:28
look at this
02:30
60 20 minus 80 plus 80
02:32
cancel each other
02:34
and remaining only figure is 50
02:36
now arithmetic means
02:38
which is in that method
02:40
x bar is equal to a
02:42
plus mission fd
02:43
12 by mission f
02:44
a is equal to 25
02:46
plus 50
02:47
12 by 20
02:48
0 is cancelled by 0
02:50
so we have
02:52
25 plus 2.5
02:54
xy is equal to 27.5
02:56
this is our answer
02:58
look at this
03:00
it is lies in the
03:02
same
03:04
point
03:06
to 30
03:07
now we will move to the
03:08
b part of the
03:10
question number 4
03:12
section b under question
03:14
2
03:16
so
03:18
find the distance between the
03:22
centers a and b if a is equal to 6 centimeter
03:26
c d is equal to 4 centimeter
03:28
c d is equal to 4 centimeter
03:30
b d is equal to 5 centimeter
03:32
here is the solution
03:34
so we have
03:36
drawn this diagram
03:40
not exactly as
03:44
not exactly as a given measurement
03:46
so a d is equal to 6 centimeter
03:48
d is equal to 6 centimeter
03:50
d is equal to 4 centimeter
03:52
d is equal to 4 centimeter
03:54
d b is equal to 5 centimeter
03:56
a d is 6 centimeter
03:58
d b 5 centimeter
04:00
c d is equal to 4 centimeter
04:02
a b this is the distance from
04:04
a to b
04:06
we have to be determined
04:08
in triangle a d c
04:10
a d c
04:12
a c
04:14
a c
04:16
a c is equal to 80
04:18
square minus c d whole
04:20
square
04:22
the first theorem
04:24
6k minus 4 square 36
04:26
minus 16
04:28
20 and a c is equal to plus
04:30
minus 200
04:32
under root 5
04:34
now in triangle c d b
04:36
c b scale is equal to
04:38
bt whole square minus c d whole square
04:40
4 centimeter whole square
04:42
minus 4 centimeter whole square
04:43
25 minus 6
04:44
25 minus 16
04:46
25 minus 16
04:48
which is equal to 9
04:50
so taking square root of both side
04:52
c b is equal to plus minus 3
04:54
so a b is equal to
04:56
a b plus c b
04:58
plus minus 2 underscore 5
05:00
plus minus 3
05:02
so
05:04
you will get this
05:06
value after solving this
05:08
under root 5
05:10
and then multiply by 2
05:12
and then we will once
05:14
add in minus values
05:16
then we will add in
05:18
plus values
05:20
i hope you will find this
05:22
solution useful if you have any question
05:24
and query query you can ask me
05:26
in the comment section
05:28
thanks for watching
05:30
assalamualaikum
05:32
that is
05:34
and
05:36
if
05:38
you
05:38
you
05:41
you
05:43
can
05:43
you
05:44
and
05:45
you
05:46
you
05:48
you
05:50
you
05:51
you
05:52
you
05:53
you
05:55
you
05:57
you
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