10th Class Maths Exam- SSC 2-Paper 2025 Final Solution-FBISE-Q 2 ii

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00:00what

00:04there are

00:07some

00:08lessons

00:09question no.2

00:10a

00:10and

00:11b

00:12and

00:13if you have

00:14question no.2

00:15part

00:17a

00:20customer

00:21Given sets verify that parentheses start P minus Q 4 prime is equal to P prime union

00:29Q. U stand here a union and but here as a name of set, universal set.

00:38P is also set 234.8 and Q is equal to 13579.

00:46P minus Q is equal to P prime union Q.

01:00So, let's start with the set.

01:05U is equal to 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.

01:09National number set is universal set.

01:11234.5.8.

01:14Let me change this set again.

01:16Okay.

01:23And Q is equal to 13579.

01:26Prove that parentheses P minus Q whole prime is equal to P prime union Q.

01:32P minus Q is equal to 23458 minus 13579 248.

01:38Now, P minus Q whole prime is equal to 13567 910.

01:48So, let's look at this.

01:49But first, what we have done, we take out all the elements of P which is not available in

01:57Q.

01:58In other words, we can say that we have subtract all elements of P minus Q from U and rest of

02:17the elements have been written in the new set name label P minus Q prime.

02:23Now, move to the further P bar or P prime is equal to 1234.

02:31567910 minus 23458 and it is basically U minus P.

02:50So, P minus Q prime is equal to P prime union Q proved.

03:20Now, come to the second part B of the question number 2.

03:33Let's read it first.

03:35Then, we will cover the solution.

03:38If W dot X is equal to Y dot Z then verify that 6 W minus 5 X divided by 6 W plus 5 X is

03:54equal to 6 W minus 6 W minus 6 W minus 6 W minus 6 W minus 6 W plus 5 X.

04:016 W minus 5 Z.

04:02So, if you will explain how that values cross B is to optimize the solution and get the solution

04:05you truthfully, so, we will write a rule out and ask the solution if you need to be trouver

04:10the solution.

04:116w minus 5x plus 6w plus 5x, 6w minus 5x minus 6w plus 5x.

04:246y minus 5z plus 6y plus 5z, 6y minus 5z minus 6y plus 5z.

04:34What is component or dependent theorem?

04:36So this theorem says that first we add the numerator in the numerator then in the next

04:45we subtract the same numerator from the area of the numerator but in the denominator section.

04:53So look at this 6w plus 6w is equal to 10w minus 5x plus 5x cancel each other.

05:026w minus 5x minus 6w is cancel each other and minus 5x minus 5x is equal to minus 10x.

05:1112y minus 10z, 10 is cancel by this, 10 is cancel by this, 12 is cancel by this, 12.

05:17So w.x is equal to y.z has proved.

05:24So here are the parts of our part 2.

05:36Assalamualaikum warahmatullahi wabarakatuh.

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