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A particle is moving in a circular motion and at any instant its motion equation is given by angular displacement =40 power 4 / 40 - 3 ki power 3 / 3 . the angular acceleration of particle after 10 seconds is
#jee main april 2026 question
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#jee main kinematics question
#jee main circular motion questions

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00:00So, in this question, we are given a particle is rotating in a circular motion and any intense motion can
00:06be described by this equation.
00:08Here, just theta is not angle but angular displacement.
00:12So, angular acceleration after 10 seconds is just.
00:16So, we know if we differentiate angular displacement with respect to time, then we will get angular velocity.
00:23And if we differentiate again with respect to time, we will get angular acceleration equation.
00:29So, first, do the first differentiation.
00:32Constant will come same to same with no change.
00:36So, 5 Tk power 4.
00:38Tk power 4 differentiation, 4 T cube.
00:40Here, 4 T cube.
00:42T cube differentiation, 3 T is required.
00:453 to 3 cancel, 5 into 4, 20.
00:4722 to the 40.
00:49So, 20 has to come.
00:52Now, T cube differentiation, 3 T is required.
00:54These two on denominator came same as this above.
00:59So, T is required differentiation, 2 T.
01:02So, 3 into T is square upon 2 minus 2 T.
01:05Angular acceleration at any second.
01:07We put the value of time 10 seconds.
01:1010.
01:11So, 10 into 10, 100.
01:13100 into 300 upon 150.
01:16Minus 2 into 10, 20.
01:18150 minus 20 is equal to 130.
01:20If in the option, the unit is also given.
01:24Then, the unit will come meter per second is required.
01:27Using the optimizer that might not be receive.
01:27Every option, the unit will be installed.
01:27the unit will be just up.
01:28In failing.

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