Static Electricity -04- Coulomb Force Vector

Rebiaz Studio

A particle with a charge of 2 μC is at coordinates (1, 6) cm, and a particle with a charge of 4 μC is at coordinates (4, 2) cm. What is the column force experienced by the particle with a charge of 4 μC? Coulomb's constant: k = 9x10⁹ N.m²/C²  Watch the video related to *STATIC ELECTRICITY* : https://dailymotion.com/playlist/x80pkv  By following this channel it is very useful for the development of this channel. The Dailymotion application is easy to install on any smartphone, and does not take up much memory space.

Transcript

00:00Hi friends, knowledge is limitless.

00:05Therefore, if you continue to learn, your world will become wider.

00:10Force is one of the vector quantities.

00:15In this series, we will learn to use vector analysis to calculate the Coulomb force.

00:22Because the coordinates of a particle are determined by two values, it is a point in a two-dimensional coordinate system.

00:30The first particle is at point one six.

00:35The second particle is at point four two.

00:39All values are still in centimeters.

00:44We are asked to get the force vector acting on the charged particle at point two.

00:51The charges of both particles have the same sign.

00:55Both particles will move away from each other.

01:02The column force is the central force.

01:05Simply draw a straight line connecting the mass points of the two particles.

01:11This is the force we want to calculate.

01:16We will calculate this force through vector analysis.

01:20First, draw a vector R1 from the center of coordinates to particle one.

01:27Draw a vector R2 from the center of coordinates to particle two.

01:33Now, vector R is the vector that connects point one to point two.

01:39This vector is in line with vector F21.

01:43It seems that the two vectors are in the same direction, so we don't need to add a negative sign to the force equation.

01:50Vector F21 is equal to KQ1Q2 vector R divided by the magnitude of vector R cubed.

01:58There is a quite useful tip.

02:01That in the calculation process, the charge value is always positive regardless of its sign.

02:07Because the direction of the vector is already known.

02:11Numerically, vector R1 is 0.01i hat plus 0.06j hat.

02:18In the calculation process, we use meters instead of centimeters.

02:23Vector R2 is 0.04i hat plus 0.02j hat.

02:32Vector R is vector R2 minus vector R1.

02:38Just substitute vector R1 and vector R2.

02:43From here, vector R is 0.03i hat minus 0.04j hat.

02:51The magnitude of vector R is the norm of vector R.

02:54R is equal to 0.05 meters.

03:00Now, we can see some values from the problem sheet.

03:07We can use a scientific calculator.

03:10You may get different results.

03:11Vector F21 is 17.28i hat minus 23.04j hat.

03:18The component of the force vector is positive on the x-axis and negative on the y-axis.

03:25This means that vector F21 is in quadrant 4 as estimated in the picture.

03:33Happy learning everyone!

03:37For four years to complete the scan of the x-axis.

03:42The x-axis dropper is110.

03:43The x-axis is at the sum of the x-axis.

03:49The x-axis is at the x-axis.

03:52The x-axis is at the x-axis.

Category

Transcript

Comments

Recommended