Question No. 2 & Question No. 10

Lesson#6
Question No. 2
Q2: Show that:
=.sin⁡/2 sin⁡/2 sec⁡/2=.sin⁡/2 sin⁡/2 sec⁡/2=.sin⁡/2 sin⁡/2 sec⁡/2
Question No. 10
Q10: Prove that:
=(.sin⁡〖/2〗 〖 sin〗⁡〖/2〗)/cos⁡〖/2〗 =(.sin⁡〖/2〗 sin⁡〖/2〗)/cos⁡〖/2〗 =(.sin⁡〖/2〗 sin⁡〖/2〗)/cos⁡〖/2〗
Now it is exactly Q#2, watch solution of Q#2.
Application of Trigonometry
Chapter No 12
Exercise No 12.8
Mathematics
part 1